Section Modulus calculation and optimization

Hood Design Section Modulus;

Section modulus is to find the geometric property for a given cross-section used in the design.It is used to find out the strength of the hood and increase its strength.

Section modulus (S) = I/Y

I = Moment of inertia of structure.

Y = Distance between the neutral axis and the extreme end of the object.

Section modulus-1;

Maximum moment of inertia(max) = 4.885951709e+06[mm^4]

Minimum moment of inertia(min) = 1.417298010e+04[mm^4]

The total distance of the hood Y = 880.1915 mm

Distance between the neutral axis to the extreme end = (880.1915/2) = 440.096 mm

To find section modulus of HOOD section, we have to calculate

1)Section modulus(S):-I/Y=4.885951709e+06[mm^4]/440.096 mm

=11.08X10³mm³(Maximum strength).

2) Section modulus(S):-I/Y=1.417298010e+04[mm^4]/ 440.096 mm

=0.032x10³mm³(minimum strength).

Section modulus-2;

I have increased the distance between outer and inner panel by 3mm compared to the existing one.

Maximum moment of inertia(max)= 4.874329731e+06[mm^4]

Minimum moment of inertia(min) = 1.565969350e+04[mm^4] =

To find section modulus of new HOOD section, we have to calculate

1)Section modulus(S):-I/Y=4.874329731e+06[mm^4]/440.096 mm

=11.075X10³mm³(Maximum strength).

2) Section modulus(S):-I/Y= 1.565969350e+04[mm^4]/ 440.096 mm

=0.0358x10³mm³(minimum strength).

From the above calculations, I got an improvement in section modulus for about 0.0358x10³ mm3

so that I also made an improvement in resistance to bending of my HOOD design.