Challenge

Week 6 Challenge

DESIGN OF BOX CULVERT FOR 12.00x5.50
1.0 Input Data
INPUT DATA :
No. of cells = 1
Clear Span = 12.00 m
Clear Height = 5.50 m
Width of Haunch = 0.15 m
Depth of Haunch = 0.15 m
No. of division of Bottom Slab = 13
Depth of Top Slab = 0.400
Depth of Bottom Slab = 0.450
Depth of External Vertical Wall = 0.400
Thickness of Wearing Coat = 0.05 m
Thickness of fill (on top slab) = 4.404 m
Safe bearing capacity = 23 t/m2
Allowable Settlement = 75 mm
Spring Constant = 3066.67 KN/m
Density of concrete = 25 KN/m3
Bulk Density of soil = 20 KN/m3
Density of submerged soil = 10 KN/m3
Density of Wearing Coat = 22 KN/m3
Density of fill = 20 KN/m3
Coefficient of earth pressure at rest = 0.5
Carriageway Width = 13 m
Crashbarrier = 0.5 m
Footpath = 2 m
Camber = 2.5 %
Maximum air shade temparature = 46.5 oC
Minimum air shade temparature = 8.6 oC
2.0 Design Parameter
Grade of Concrete = M30
Grade of steel ("m" for Mild Steel & "t" for HYSD) = t
Type of exposure Moderate
Minimum grade of concrete M 30
Clear Cover for earth face structural component = 75 mm
Clear Cover for inside face structural component = 40 mm
Clear Cover for foundation = 75 mm
Impact For Live Load = 1.25
Thickness of top slab = 400 mm
Thickness of bottom slab = 450 mm
Thickness of external vertical wall = 400 mm
Thickness of internal vertical wall = 0 mm
2.1 Dead Load
Self weight of the structure has been calculated directly in STAAD file by the comment "SELFWEIGHT -1".
2.2 Super Imposed Dead Load
(a) Wearing Coat 10.35
Thickness of wearing coat = 0.05 m
Load ( UDL ) due to WC on top slab = 0.05 x 22 = 1.1 kN/m width
(b) Earth fill on top slab
Thickness of earth fill = 4.40 m
Load (UDL) due to earth fill = 4.404 * 20 = 88.08 KN/m
(c) Parapet loading
Load ( UDL ) due to Parapet = 8.2875 KN/m
Total SID load on top slab = 96.3675 KN/m
2.3 Earth Pressure
Thickness of top slab = 0.400 m
Height of top haunch = 0.150 m
Clear height between top & bottom slab = 5.500 m
Height of bottom haunch = 0.150 m
Thickness of bottom slab = 0.450 m
Height from top Intensity of Earth pressure
(m) (KN/m2)
Bulk soil Submerged soil Water
4.654 4.654 0.5 * 20 * 4.654 = 46.54 0.00 0.00
0.200 4.854 0.5 * 20 * 4.854 = 48.54 0.00 0.00
0.150 5.004 0.5 * 20 * 5.004 = 50.04 0.00 0.00
0.155 5.159 0.5 * 20 * 5.159 = 51.59 0.00 0.00
2.445 7.604 0.5 * 20 * 7.604 = 76.04 12.23 24.45
2.445 10.049 0.5 * 20 * 10.049 = 100.49 12.23 24.45
0.155 10.204 0.5 * 20 * 10.204 = 102.04 0.77 1.55
0.150 10.354 0.5 * 20 * 10.354 = 103.54 0.75 1.5
0.225 10.579 0.5 * 20 * 10.579 = 105.79 1.13 2.25
2.4 Live Load Surcharge
Equivalent height = 1.2 m
Uniform Intensity of loading = 1.2 * 20 * 0.5 = 12.00 KN/m2
2.5 Braking Load
Carriageway Live Load = 700 KN
Dispersion width = 8.554 m
Braking Load = 0.2 * 700/8.554 = 0.00 KN
FILL ON STRUCTURE IS MORE THAN 1M HENCE BRACING FORCE DIRECTLY TRANSFERED FROM SOIL HENCE BRAKING FORCE IS IGNORED

