Section Modulus calculation and optimization
AIM:
To calculate the section modulus of the hood and optimize the design to have an improved section modulus.
SECTION MODULUS:
S=I/Y
Here,
S = Section modulus
I= Moment of Inertia (Unit mm 4)
Y= Distance from Neutral axis to the extreme end (unit mm)
The Unit of a “section modulus” is (mm3)
DISTANCES BETWEEN THE ENDS
TOTAL DISTANCE = 876 mm
Y=438mm (DISTANCE from netrual axis to one side of the end point)
While increasing the depth , strength also increases.
CASE: 1
HERE, Section modulus
S=I/Y
Here,
S = Section modulus
I= 3.02 X 10^5 (Unit mm 4)
Y= 438 (unit mm)
The Unit of a “section modulus” is (mm3)
S = 3.02 x 10 ^5 / 438
= 689.5 mm3
CASE 2: After Optimization
Here, We increased the depth of the inner panel by 0.5 mm.
HERE, Section modulus
S=I/Y
Here,
S = Section modulus
I= 3.06 X 10^5 (Unit mm 4)
Y= 438 (unit mm)
The Unit of a “section modulus” is (mm3)
S = 3.065 x 10 ^5 / 438
=700 mm3
CONCLUSION:
- After the calculations of the above 2 cases, the section modulus of an S1 and S2 difference is 11.5mm3. The section modulus value of Case 2 is higher than Case 1.
- As we increase the section area, the moment of inertia & section modulus increase, and strength also increases.
CASE 2 is better than CASE 1.