Challenge

Understanding the concepts on Degrees of Freedom

AIM: Understanding the concepts on Degrees of Freedom

Questions:

  • Ln , Mn and Γn for each of the five modes are to be computed from Equations below.
  • Also, calculate the effective modal mass Mn* and the modal mass participating ratio for the 5 modes. The mass matrix will be required to evaluate these parameters.
  • Finally, obtain the base shear for each of the 5 modes of vibration and the combined base shear as per SRSS rule. The pseudo acceleration design spectrum to obtain the base shear for each mode is provided below.
  • How many modes are to be considered such that a modal mass participating ratio of 90% is obtained?

Answer:

Step 1: Calculation of Modified Mass Matrix (Mn):

Mn = ɸTn*m* ɸn

1. Mode 1

M1 = ɸT1*m* ɸ1

M1 = 3.861M

2. Mode 2

M2 = ɸT2*m* ɸ2

M2 = 3.861M

3. Mode 3

M3 = ɸT3*m* ɸ3

M3 = 3.861M

4. Mode 4

M4 = ɸT4*m* ɸ4

M4 = 3.861M

5. Mode 5

M5 = ɸT5*m* ɸ5

M5 = 3.861M

Step 2: Calculation of Modal Property (Ln):

Ln = ɸn*m*ɩ

1. Mode 1

L1 = ɸ1*m*ɩ

L1 = 4.121M

2. Mode 2

L2 = ɸ2*m*ɩ

L2 = -1.965M

3. Mode 3

L3 = ɸ3*m*ɩ

L3 = 5.086M

4. Mode 4

L4 = ɸ4*m*ɩ

L4 = 0.381M

5. Mode 5

L5 = ɸ5*m*ɩ

L5 = 0.175M

Step 3: Calculation of (Γn):

Γn = Ln/Mn

  • Γ1 = L1/M1 = 4.121M/ 3.861M = 1.067
  • Γ2 = L2/M2 = -1.965M/ 3.861M = -0.509
  • Γ3 = L3/M3 = 5.086M/ 3.861M = 1.317
  • Γ4 = L4/M4 = 0.381M/3.861M = 0.099
  • Γ5 = L5/M5 = 0.175M/ 3.861M =0.045

Step 4: Calculation of Effective Modal Mass (Mn*):

Mn* = Ln2/Mn

  • M1* = L12/M1 = (4.121M)2/ 3.861M = 4.39M
  • M2* = L22/M2 = (-1.965M)2/ 3.861M =0.98M
  • M3* = L32/M3 = (5.086M)2/ 3.861M = 6.70M
  • M4* = L42/M4 = (0.381M)2/3.861M = 0.04M
  • M5* = L52/M5 = (0.175M)2/ 3.861M = 0.01M

Step 5: Calculation of Modal Mass Participating ratio:

Mj = Total Mass = M+M+M+M+M = 5M

  • For Mode 1 = M1*/ Mj =0.88
  • For Mode 2 = M2*/ Mj =0.086
  • For Mode 3 = M3*/ Mj =0.024
  • For Mode 4 = M4*/ Mj =0.008
  • For Mode 5 = M5*/ Mj =0.002

Step 6: Calculation of Base Shear (Vbn):

Vbn = Mn*x An

T1 = 2 sec ; A1 = 0.27g

T2 = 0.6852 sec ; A2 = 0.76g

T3 = 0.4346 sec ; A3 = 1.03g

T4 = 0.3383 sec ; A4 = 1.03g

T5 = 0.2966 sec ; A5 = 0.76g

a. Mode 1

Vb1 = M1*x A1 = 4.40M * 0.27g = 1.188Mg

b. Mode 2

Vb2 = M2*x A2 = 1.00M * 0.77g = 0.77Mg

c. Mode 3

Vb3 = M3*x A3 = 6.70M * 1.03g = 6.901Mg

d. Mode 4

Vb4 = M4*x A4 = 0.04M * 1.03g = 0.041Mg

e. Mode 5

Vb5 = M5*x A5 = 0.01M * 0.77g = 0.77Mg

Step 7: Calculation of combined base shear as per SRSS Rule:

(Vb)2 = Vb12 + Vb22 + Vb32 + Vb42 + Vb52

Vb = 1.1882 + 0.772 + 6.9012 + 0.0412 + 0.772

Vb = 7.086

Step 8: Calculation of Total modes to be considered

The two modes are to be considered such that a modal mass participating ratio of 90% is obtained

M1*/ Mj + M2*/ Mj = 88% + 8.6% = 96.6%

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