3) LIVE LOADS DUE TO 70R TRACK LOADING
Max. Wheel Load = 35.00 t
Tyre Dimensions :
a) Along Traffic Direction : 4.57 m Distributed width = 6.670 m
b) Perpendicular to Traffic : 0.84 m Distributed width = 5.000 m
c) Spacing of Wheels : 2.90 m
Distribution along the span is contact area +2X(Fill Height)
Hence,
Width of Tyre after Distribution = 4.570 + 2 x ( 0.05 + 1 ) = 6.670m
6.670m
Distribution Perpendicular to span = beff =b1
where,
lo = Effective Span = 12.40 m
b1 = Breadth of concentrated area = tyre width + 2 x Fill height.
= 2.940m
Hence, beff = 2.940m For one wheel Impact = 1.11125
Hence the the dispersion in the perpendicular to the traffic = 5.000m
Thus for the axle, the total Distribution area is as shown in the shaded portion is
= 5.000 m x 6.670m for a load of
Total wheel Load = 70.000 t
Hence, equivalent unit area load = 2.332 t /m2
Hence, udl = 2.332 t /m2
Hence, Base udl = 2.332 t /m2

4) LIVE LOADS DUE TO 40T BOGIE LOADING - 20T AXLE LOAD
Max. Wheel Load = 5.00 t
Tyre Dimensions : Tyre width = 36 cm
a) Along Traffic Direction : 0.2634 m Tyre Pressure = 5.273 kg/cm2
b) Perpendicular to Traffic : 0.86 m
c) Spacing of Wheels perpendicular drn. : 2.79 m Crash Barrier (Typ)
CL of Deck
c) Spacing of Wheels longitudinal drn. : 1.22 m
Width of the Slab Panel : 13.00 m
Dispersion along Traffic direction = 0.263+ 2 X 1 = 3.583 m
where,
lo = Effective Span = 12.40 m
b1 = Breadth of concentrated area = tyre width + 2 x Fill ht.
= 2.960m
Hence, beff = 2.960m For one wheel Impact = 0
Hence the the dispersion in the perpendicular to the traffic = 4.890m
Thus for the axle, the total Distribution area is as shown in the shaded portion is
= 4.890 m x 3.583m for a load of
Total wheel Load = 40.000 t
Hence, equivalent unit area load = 0.000 t /m2
0.000 t
LIVE LOADS DUE TO CLASS A LOADING
Max. Wheel Load = 5.70 t
Tyre Dimensions :
a) Along Traffic Direction : 0.25 m
b) Perpendicular to Traffic : 0.50 m
c) Spacing of Wheels perpendicular drn. : 2.30 m
c) Spacing of Wheels longitudinal drn. : 1.20 m
Width of the Slab Panel : 13.00 m

Dispersion along Traffic direction = 0.250+ 2 X 1= 3.550 m
Distribution Perpendicular to span = beff = + b1
where,
lo = Effective Span = 12.40 m
b1 = Breadth of concentrated area = tyre width + 2 xFill ht.
= 2.600m
Hence, beff = 2.600m For one wheel Impact = 1.12
Hence the the dispersion in the perpendicular to the traffic = 4.000m
But the pannel width is restricted = 13.00 m
Thus for the axle, the total Distribution area is as shown in the shaded portion is
= 4.000 m x 3.550m for a load of
Total wheel Load = 22.800 t
Hence, equivalent unit area load = 1.802 t /m2
1.802 t

1.802t Loading on top

Temperature Rise Case

Parameters:
Grade of Concrete M = 30
Elasticity for Concrete Ei = 3.100E+07 KN / m2
Modified Elasticity for Concrete Ec =Ei 3.100E+07 KN / m3
Coefficient of Thermal Expansion a = 0

