Challenge

To calculate the dead , live and wind load for RC residential structure and to apply them using TSD

  1. Calculate dead load in design report based on IS code and apply dead load on the model
  • Finishes of 50mm
  • Slab thickness as per the design
  • Brick wall load
  • Roofing load

AIM : To calculate dead load as per IS code and apply dead load on the model

INTRODUCTION:

Loads cases and load combinations are generated, assigned for the structure using tekla and validation of those loads is an important part of Tekla Structural Designer as it ensures a valid model for the analysis and design routines. Imposed Loads are assigned according to IS 875 Part 2

Dead Load calculation

Slab load : model slab in software

Finishes : 50mm x 24 KN/m^3 = 0.05 x 24 = 1.2 KN/m2

Brick wall width = 155mm

Unit weight = 20 KN/m^3

Floor height (Ground floor to First floor) = 5.2m

Brick wall loading for ground floor = 20 x (150/1000) x 5.2 = 15.6KN/m

Floor height (First floor to roof ) = 6.8 m

Brick wall loading for first floor = 20 x (150/1000) x 6.8 = 20.4KN/m

Roofing load based on purlin size :1.5KN/m^2

Ceiling loading 0f 0.3KN per sq m

PROCEDURE :

  • Generate load cases

  • Generate load combinations
  • Now click on Load combinations in load tab
  • Click on generate, we get initial paramters. Check and click on next

  • Select dead load at the bottom
  • Now select area load from panel load (Load tab)
  • Select area load = 1.2KN/m2 in ground floor and first floor and apply it
  • Ground floor :
  • First floor
  • Now to apply brick load to Groundfloor, Firstfloor
  • Select "Full udl" in load tab and apply brick load = 15.6 for groundfloor and First floor = 20.4KN/m
  • Groundfloor
  • First floor

RESULTS :

  1. Calculate live load in design report based on IS code and apply live load on the model

AIM : To calculate liveload as per IS code and apply live load on the model

INTRODUCTION :

Loads cases and load combinations are generated, assigned for the structure using tekla and validation of those loads is an important part of Tekla Structural Designer as it ensures a valid model for the analysis and design routines. Imposed Loads are assigned according to IS 875 Part 2

Work areas without machinery/equipments = 2.5KN/m^2

Work areas with machinery/equipments (Heavy) = 10KN/m^2

Staircase : 4KN/m^2

Toilets : 2KN/m^2

Canteen : 3KN/m^2

Store room : 2.4KN/m^2

Conference room : 4KN/m^2

Meeting room : 4KN/m^2

Office room : 4KN/m^2

Manager room : 4KN/m^2

Corridor : 4KN/m^2

Roof access not provided is taken as : 0.75KN/m2

PRODEDURE :

  • Now click on imposed loads at bottom
  • Select area load in the panel loads
  • Assign loads on the all floors according to the IS 875part 2
  • Ground floor
  • First Floor
  • Roof access not provided is taken as : 0.75KN/m2

RESULTS :

3. Generate manual wind loading in the design report based IS code as per the following input

  • Basic wind speed = 50m/s
  • Terrain category 2

AIM : To generate wind load based on IS code

INTRODUCTION : Wind load is calculated as pe IS 875 part III

Wind load calculation :

Wind speed taken as 50m/s

Terrain category is given as 2

Vb = Basic wind speed which is given as 50m/s

Normally basic wind speed is selected from appendix A of code book IS 875 III which is given based on wind speed in various cities

Design wind speed Vz= Vb*K1*K2*K3*K4

Where Vz depends on risk level, terrain roughness, height, size of structure, local topography

K1 = Probability factor

It is taken from table 1 of IS 875 III

Life of structure is taken as 50 yrs and wind speed is given as 50m/s. Based on this K1 =1

K2 = Terrain, height, structure factor which is taken from table 2 = 1.05

K3 = Topography factor which is taken as 1 (θ<3 = 1 and θ>3 = 1 to 1.36)

K4 = Importane factor for cyclonic region K4 is taken as 1.15

Where K4 = 1.3 Structure for post cyclonic importance
= 1.15 Industrial structure
= 1 All other structure

RESULT :

  • Design wind speed Vz = Vb x K1 x K2 x K3 x K4 = 50 x 1 x 1.05 x 1 x 1.15 = 60.375m/s =60.4m/s
  • Design wind pressure = Pz = 0.6 x Vz^2 = 2188.8N/m2 = 2.188KN/m2 = 2.2KN/m2

4. Based on the above calculation apply the loadings on the model

AIM: To apply wind load on the model based on wind load calculations as per IS 875 part III

INTRODUCTION:

  • Wind speed = 50m/s
  • Life period = 50yrs
  • Terrain category = 2
  • Design wind speed Vz = Vb x K1 x K2 x K3 x K4 = 50 x 1 x 1.05 x 1 x 1.15 = 60.375m/s =60.4m/s
  • Design wind pressure = Pz = 0.6 x Vz^2 = 2188.8N/m2 = 2.188KN/m2 = 2.2KN/m2
  • Length = 19.225, Width = 10.7m, Height = 16.88m
  • L/W = 1.8 and H/W = 1.57
  • External pressure coefficients for wall is taken from table 5 IS 875 III (H/W=1.57)

External Pressure Coefficients (Cpe) for Pitched Roofs of Rectangular Clad Buildings

PROCEDURE :

  • select Load cases and add wind loads

Above calculated loads are applied on the model

RESULTS :

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