Project on Concrete Mix Design for various grades of Concrete
*INDICATES=MULTIPLICATION
Concrete Mix Design for M35 grade concrete with fly ash;
Mix proportion of concrete using fly ash
a)Grade ; M35
b)Type of cement : OPC 43 grade conforming to IS 8112
c)Type of mineral admixture : fly ash Cnforming to IS 3812(Part 1)
d)Maximum norminal size of aggregate : 20mm
e)Minimum cement content : 320kg/mm2
f)Maximum water cement ratio:0.45
g)Workability: 100mm
h)Expoure condition : Severe(for reinforcement concrete)
i)Maximum cement content :450kg/mm3
j) chemical admixture type :superplasitizer
2)Test data for materials;
a)cement used : OPC 43 grade
b)specific gravity of cement :3.15
c)fly ash conforming IS 3812(Part1)
d) specific gravity of fly ash :2:2
e) specific gravity of
coarse aggregate :2.74
fine aggregate :2.74
f)water obsartion
coarse aggregate :0.5%
fine aggregate :1.0%
g)free surface moisture
coarse aggregate : NIL
fine aggregate :NIL
D) seive analysis
as per code book for coarse aggregate
fine aggregate : conforming to grading zone 1 of table 4 of IS 383
3) Target stength for mix proportion
f'ck=fck+1.65S
=35+1.65*5=43.25n/mm^2
4)Selection of Water-cement ratio ;
From Table 5 of IS 456: 2000 for severe exposure, maximum water-cement ratio = 0.45
Based on experience, adopt water-cement ratio as 0.40
0.40 < 0.45, Hence O.K
5)Selection of Water content
From Table 2 of IS 10262: 2009, maximum water content for 20mm aggregate = 186 litre (for2Smm to 50mm slump range)
Estimated water content for 100mm slump 186 + 6/100 *186=197 litre
As superplasticizer is used, the water content can be reduced up to 30%
Based on trials water content reduction of 29% is achieved with plasticizer.
Hence the arrived water Content = 197*0.71 = 140 litre
6)Calculation of Cement Content:
Water-cement ratio = 0.4
Cementitious material(cement + fly ash)content -140/0.4 =350 kg/m^3
From Table 5 Of IS 456 minimum cement content for 'severe' exposure condition= 320 kg/mA3
350 kg/mA3 > 320 kg/rnh3, Hence OK
Cementitious material content = 350*1.10=385 KG/M^3
Water content =140KG/M^3
Water-cement ratio =140/385=0.365
Fly ash @ 30% total cementitious material content =385*30%=115KG/M^3
cement (OPC) =385-115=270KG/M^3
saving of cement while using fly ash =350-270=80KG/M^3
fly ash being utilized = 115KG/M^3
Proportion of Volume of coarse aggregate and Fine aggregate content:
From Table 3 of IS 10262: 2009, Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone l) for ratio 0.6
In the present case the water cement ratio is 0.40
- Therefore, the volume Of coarse aggregate needs to be increased to decrease the fine aggregate content.
- As water-cement ratio is lower by 0.10, the proportion Of volume Of coarse aggregate is increased by 0.02. (atthe rate of-/+ 0.01 for every ± 0.05 change in water-cement ratio).