/ oC

Member Description h h1 h2 h3 T1 T2 T3
( m ) ( m ) ( m ) ( m ) oC oC oC
Top slab 0.4 0.120 0.120 0.120 17.80 4.00 2.10
Member Description CG of Section from TOP CG of Section from BOTTOM CG of TOP BLOCK from TOP CG of MID BLOCK from TOP CG of BOTTOM BLOCK from BOTTOM x1 x2 x3 M
m m m T - m
Top slab 0.2000 0.2000 0.0473 0.1600 0.0400 0.1527 0.0400 0.1600 0.00

TEMPERATURE FALL CASE:-

Member Description h h1 h2 h3 h4 T1 T2 T3 T4
( m ) ( m ) ( m ) ( m ) ( m ) oC oC oC oC
Top slab 0.400 0.080 0.100 0.100 0.080 10.60 0.70 0.80 6.60
Member Description CG of Section from TOP CG of Section from BOTTOM CG of TOP BLOCK from TOP CG of MID BLOCK from TOP CG of MID BLOCK from BOTTOM CG of BOTTOM BLOCK from BOTTOM x1 x2 x3 x4 M
m m m m KN - m
Top slab 0.200 0.200 0.028 0.113 0.113 0.030 0.172 0.087 0.087 0.170 0.00
6.0 Design of Box Structure(ULS-Basic Combonation)
Grade of Concrete = M 30
Grade of Steel = Fe 500
Stress in Concrete (Rare combination) = 14.4
Stress in Steel (Rare & QPC combination) = 400
Modular ratio = 6.45
Modular Ratio for Long term = 12.90
Stress in Concrete (QPC combination) = 10.8
Crack width (As per Table-12.1) = 0.3 mm
Min shear reinf. ratio (ρmin) = 0.00091
Design yield strength of shear reinforcement fywd = 0.8*fyk/γs = 348
modulus of elasticity of rienforcing of steel (Es) = 200000 MPa
modulus of elasticity of concrete (Ecm) = 31000 MPa
6.1Check for ULS as per IRC:112-2011: Main Reinforcement
Section Face Mdes (KN.m) Depth of NA (mm) MOR (KN.m) Doverall provd. (mm) Deff provd.
(mm)
Ast Req. (min) (mm2/m) Bar Mark Diameter Spacing Bar Mark Diameter Spacing Ast provd. (mm2/m) r
(% steel)
Status
(check for MOR)
Steel Min & Max Check
1 Top 54 48.0 173.4 400 354 460 w1 12 190 ts1 12 190 1190 0.34 OK OK
Bottom 31 22.8 86.3 360 468 - 0 200 ts2 12 200 565 0.16 OK OK
2 Top 0 24.0 89.2 400 354 460 ts1 12 190 - 0 200 595 0.17 OK OK
Bottom 101 40.6 148.2 354 460 ts2 12 190 ts8 10 190 1009 0.28 OK OK
3 Top 54 48.0 173.4 400 354 460 ts1 12 190 w1 12 190 1190 0.34 OK OK
