Challenge

Project on Concrete Mix Design for various grades of Concrete

AIM:

To calculate the concrete mix design for M35 grade concrete with fly ash & M50 grade concrete without fly ash.

  • OBJECTIVE:

The objective of this project is to produce a mix design for M35 grade concrete containing fly ash and M50 grade concrete. The mix will be prepared as per IS METHOD: Concrete mix proportioning guidelines from IS 10262:2009 and recommented guide lines from IS 10262:1982.

  • EQUATIONS USED:

1)Target mean strength

f'ck=fck + 1.65s

Where

  • f'ck = target average compressive strength at 28 days
  • fck characteristics compressive strength at 28 days,and
  • S= standard deviation

2) Cement content

Cement content = water content / water-cement ratio

3) Volume Calculations

(a) Volume of concrete (b) Volume of cement = [Mass of cement] / [Specific

(c) Volume of water = [Mass of water] / [Specific

(d)Volume of chemical admixture = [Mass of admixture] / [Specific Gravity of admixture] x 1/1000

Gravity of Cement] x 1/1000 Gravity of water] x 1/1000 (g) Mass of fine aggregate= ex Volume of Fine Aggregate x Specific Gravity of Fine Aggregate x 1000

(e) Volume of all in aggregate =[a-(b+c+d)] (f) Mass of coarse aggregate= e x Volume of Coarse

PART 1

  • To Calculate the Concrete Mix Design for M35 grade concrete with fly ash:

M35 grade concrete with Fly ash

STEP 1: Stipulations for Concrete design mix

Grade designation = M35

Type of cement = opc 43 Grade confirming to IS 8112

Type of mineral admixture = fly ash confirming to IS 3812 (Part 1)

Maximum nominal size of aggregate. =20 mm

Minimum cement content =320 kg/m³ (Table 5 of IS 456:2000- Exposure condition)

aximum water-cement ratio =0.45 (Table 5 of IS 456:2000 Exposure condition)

Workability. = 100 mm (slump value for pumpable concrete)

Exposure condition. = Severe (For Reinforced Concrete)

Method of concrete placing =Pumping

Degree of supervision =good

Type of aggregate =Crushed Angular Aggregates

Maximum cement content. =450 kg/m³

Chemical admixture type =Super Plasticizer

STEP 2: TEST DATA FOR MATERIALS

Cement used= OPC 43 Grade conforming IS 8112

Specific gravity of cement. =3.15

Fly ash=confirming to IS 3812 (Part 1)

Specific gravity of fly ash=2.2

Chemical admixture=Super Plasticizer conforming to IS 9103

Specific gravity of coarse aggregate=2=74

Specific gravity of fine aggregate=2.74

Water absorption of coarse aggregate=0.5%

Water absorption of fine aggregate=1.0%

Free surface moisture of Coarse aggregate =Nil

Free surface moisture of Coarse aggregate=Nil

Sieve analysis: Coarse aggregate=Conforming to Table 2 of IS 383

Sieve analysis: Fine aggregate Conforming to Grading Zone II of Table 4 of IS 383

STEP 3: TARGET STRENGTH FOR MIX PROPORTIONING

f'ck=fck+1.65s

Where

  • f'ck = target average compressive strength at 28

days fck characteristics compressive strength at 28

days, and

  • standard deviation

From Table I of IS 10262:2009, Standard Deviation, s = 5 N/mm².

35+1.65 x 543.25 N/mm²

  • Target mean strength = 43.25 N/mm²

The Standard deviation (S) value for the M35 grade concrete is given in table 8 of 1S456.

STEP 4: SELECTION OF WATER-CEMENT RATIO

The maximum water-cement ratio to design M50 grade concrete can be found from Table 5 of IS 456-2000.

Maximum W/C ratio =0.45

Based on experience adopted water cement ratio is .44 0.44 0.45, hence ok

Adopted W/C ratio=0.44

STEP 5: SELECTION OF WATER CONTENT

[26/06, 1:54 pm] .: From Table 2 of IS 10262:2009, maximum water content for

20 mm aggregate

186 litre (for 25 to 50 mm slump range)

Clause 4.2 suggests increasing of 3% of water content for every extra 25mm slump from 50mm slump. So a 6% is to be added to it

Estimated water content for 100 mm slump

186+ (6/100)*186 = 197 litre.

