Section Modulus calculation and optimization

HOOD MODULE

Section modulus is a direct measure of the strength of any cross-sectional area of ​​an object around a reference axis (neutral axis).
Strength is nothing but the ability to carry more loads, so higher strength has a high ability to carry more loads.
This strength can be measured directly from the formula for the section modulus and defined by the formula below.
Cross-sectional modulus represented by the symbol "S".

S=I/Y

where 'I is the moment of inertia

'Y' is the distance from the reference line (neutral axis) to one of the extreme ends of the object.

The moment of inertia is nothing but the resistance to moment, bending or twisting, that is, if we apply any external load to the body, how much resistance it offers tends to deform.
The higher the value of the moment of inertia, the higher the resistance to deformation under a certain load, therefore we can say that the moment of inertia is directly proportional to the strength of the material, and the strength of the material can be calculated using the section modulus. .
If we change the neutral axis towards the positive or negative side, the overall strength of the body will decrease because when the neutral axis line lies in the middle of the section, it has higher strength only at a particular point, so here the value of 'Y' was inversely proportional to the modulus of the section.

Hence the formula shown above.

Using the same principle, I calculate the strength of the hood panel.

Here the moment of inertia was calculated using the obtained values ​​of the NX software

IMAX:-8.485481X105mm4

Imin:-3.18672x103mm4

The total length of the 'Y' value was 488.8252 mm

So on the neutral axis we need a 'Y' value: -Y/2=488.8252/2=244.412 mm

1) Section modulus (S):-I/Y=8.485481X105mm4/244.412mm

= 3.471 x 103 mm3 (maximum strength).

2) Section modulus (S):-I/Y=3.18672x103mm4/244.412mm

=0.013x103mm3 (minimum strength).

So the hood strength ranges from 0.013 x 103 mm3 to 3.471 x 103 mm3

Now one more clue is that here the curve of the inner panel is shifted outwards by 1 mm, increasing the cross-sectional area, the results are shown below.



I got the values

IMAX: -8.4462 x 105mm4

Imin:-3.61202x103mm4

The total length of the 'Y' value was 488.8252 mm

So on the neutral axis we need a 'Y' value: -Y/2=488.8252/2=244.412 mm

1) Section modulus (S):-I/Y=8.4462X105mm4/244.412mm

=3.455X103mm3 (maximum strength).

2) Section modulus (S):-I/Y=3.61202x103mm4/244.412mm

=0.014x103mm3 (minimum strength).

So the hood power ranges from 0.014x103mm3 to 3.455X103mm3.

So here when comparing both hoods there are changes in the MAX and MIN strength values, which I found that when I increased the cross-sectional area by 1 mm, the minimum strength value increased from 0.013x103mm3 to 0.014x103mm3, so with the increase the cross-sectional area leads to an increase fortress.
But when we saw the value of the maximum strength, its slight decrease from 3.471X103mm3 to 3.455X103mm3, I think it is due to the construction of the hood, here we want to know that when the cross-sectional area increases, the minimum strength will increase or maximum strength or increase both.
So Newton's first law also explains that if the mass is higher, the force required to move the object is also high because it puts more resistance to the movement of the object. We called this resistance MOMENT OF INERTIA.
The same principle will work in the case of the hood, i.e. increasing the cross-sectional area by 1 mm, the minimum bearing capacity or strength increased by approximately 8% percent, as we observed from the above discussion.
The strength of the material also depends on the composition of the material, the thickness and the cross-sectional area of ​​the object.

CONCLUSION:-

The strength of the material is directly proportional to the moment of inertia, therefore increasing the cross-sectional area leads to an increase in the total weight of the object, i.e. an increase in strength.