Bottom 31 22.8 84.8 354 460 ts2 12 200 - 0 200 565 0.16 OK OK
4 Outside 83 48.0 155.3 400 319 415 w1 12 190 ts1 12 190 1190 0.37 OK OK
Inside 0 24.0 80.1 319 415 w2 12 190 w2' 0 190 595 0.19 OK OK
5 Outside 58 24.0 80.1 400 319 415 w1 12 190 - 0 200 595 0.19 OK OK
Inside 0 24.0 80.1 319 415 w2 12 190 w2' 0 190 595 0.19 OK OK
6 Outside 80 46.8 151.6 400 319 415 w1 12 190 bs1 12 200 1161 0.36 OK OK
Inside 0 24.0 80.1 319 415 w2 12 190 w2' 0 190 595 0.19 OK OK
7 Top 61 40.5 153.4 450 367 477 bs3 16 200 - 0 200 1005 0.27 OK OK
Bottom 54 46.8 176.9 369 480 w1 12 190 bs1 12 200 1161 0.32 OK OK
8 Top 127 48.0 181.2 450 369 480 bs3 12 190 bs6 12 190 1190 0.32 OK OK
Bottom 0 24.0 93.1 369 480 bs1 12 190 - 0 190 595 0.16 OK OK
9 Top 61 40.5 153.4 450 367 477 bs3 16 200 - 0 200 1005 0.27 OK OK
Bottom 54 46.8 176.9 369 480 bs1 12 200 w1 12 190 1161 0.32 OK OK
Distribution Steel
Section Face Doverall provd. (m) Deff provd. (m) Ast reqd. (mm2/m) Bar Mark Diameter Spacing Bar Mark Diameter Spacing Ast provd. (mm2/m) r
(% steel)
Status
1,2 & 3 Top 400 343 238 ts4 10 200 - 0 200 393 0.11 OK
Bottom 202 ts5 10 200 - 0 200 393 0.11 OK
4,5 & 6 Outside 400 308 238 w4 10 200 - 0 200 393 0.13 OK
Inside 238 w5 10 200 - 0 200 393 0.13 OK
7,8 & 9 Top 450 354 238 bs4 10 200 - 0 200 393 0.11 OK
Bottom 232 bs5 10 200 - 0 200 393 0.11 OK
Check for Shear as per IRC:112-2011: Main Reinforcement
Section Vdes
(KN)
Axial Comp. Force
(KN)
Shear resistance without shear reinforcement (VRd.c) Minimum shear resistance (νRd.c) Shear Resistance of concrete
(KN)
Status Dia
of bar
No of legs Spacing of bar Spacing Required Check for Spacing Max Long. Spacing ρmin provided Check (ρmin)< (ρmin)pro SF by shear reinf.
(V Rd.s)
VNS - VRd.c Status
1,2 & 3 166.4 93.4 160.6237 151.745 160.62 Provide Shear Rein. 12 4 200 851 OK 266 0.00226 OK 708.4 5.82 OK
4,5 & 6 65.8 255.8 170.8254 160.507 170.83 OK 0 2 200 0 Not OK 239 0.00000 Not OK 0.0 -105.00 OK
7,8 & 9 198.4 123.1 164.9478 158.479 164.95 Provide Shear Rein. 12 4 200 804 OK 277 0.00226 OK 796.997 33.40 OK