(Note: If Super plasticizer is used, the water content can be reduced up to 20% and above.)

Based on trials with Super plasticizer water content reduction of 20% has been achieved, Hence the arrived water content

197*0.8 158 litre

Water required 158 litres

STEP 6: CALCULATION OF CEMENT AND FLY ASH REQUIRED

Adopted w/c Ratio =0.44

Total cementitious (Cement + fly ash)requirement =Water content/ Water Cement ratio

158/0.44 359 kg/m³

The cementitious content has to be increased in order to attain good workability and strength. The increment required is determined on the basis of experience and research. Here we are increasing cementitious content by 10%

Final cementitious content=359 X 1.10 395 kg

From Table 5 of IS 456, Minimum cement content for 'Severe' exposure conditions

320 kg

395 kg/m³ 320 kg/m³ hence ok.

Cementitious material content

395

New water cement ratio

158/395 =0.4

Fly ash content is taken as 30% of the total cementitious content

395 X.3 118.5 kg/m³

Cement required

395118277 kg/m³

Cement quantity saved due to fly ash addition

350-277 73 kg/m³

Cementitious material, cement and fly ash required is 395 kg/m³, 277 kg/m³ and 118 kg/m³ and the new water cement ratio is 0.4 respectively

STEP 7: VOLUME OF COARSE AGGREGATE AND FINE AGGREGATE CONTENT

From Table 3 of (IS 10262:2009) Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone II) for water-cement ratio of 0.50 is 0.62.

In the present case water-cement ratio is 0.44. Therefore, volume of coarse aggregate is required to be increased to decrease the fine aggregate content. As the water-cement ratio is lower by 0.06. The proportion of volume of coarse aggregate is increased by 0.02 (at the rate of -/+ 0.01 for every ± 0.05 change in water-cement ratio).

Therefore, corrected proportion of volume of coarse

aggregate for the water-cement ratio of 0.44

0.632

For pumpable concrete these values should be reduced up to 10%. Therefore, volume of coarse aggregate

0.632 x 0.9 0.568.

Volume of fine aggregate content

1-0.568=0.431

Volume of fine aggregate and coarse aggregate is 0.431 and.568

STEP 8: MIX CALCULATIONS

The mix calculations as per unit volume of concrete shall

be as follows:

a) Volume of concrete=1m³

b) Volume of cement = [Mass of cement] / [Specific Gravity of Cement] x 1/1000

(277/3.15) x (1/1000)=0.087m³

c) Volume of fly ash = [Mass of fly ash] / [Specific Gravity of fly ash] x 1/1000

(118/2.2) x (1/1000)=0.053

d) Volume of water = [Mass of water] / [Specific Gravity of

water] x 1/1000 (158/1) x (1/1000) = 0.158m³

e) Volume of chemical admixture = [Mass of admixture] / [Specific Gravity of admixture] x 1/1000

(7.6/1.145) X (1/1000) =0.006 m³

f) Volume of all in aggregate =

[a-(b+c+d+e)]

[1-(0.087+0.053+0.158+0.006)] = 0.696m³

g) Mass of coarse aggregate= fx Volume of Coarse Aggregate x Specific Gravity of Fine Aggregate x 1000

0.696x 0.568 x 2.74 x 1000 1077 kg/m³

h) Mass of fine aggregate= fx Volume of Fine Aggregate x Specific Gravity of Fine Aggregate x 1000

0.696x 0.431x 2.74 x 1000 = 822 kg/m³

STEP 9: MIX PROPORTIONS

Cement =277 kg/m³

Fly ash= 740%

Water=158 1/m³

Fine aggregate=822 kg/m³

Coarse aggregate 20mm=1077 kg/m³

Chemical admixture=7.18 kg/m³

Water-cement ratio (lowest W/C ratio is selected)=0.4

Mix Proportion By weight=1:2.08:2.72

STEP 10: The slump shall be measured, the water content and dosage of admixture shall be adjusted for achieving the required slump on trial. The mix proportion shall be reworked for the actual water content and checked for durability requirements

STEP 11: Two more trials having variation of 10% of water cement ratio shall be carried out and a graph between three water- cement ratios and corresponding strengths shall be plotted to work out the mix proportions for the given target for field trials.