Therefore, corrected volume of coarse aggregate for the water-cement ratio of 0.40= 0.62
For pumpable Concrete these Values are reduced by 10%
Therefore, volume of coarse aggregate 0.62*0.9 =0.56
Volume of fine aggregate content=1-0.56=0.44
7) Mix Calculations:
The mix calculation per unit volume Of concrete shall be as follows:
- Volume of Concrete 1 M^3
- Volume of Cement = Mass ofcement/Specific gravity of cement*1/100=270/3.15*1/1000=0.086m^3
- Volume of Fly ash = Mass of fly ash /Specific gravity of fly ash*1/100 =115/3.15*1/1000=0.052m^3
4) volume of water =mass of water /specific gravity of water*1/100
=140/1*1/1000=0.140m^3
5) volume of chemical admixture =mass of chemical admixture/specific gravity of admixture *1/100
=7.6/1.145*1/1000=0.006m^3
6) volume of aggregate (FA&CA) = (a-(b+c+d+e))
=(1-(0.086+0.052+0.14+0.006))
=0.716m^3
7) Mass of coarse aggregate =f*volume of coarse aggregate *specific gravity of coarse aggregate *1000
=0.716*0.56*2.74*1000=1098KG/M^3
8)mass of fine aggregate =f*volume of fine aggregate *specific gravity of fine aggregate *1000
=0.716*0.44*2.74*1000=863KG/M^3
9) Mix proportions for Trial Number 1:
Cement =270KG/M^3
Fly ash =115KG/M^3
Water =140KG/M^3
Fine aggregate =868KG/M^3
Coarse aggregate =1098KG/M^3
Chemical admixture =7KG/M^3
Water-cement ratio =0.364
Trial Mix Ratio =1:2.12:2.54
Concrete Mix Design for M50 grade concrete without Fly ash
Mix proportion of concrete Without fly ash
a)Grade ; M50
b)Type of cement : OPC 43 grade conforming to IS 8112
c)Maximum norminal size of aggregate : 20mm
d)Minimum cement content : 320kg/mm2
e)Maximum water cement ratio:0.45
g)Workability: 100mm
h)Expoure condition : Severe(for reinforcement concrete)
i)Maximum cement content :450kg/mm3
j) chemical admixture type :superplasitizer
2)Test data for materials;
a)cement used : OPC 43 grade
b)specific gravity of cement :3.15
c) specific gravity of
coarse aggregate :2.74
fine aggregate :2.74
e)water obsartion
coarse aggregate :0.5%
fine aggregate :1.0%
f)free surface moisture
coarse aggregate : NIL
fine aggregate :NIL
D) seive analysis
as per code book for coarse aggregate
fine aggregate : conforming to grading zone 1 of table 4 of IS 383
3) Target stength for mix proportion
f'ck=fck+1.65S
=50+1.65*5=58.25n/mm^2
4)Selection of Water-cement ratio ;
From Table 5 of IS 456: 2000 for severe exposure, maximum water-cement ratio = 0.45
Based on experience, adopt water-cement ratio as 0.40
0.40 < 0.45, Hence O.K
5)Selection of Water content
From Table 2 of IS 10262: 2009, maximum water content for 20mm aggregate = 186 litre (for2Smm to 50mm slump range)
Estimated water content for 100mm slump 186 + 6/100 *186=197 litre
As superplasticizer is used, the water content can be reduced up to 30%
Based on trials water content reduction of 29% is achieved with plasticizer.
Hence the arrived water Content = 197*0.71 = 140 litre
6)Calculation of Cement Content:
Water-cement ratio = 0.4
cement content =140/0.4 =350 kg/m^3
From Table 5 Of IS 456 minimum cement content for 'severe' exposure condition= 320 kg/mA3
350 kg/mA3 > 320 kg/rnh3, Hence OK
Proportion of Volume of coarse aggregate and Fine aggregate content:
From Table 3 of IS 10262: 2009, Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone l) for ratio 0.6
In the present case the water cement ratio is 0.40
- Therefore, the volume Of coarse aggregate needs to be increased to decrease the fine aggregate content.
- As water-cement ratio is lower by 0.10, the proportion Of volume Of coarse aggregate is increased by 0.02. (atthe rate of-/+ 0.01 for every ± 0.05 change in water-cement ratio).
Therefore, corrected volume of coarse aggregate for the water-cement ratio of 0.40= 0.62
For pumpable Concrete these Values are reduced by 10%
Therefore, volume of coarse aggregate 0.62*0.9 =0.56
Volume of fine aggregate content=1-0.56=0.44
7) Mix Calculations:
The mix calculation per unit volume Of concrete shall be as follows:
- Volume of Concrete 1 M^3
- Volume of Cement = Mass ofcement/Specific gravity of cement*1/100=350/3.15*1/1000=0.111m^3
3) volume of water =mass of water /specific gravity of water*1/100
=140/1*1/1000=0.140m^3
4) volume of chemical admixture =mass of chemical admixture/specific gravity of admixture *1/100
=7.6/1.145*1/1000=0.006m^3
5) volume of aggregate (FA&CA) = (a-(b+c+d))
=(1-(0.111+0.052+0.14+0.006))
=0.743m^3
6) Mass of coarse aggregate =e*volume of coarse aggregate *specific gravity of coarse aggregate *1000
=0.743*0.56*2.74*1000=1143KG/M^3
8)mass of fine aggregate =e*volume of fine aggregate *specific gravity of fine aggregate *1000
=0.743*0.44*2.74*1000=898KG/M^3
9) Mix proportions for Trial Number 1:
Cement =350KG/M^3
Water =140KG/M^3
Fine aggregate =898KG/M^3
Coarse aggregate =1143KG/M^3
Chemical admixture =7KG/M^3
Water-cement ratio =0.4
Trial Mix Ratio =1 : 2.54 : 3.24