SLS-RARE COMBINATION:-

Tensile strength of concrete (fctm) 2.5 MPa
Clear Cover for earth face 75 mm
Clear Cover for inside face 40 mm
Clear Cover for foundation 75 mm
7.1 Check for SLS as per IRC:112-2011: Stress checking of Concrete and Steel
Main Reinforcement
Section Face Mdes (KN.m) Depth of NA (m) Doverall provd. (m) Deff provd. (m) Ast Prov. (mm2/m) Max. comp. stress in concrete Status Max. Tensile stress in steel Status
1 Top 38 65 400 354 1190 3.40 OK 97.49 OK
Bottom 22 48 360 565 2.68 OK 113.30 OK
2 Top 0 47 400 354 595 0.00 OK 0.00 OK
Bottom 72 60 354 1009 6.81 OK 214.23 OK
3 Top 38 65 400 354 1190 3.39 OK 97.24 OK
Bottom 22 47 354 565 2.76 OK 115.27 OK
4 Outside 60 61 400 319 1190 6.29 OK 170.43 OK
Inside 0 45 319 595 0.00 OK 0.00 OK
5 Outside 38 45 400 319 595 5.28 OK 208.76 OK
Inside 0 45 319 595 0.00 OK 0.00 OK
6 Outside 58 61 400 319 1161 6.24 OK 169.04 OK
Inside 0 45 319 595 0.00 OK 0.00 OK
7 Top 42 63 450 367 1005 3.89 OK 121.45 OK
Bottom 38 66 369 1161 3.21 OK 94.35 OK
8 Top 90 73 450 369 1190 8.20 OK 215.10 OK
Bottom 0 48 369 595 0.00 OK 0.00 OK
9 Top 42 63 450 367 1005 3.89 OK 121.45 OK
Bottom 38 66 369 1161 3.20 OK 94.05 OK
8.1 Check for SLS as per IRC:112-2011: Crack width checking
400
Main Reinforcement
Section Face Mdes (KN.m) Depth of NA (m) Doverall provd. (m) Deff provd. (m) Ast Prov. (mm2/m) Max. comp. stress in concrete Status Max. Tensile stress in steel Status Equivalent Diameter rr.eff (esm-ecm) Maximum crack spacing Sr,max Crack width Status
1 Top 32 65 400 354 1190 2.83 OK 81.17 OK 12 0.01066 0.00024 361.4 0.09 OK
Bottom 22 48 360 565 2.68 OK 113.30 OK 12 0.00565 0.00034 496.8 0.17 OK
2 Top 0 47 400 354 595 0.00 OK 0.00 OK 12 0.00518 0.00000 564.1 0.00 OK
Bottom 72 60 354 1009 6.81 OK 214.23 OK 11 0.00891 0.00064 347.7 0.22 OK
3 Top 32 65 400 354 1190 2.83 OK 81.17 OK 12 0.01066 0.00024 361.4 0.09 OK
Bottom 18 47 354 565 2.29 OK 95.68 OK 12 0.00492 0.00029 550.9 0.16 OK
4 Outside 52 61 400 319 1190 5.45 OK 147.75 OK 12 0.01055 0.00044 363.4 0.16 OK
Inside 0 45 319 595 0.00 OK 0.00 OK 12 0.00503 0.00000 541.8 0.00 OK
5 Outside 31 45 400 319 595 4.35 OK 172.12 OK 12 0.00503 0.00052 575.8 0.30 OK
Inside 0 45 319 595 0.00 OK 0.00 OK 12 0.00503 0.00000 541.8 0.00 OK
6 Outside 50 61 400 319 1161 5.35 OK 145.06 OK 12 0.01028 0.00044 368.4 0.16 OK
Inside 0 45 319 595 0.00 OK 0.00 OK 12 0.00503 0.00000 541.8 0.00 OK
7 Top 33 63 450 367 1005 3.08 OK 96.21 OK 16 0.00779 0.00029 485.2 0.14 OK
Bottom 28 66 369 1161 2.39 OK 70.12 OK 12 0.00908 0.00021 394.7 0.08 OK
8 Top 84 73 450 369 1190 7.65 OK 200.70 OK 12 0.00947 0.00060 351.4 0.21 OK
Bottom 0 48 369 595 0.00 OK 0.00 OK 12 0.00445 0.00000 628.8 0.00 OK
9 Top 33 63 450 367 1005 3.08 OK 96.21 OK 16 0.00779 0.00029 485.2 0.14 OK
Bottom 28 66 369 1161 2.39 OK 70.12 OK 12 0.00908 0.00021 394.7 0.08 OK

Check for Safe Bearing Capacity of Soil

Support No. DL+SIDL reaction
(KN)
Live load Reaction (KN)
1 13.053 0.735
2 22.822 1.284
3 23.132 1.301
4 26.583 1.495
5 39.785 2.236
6 53.05 2.981
7 53.025 2.979
8 53.05 2.981
9 39.785 2.236
10 26.583 1.495
11 23.132 1.301
12 22.822 1.284
13 13.053 0.735
SUM 409.9 23.0

