Challenge

To calculate wind load for industrial steel structures and to apply it by using TSD

Q1

Aim:- to calculate the wind loading for the given data

  • calculate extenal pressure coefficients
  • calculate internal pressure coefficients
  • net pressure coefficients
  • design pressure for wall
  • wind loading to be applied on the wall panel

Given data:-

  • basic wind speed is 39m/s
  • terrain category is 2
  • probable design life of the building is 50years
  • greater horizontal dimension (length)= 24
  • lesser horizontal dimension (width)= 18
  • height of the building = 14

Ratio of wall and roof coefficeints:-

  • l/w =24/18= 1.33 (wall)
  • h/w = 14/18 = 0.78 (roof)

Wind pressure coefficients:-

  • risk coefficient K1 = 1
  • terrain factor and size factor K2 = 1
  • topography coefficient K3 = 1(for 50 years)
  • important factor for cyclonic K4 = 1.15

calculation of wind speed:-

  • design wind speed Vz= Vb x K1 x K2 x K3 x K4

Vz= 39 x 1 x 1 x 1 x 1.15= 44.85

  • design wind pressure Pz=0.6 Vz^2

Pz= 0.6 x 44.85^2 =1206.91 N/m^2

Pz =1.206 kN/m^2

Wall loading calculations:-

wind load along Y direction(face A)

+Cpi -Cpi

height at different level= upto 10m upto 10m

external pressure coefficient Cpe 0.7 0.7

internal pressure coefficient Cpi 0.5 -0.5

net pressure coefficient Cp 0.2 0.12

design wind pressure 1.207 1.207

wind load to be applied 0.241 1.448

factor x loading 0.253 1.52

wind load along Y direction(face B)

+Cpi -Cpi

height at different level= upto 10m upto 10m

external pressure coefficient Cpe -0.25 -0.25

internal pressure coefficient Cpi 0.5 -0.5

net pressure coefficient Cp -0.75 0.25

design wind pressure 1.207 1.207

wind load to be applied -0.905 0.302

factor x loading -0.95 0.32

wind load along Y direction(face C and D)

+Cpi -Cpi

height at different level= upto 10m upto 10m

external pressure coefficient Cpe -0.6 -0.6

internal pressure coefficient Cpi 0.5 -0.5

net pressure coefficient Cp -1.1 -0.1

design wind pressure 1.207 1.207

wind load to be applied -1.328 -0.12

factor x loading -1.4 -0.13

wind load along Y (-) direction

+Cpi (h/w =0.78) -Cpi (h/w =0.78)

external pressure coefficient Cpe -0.88 -0.4 -0.88 -0.4

internal pressure coefficient Cpi 0.5 0.5 -0.5 -0.5

net pressure coefficient Cp -1.38 -0.9 -0.38 0.1

design wind pressure 1.207 1.207 1.207 1.207

wind load along X direction(along EG)

+Cpi -Cpi

height at different level= upto 10m upto 10m

external pressure coefficient Cpe -0.76 -0.76

internal pressure coefficient Cpi 0.5 -0.5

net pressure coefficient Cp -1.26 -0.26

design wind pressure 1.207 1.207

wind load to be applied -1.52 -0.314

factor x loading -1.596 -0.33

wind load along X direction(along FH)

+Cpi -Cpi

height at different level= upto 10m upto 10m

external pressure coefficient Cpe 0 0

internal pressure coefficient Cpi 0.5 -0.5

net pressure coefficient Cp -0.5 0.5

design wind pressure 1.207 1.207

wind load to be applied -0.6 0.6

factor x loading -0.63 0.63

Result:- the wind loading to be applied on each face is calculated

Q2

Aim:- to assign the above calculated wind loading to the model

  • click on load>loadcases
  • add all the wind load combinations as per the direction of wind and coefficient of pressure

  • assign the loads to the model according to the standards of IS 875 part 3 as per the wind load values calculated above

RESULT:- all the wind loads calculated are assigned on the model as per the standards of IS 875 part 3

Q3

AIM:- to generate the wind loads using wind wizard from tekla structures

  • open the model
  • with all the member properties assigned
  • load cases and load combinations generated
  • with assignes wall panels, roof panels and slab panels
  • assign the floor finishes and live loads considered

  • now open the wind wizard
  • click on worst case data

  • click on next
  • edit the data as per the question
  • select the terrain as 2
  • basic wind speed as 39
  • category of the building as industrial building
  • add the properties of the building

RESULTS:- the results of wind pressures are obtained by the wind wizards

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