Challenge

Section Modulus calculation and optimization

Aim:

To calculate the section modulus of the Hood design and improve the section of hood and calculate the section modulus and compare the cases.

Introduction:

Section modulus is defined as a geometric property of a given cross-section used in designing the flexural structures. It is purely dependent only on the cross-section of the member.

There are two types of section modulus

  • Elastic section of modulus
  • plastic section of modulus

Section modulus by using the formula S = I/y

S = Section Modulus

I = Moment of Inertia

y = distance between the neutral axis and the extreme end of the object

Moment of inertia:

The bending stiffness of a structural member’s cross-sectional shape.

Moment of inertia is specific to bending of the cross section of the member.

Case 1- Original Design:

In the original hood design,

From the analysis, we got minimum moment of inertia as

I min = 1.590294342e+04[mm^4] and We know y = 439.5mm from measuring the distance between the neutral axis and the extreme end.

Therefore, S= I/y

I min = 1.590294342e+04[mm^4]

y = 439.5mm

S = 1.590294342e+04[mm^4] / 439.5

Section Modulus S min= 36.18 mm^4

Case 2- Modifying the original Hood design:

Changes made to increase the strength of the hood:

Improving the section modulus by modifying the design by offsetting the outer panel by 2 mm in outward direction.

From the analysis, we got minimum moment of inertia as

I min =1.689915388e+04[mm^4]

And y = 439.5mm.

Therefore, S min = 1.689915388e+04[mm^4] / 439.5

S min = 38.45 mm^4.

Table

Case Design Moment of Inertia(min) Section modulus
#1 Original hood 1.590294342e+04[mm^4] 36.18 mm^4
#2 Modified hood 1.689915388e+04[mm^4] 38.45 mm^4

Conclusion

Thus, Section modulus of the hood is calculated and section of hood is improved to increase the strength and section modulus is calculated again.

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