MODEL CALCULATIONS:-

Model Calculation :
Maximum BM under Basic combination = 5.41 t-m (From analysis)
Maximum SF (VNS) = 16.64 t
Total Depth D (mm) = 400 mm
Effective Depth d (mm) 354 mm Deck slab Thk = 0 mm
Web Width bw (mm) 1000 mm
Width bf (mm) 1000 mm
Grade of Concrete Used = M30
Grade of steel Fe 500
Charactristic strength of concrete (fck) = 30 MPa Table no:6.5 (IRC:112-2011)
Charactristic strength of steel (fy) = 500 MPa Table no:18.1 (IRC:112-2011)
Tensile strength of concrete (fctm) = 2.5 MPa Table no:6.5 (IRC:112-2011)
Design yield strength of shear reinforcement fywd = 0.8*fyk/γs = 348 MPa Page 86 IRC-112-2011
Partial material safety factor for concrete (gm) = 1.5 Basic Page 49: (IRC:112-2011)
Partial material safety factor for Steel (gs) = 1.15 Basic Page 30: (IRC:112-2011)
Ultimate compressive strain in the concrete (єcu3) = 0.0035 Up to fck ≤ 60Mpa Table no:6.5 (IRC:112-2011)
modulus of elasticity of rienforcing of steel (Es) = 200000 MPa Clause 6.2.2 (IRC:112-2011)
modulus of elasticity of concrete (Ecm) = 31000 MPa Table no:6.5 (IRC:112-2011)
modular ratio αe (Es/Ecm) = 6.45 page-126 IRC-112-2011
Ultimate tensile strain in the steel (єs) = [{fy/(gs xEs)}+0.002] = 0.00417
Coefficient to consider the influence of the concret strength (a) = 0.67 Cube A2.10 Page : 244 (IRC:112-2011) Cube or
Factor (l ) = 0.8 0.8 Up to fck ≤ 60Mpa,Eq.A2-33 (IRC:112-2011); 0.8-((fck-60)/500) for 60<fck<110Mpa
Factor (h) = 1 1.0 Up to fck ≤ 60Mpa,Eq.A2-35 (IRC:112-2011); 1.0-((fck-60)/250) for 60<fck<110Mpa
fcd = (a*fck/gm) = 13.400 page-49 IRC-112-2011
Factor b = (l/2) = 0.400
Cover = 75 mm
Effective depth of member (d) = 354 mm
Limiting Neutral axis depth (x lim) = (d*ecu3)/(es+ecu3) = 161.46 mm
Calculation for check of Moment Of Resistance (MOR) Ultimate Limit State (ULS)
Force in compression = Force in Tension from Fig. A2-4 - rectangular Tensile Strength and IS 456: 2000 , Annexure-G
Fig- A2-4, page-243 IRC-112-2011
fy*As
= hfcd * lxu* b = Fav * xu*b
gs
fcd = a*fck/gm = 0.4467 fck
Fav = hfcd * l = 0.36 fck
fy/gs = = 0.87 fy
As = (0.36 fck/0.87 fy ) Xu * b
X = 0.87 fy * As / (0.36 fck * b )
Assume Provided reinforcement Ast = 1190 mm2
Ast min = 460 mm2 > 1190 OK
Ast max = 10000 mm2 < 1190 OK
Cl. 16.5.1.1 of IRC:112-2011
Neutral Axis Depth X (mm) = = 47.95 mm
Lie in flange = 0.87*fy*Ast/0.36*fck*bf
Neutral Axis Xlim (mm) = (d*ecu3)/(es+ecu3) = 161.46 mm
Neutral Axis Depth Xu (mm) = 47.95<161.46 = 47.95 mm
MOR : = 0.36 fck * Xu * bf * ( d -0.4 * Xu ) OR
0.87 fy * As * ( d -0.4 * Xu )
= 17.339 t.m
Check for MOR
MOR Mu lim (t.m) = 17.339 t.m > 5.41 OK
Calculation of Stresses in the reinforcement and concrete (SLS- Rare combination)
Maximum BM under Rare combination = 3.83 t.m (From analysis)
Neutral Axis Depth X (mm) = 47.95 mm
MOI of cracked section (mm4) = b*x^3/12+m*Ast*(d-x)^2
= 7.56E+08 mm4
Stress in concrete (Mpa) = M*x/Icr = 2.43 < 14.4 OK
Stress in Steel (Mpa) = m*M*(d-x)/Icr = 100.06 < 400 OK
Calculation of Stresses & Crack width (SLS- Quasi permanent combination)
Maximum BM under Rare combination = 3.19 t.m (From analysis)
Neutral Axis Depth X (mm) = 47.95 mm
