Week 2 Challenge
Q1
1.1 How will you assign the Circular section to the column?
AIM,
To assign a circular section to the column.
INTRODUCTION,
- Columns are the vertical member in the structure that can be of varying sizes in dimension.
- The circular section of the column is provided on the upper floor of the building for the better load carrying and access purposes.
PROCEDURE,
- Create the model in the STAAD Pro that can be a column.
- Go to properties in that define parameters.
- Assign the circular shape of the column.
- The radius of the circular is given.

RESULT:
The circular section to the column is created.
1.2 How will you assign the Unit system to a .std model file?
To assign the unit system in the STAAD pro
- Go to the file menu and then the settings.
- Open the structural settings.
- Change the dimensions to the required units.

1.3.What are the parameters to be specified while using the “Bay Frame” option?
To create the parameter of the design by Bay frame,
- By clicking on structural wizard option.
- Click frame model and the bay frame.
- Enter the parameters like length, breadth, height and the bay frame along the length, breadth and height.

1.4 Name a few codal standards incorporated in STAAD Pro software.
In STAAD pro the Codal standard are incorporated for the steel, Concrete, Aluminum.
For steel the codal provision are ISO800, IS800:2007, IS800:2007, WSD, IS 801.
For the concrete the Codal provision are IS 456 and IS 13920 for the seismic Design.
1.5 How will you specify the design compressive strength for a RCC section?
- Go to the Design option.
- Click on the define parameter.
- IN the design Parameter the Fck Compressive strength of RCC section is Given as 25000KNm.

Q2
2.1 State the “Input” steps involved in RCC design.
STEPS involved in RCC design are
- GEOMETRY
- The Node location and the node spacing are given.
- PROPERTIES
- Specify the sectional properties of the section .
- MATERIALS
- Specify the properties of the materials.
- SPECIFICATION
- The specification are given.
- SUPPORT
- The end support are to be given.
- LOADING
- Need to provide the loading pattern and the loading combination.
- ANALYSIS
- Need to analyse the modal and all the input specification are given.
- DESIGN
- FInally the design are to be done.
2.2 Explain the difference between Fixed and Enforced support condition in STAADPro.
- In STAAD Pro, support displacement loads cannot be applied to such model went the fixed type of support is specified.
- For the ENFORCED but type, there is no provision to specify a spring constant.
- The only choices, which are built into the program, are Zero stiffness.
Q3
3.1 Explain the steps involved in analysis of a model using STAAD Pro sequentially.
The steps involved in analysis of a model are,
- Before Analysis the model the load pattern and load combination are to be provided to the model.
- Then go to analysis option.
- Define command.
- Select the data for the analysis of the model by perform analysis, delta analysis, Nonlinear Analysis
- It depends upon the support conditions.
3.2 Explain the two ways in which a structural framework/model can be created in STAAD Pro software.
The two ways to model the structural framework is,
- Creating model by Node by Node.
- Creating model by Bay frame.


3.3 Elaborate the different support conditions in STAAD Pro.

3.4 How will you extract the stress distribution for a staircase slab?
- After completion of slab is done by Node placement.
- The creation of plate is used in stair case.
- By using generate mesh.
- The stress distribution for the staircase slab is done by viewing colour in slab of the design.
3.5 Explain the different ways to view SFD & BMD in STAAD Pro.
- After completion of the Design the STAAD Pro will automatically provide the BMD and SFD.
- By entering to the Post processing process click on OK.
- By clicking the beam results Deflection command.
- Reaction click the beam deflection.
PRACTICAL
1. Analyze the following structural elements and validate the results
A. Simply Supported Beam
a. A Simply supported beam with two point loads symmetrically placed
b. Span L = 20m
c. Load P = 50kN each
d. Both P located at 5m from each support
B.Fixed Beam
a. Span L = 16m
b. Uniformly Distributed Load w=9kN/m

















