CALCULATE SECTION MODULUS AND OPTIMIZATION OF CAR HOOD

CALCULATE SECTION MODULUS AND OPTIMIZATION OF CAR HOOD:

OBJECTIVE:

• The aim of the project is to find the section modulus using the formula S=I/Y of the designed front hood and optimizing it to get an improved section modulus compared to the previous section.

What is Section Modulus:

• Ratio of total moment resisted by the section to the stress in the extreme fibre.
• It gives us an idea about how much of load the given structure can take.
• If the section modulus increases the moment of resistance increases and hence its load bearing capacity.

Then the value can be used to find out the section modulus using the formula given

`mathsfS=mathsfI/mathsfY`

where,

`mathsfS` - Section Modulus

`mathsfI` - Moment of inertia value from the inertia analysis

`mathsfY` - Distance from Neutral axis to outermost fiber

It is also often used to determine the yield moment (My) such that,

My = s`times``sigmamathsfy`

where,

`sigmamathsfy` - Yield Strength of the material (515 MPa = 515 N/`mathsfmmathsfm^mathsf2` for stainless steel)

ANALYSIS:

• CASE 1:

Y=440mm

Maximum Moment of Inertia `mathsfI=` 4.799083717`times``10^mathsf6` `mathsfmmathsfm^mathsf4`

Minimum Moment of Inertia `mathsfI=` 1.408907500`times``10^mathsf4` `mathsfmmathsfm^mathsf4`

For Maximum Moment of Inertia,

`mathsfS = (mathsf4.799083717 times 10^mathsf6) / mathsf440`

`mathsfS = mathsf10907.00 mathsfmmathsfm^mathsf3`

My `=` `mathsf10907.00timesmathsf515`

My `=` `mathsf5.61timesmathsf10^mathsf6`Nmm

For Minimum Moment of Inertia,

`mathsfS = (mathsf1.408907500 times 10^mathsf4) / mathsf440`

`mathsfS = mathsf32.02 mathsfmmathsfm^mathsf3`

My `=` `mathsf32.02timesmathsf515`

My `=` `mathsf16.49timesmathsf10^mathsf3`Nmm

• CASE 2:

After increasing the gap between inner and outer panel of hood without alternating the design constraints.

Y=440mm

Maximum Moment of Inertia `mathsfI=` 4.790705747`times``10^mathsf6` `mathsfmmathsfm^mathsf4`

Minimum Moment of Inertia `mathsfI=` 1.436271252`times``10^mathsf4` `mathsfmmathsfm^mathsf4`

For Maximum Moment of Inertia,

`mathsfS = (mathsf4.790705747 times 10^mathsf6) / mathsf440`

`mathsfS = mathsf10887.96 mathsfmmathsfm^mathsf3`

My `=` `mathsf10887.96timesmathsf515`

My `=` `mathsf5.60timesmathsf10^mathsf6`Nmm

For Minimum Moment of Inertia,

`mathsfS = (mathsf1.436271252 times 10^mathsf4) / mathsf440`

`mathsfS = mathsf32.64 mathsfmmathsfm^mathsf3`

My `=` `mathsf32.64timesmathsf515`

My `=` `mathsf16.81timesmathsf10^mathsf3`Nmm

Conclusion:

• Thus the section modulus of the Front Hood of a car was calculated. Hence I'm concluding that when the sectional area of the hood increases the stiffness and resistance of the hood will also be increased