MOI of cracked section (mm4) = b*x^3/12+m*Ast*(d-x)^2
= 7.56E+08 mm4
Stress in concrete (Mpa) = M*x/Icr = 2.02 < 10.8 OK
Stress in Steel (Mpa) = m*M*(d-x)/Icr = 83.31 < 400 OK
Equi.diameter фeq (mm) = (n1ф12+n2ф22)/(n1ф1+n2ф2) Eq. 12.9 of IRC:112-2011
= 20 mm
Spacing of Bonded Reinf. in tension zone (mm) <= 5*(C+ф/2) Cl. 12.3.4 (3) of IRC:112-2011
= 425 mm
rr.eff = As/Ac.eff = 0.010 Eq. 12.7 of IRC:112-2011
As = 1190 mm2
Ac eff = 115000 mm2
Max. crack spacing Srmax (mm) = 3.4c+0.17ф/ρp.eff Eq. 12.11 of IRC:112-2011
= 583.4 mm
(esm-ecm) = (ssc - kt fct.eff/rr.eff (1+aerr.eff))/Es >=0.6 ssc / Es
ssc = 83.31 Mpa Eq. 12.6 of IRC:112-2011
ae = 6.45
(esm-ecm) = 0.000250
Crack width Wk (mm) = Sr,max (esm-ecm) Eq. 12.5 of IRC:112-2011
= 0.146 mm < 0.30 OK
Table-12.1 of IRC:112-2011
Check for Shear- Ultimate Limit State (ULS)
Shear Force VEd (t) = 16.64 t
Max Shear Force Vmax (t) = 0.5bwdνfcd Eq. 10.5 of IRC:112-2011
= 3856.38 t > 16.64 OK
Where ν is a strength reduction factor = 0.6(1-fck/310)fck Eq. 10.6 of IRC:112-2011
= 16.26
Longitudinal force (NEd) (t) = 9.34 t
Shear resistance of section without shear reinf. (VRd.c) (t) = [0.12K(80ρ1.fck)0.33+0.15σcp]bw.d Vide 10.3.2 of IRC:112-2011
Where K = 1+ √200 <= 2 Where d is depth in mm
√d Eq. 10.2 of IRC:112-2011
νmin = 0.031K3/2fck1/2 Eq. 10.3 of IRC:112-2011
Comp. stress as CG due to Axial load (σcp) Mpa = NEd/Ac <= 0.2fcd
= 0.23 Mpa
ρ1 = Asl/bw.d <= 0.02
= 0.0034
VRd.c (t) = 16.06 t
Minimum shear resistance (VRd.c) (t) = (νmin+0.15σcp)bw.d Eq. 10.1 of IRC:112-2011
= 15.17 t
Shear resistance (VRd.c) (t) = max (16.06,15.17)
= 16.06
Check Shear Reinforcement Requirement = 16.06 t < 16.64 t
= Provide Shear Reinf.
If Shear reinforcement required then,
Net Design Shear force VNS (t) = 16.64 t
Comp. stress as CG due to Axial load (σcp) Mpa = 0.23 Mpa (NEd/Ac)
Shear Force by shear reinforcement (V Rd.s) = Aswzfywdcotθ/s Eq. 10.7 of IRC:112-2011
VNS = V Rd.max
= αcwbwzν1fcd/(cotθ+tanθ) Eq. 10.8 of IRC:112-2011
= αcwbwzν1fcd/(2/sin2θ)
σcp = 0.234 0.25 fcd = 3.35
αcw = 1.02 0.50 fcd = 6.70
1.0 Fcd = 13.401
Eq. 10.9 of IRC:112-2011
sin2θ = VNS/αcwbwzν1fcd/2
= 16.64435*10000/((1.01742463249011*1000*0.9*400*0.6*13.4)/"2
= 0.113
θ = 3.25
Cotθ = 17.64 <= 2.5 >= 1
= 2.50 vide cl.10.2.2.2 of IRC-112-2011
Dia of bar used as shear reinforcement = 8 mm
Nos of legs = 2 Nos
Spacing of bars (s) mm = 100 mm
Min shear reinf. ratio (ρmin) = 0.072√fck/fyk Eq. 10.20 OR 16.5 of IRC:112-2011
ρmin = 0.00091
ρmin provided = 0.00101 > 0.00091 OK
Shear Force by shear reinf.(V Rd.s) (t) = 31.486 t
VNS - VRd.c = 0.582 t
Check for Shear = 31.486 t > 0.582 t OK
Asw max (mm2) = 0.5*αcw bw s ν1 fcd/fywd Eq. 10.10 of IRC:112-2011
= 940.31 mm2
Check For Asw max > Asw pro = 940.31 mm2 < 100.53 mm2 OK
Max Long. Spacing (mm) = 266 mm Eq. 16.6 & 16.8 of IRC:112-2011
Check for Spacing = 266 mm > 100 mm OK
Surface Reinforcement Reqd (mm2) = 4862.00 mm2 Cl.16.5.4 of IRC:112-2011
Dia. of bars for surface reinf. (mm) = 12.00 mm
Spacing of bars ( mm) = 90.00 mm
Surface Reinforcement Provided (mm2) = 4940.15 mm2
Check for Surface Reinf. = 4940.15 mm2 < 4862.00 mm2 OK

RESULTS:-

I II III IV Axial Comp. Force(LL) Axial Comp. Force(ULS)
Node No LL (KN-m) ULS-Basic Comb. SLS-Rare Comb. SLS-Quasi Perm. Comb.
BM 'KN-M' SF 'KN' BM 'KN-M' SF 'KN' BM 'KN-M' SF 'KN' BM 'KN-M' SF 'KN' KN KN
At Face of wall outer sec 1 51 1.29 51.583 36.637 31.906 0.253 93.15
At End of haunch outer 51 1.29
D from support outer SF Sec 1 53 7.011 154.703 9.153 6.905 0.253 65.142
At center of top slab sec 2 54 5.758 93.071 66.48 66.48 0.253 57.382
At Face of wall inner sec 3 57 1.29 51.434 36.538 31.906 0.253 93.002
At End of haunch inner
D from support inner sec 3 55 7.011 154.703 9.054 6.905 0.253 65.29
At Face of wall sec 4 106 3.428 77.21 56.394 52.154 10.414 229.227
206 3.428 77.09 56.315 52.154 10.414 229.227
At End of haunch
D from support 104 0.253 58.396 42.35 39.717 10.414 233.471
204 0.253 58.396 42.3 39.717 10.414 233.471
At center of wall sec 5 103 3.08 47.15 28.848 28.848 10.414 237.282
203 3.08 47.15 28.848 28.848 10.414 237.282
At Face of wall sec 6 100 2.732 75.779 55.276 50.092 10.414 245.338
200 2.732 75.631 55.178 50.092 10.414 245.338
At End of haunch
D from support 102 0.253 65.271 38.803 37.45 10.414 241.094
202 0.253 65.123 38.734 37.45 10.414 241.094
At Face of wall sec10 2 0.476 53.174 37.003 28.138 0.253 90.978
At End of haunch
D from support 4 6.08 186.049 28.496 22.441 0.253 89.403
At center of bottom slab sec 11 5 4.01 72.363 49.744 44.612 0.253 89.403
6 5.917 108.438 76.751 74.39 0.253 89.403
7 6.553 118.272 84.289 84.289 0.253 65.271
8 5.917 108.258 76.63 74.39 0.253 57.511
9 4.01 72.182 49.624 44.612 0.253 57.511
At Face of wall sec 12 12 0.476 52.993 36.882 28.138 0.253 122.869
At End of haunch
D from support 10 7.451 186.048 28.375 22.441 0.253 57.511

STAAD PRO:-

LL due to 70R wheeled

LL due to Class A loading:-

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