PART 2:

  • To calculate the concrete mix design for M50 grade concrete without fly ash

M50 grade concrete without Fly ash

STEP 1: Stipulations for Concrete design mix

Grade designation=M50

Type of cement=OPC 53 Grade confirming to IS BIS 12269-1987

Maximum nominal size of aggregate=20 mm

Minimum cement content=320 kg/m³ (Table 5 of IS 456:2000- Exposure condition)

Maximum water-cement ratio=0.45 (Table 5 of IS 456:2000 Exposure condition)

Workability=100 mm (slump value for pumpable concrete)

Exposure condition=Severe (For Reinforced Concrete)

Method of concrete placing =pumping

Degree of supervision. Good

Type of aggregate=Crushed Angular Aggregates

Maximum cement content=450 kg/m³

Chemical admixture type=Super Plasticizer

STEP 2: TEST DATA FOR MATERIALS

Cement usedP=OPC3 Grade conforming IS 12269-1987

Specific gravity of cement=3.15

Chemical admixture=Super Plasticizer conforming to IS 9103

Specific gravity of coarse aggregate=2.74

Specific gravity of fine aggregate=0.5%

Water absorption of fine aggregate=1.0%

Free surface moisture of Coarse aggregate =Nil

Free surface moisture of Coarse aggregate=Nil

Sieve analysis: Coarse aggregate

Conforming to Table 2 of IS 383

Sieve analysis: Fine aggregate

Conforming to Grading Zone II of Table 4 of IS 383

STEP 3: TARGET STRENGTH FOR MIX PROPORTIONING

f'ck=fck + 1.65s

Where

  • f'ck = target average compressive strength at 28 days fck characteristics compressive strength at 28 days,
  • s = standard deviation

From Table I of IS 10262:2009, Standard Deviation, s = 5 N/mm².

50+ 1.65 x 5 = 58.25 N/mm²

  • Target mean strength = 58.25 N/mm²

STEP 4: SELECTION OF WATER-CEMENT RATIO

The maximum water-cement ratio to design M50 grade concrete can be found from Table 5 of IS 456-2000 for severe exposure.

Maximum W/C ratio =0.45

Based on experience adopted water cement ratio is .44

0.44 0.45, hence ok

Adopted W/C ratio=0.44

STEP 5: SELECTION OF WATER CONTENT

From Table 2 of IS 10262:2009, maximum water content for

20 mm aggregate

186 litre (for 25 to 50 mm slump range)

Clause 4.2 suggests increasing of 3% of water content for every extra 25mm slump from 50mm slump. So a 6% is to be added to it

Estimated water content for 100 mm slump

186+ (6/100)*186 = 197 litre.

(Note: If Super plasticizer is used, the water content can be reduced up to 20% and above.)

Based on trials with Super plasticizer water content reduction of 20% has been achieved, Hence the arrived water content

197 X 0.8 158 litre

Water required 158 litres

STEP 6: CALCULATION OF CEMENT REQUIRED

Adopted w/c Ratio=0.44

Cement Content

158/0.44 359 kg/m³

From Table 5 of IS 456, Minimum cement content for

'Severe' exposure conditions

320kg/m³

359 kg/m³ 320 kg/m³ hence ok.

Cement required is 359 kg/m³

STEP 7: VOLUME OF COARSE AGGREGATE AND FINE AGGREGATE CONTENT

From Table 3 of (IS 10262:2009) Volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate (Zone II) for water-cement ratio of 0.50 is 0.62

In the present case water-cement ratio is 0.44. Therefore, volume of coarse aggregate is required to be increased to decrease the fine aggregate content. As the water-cement ratio is lower by 0.06. The proportion of volume of coarse aggregate is increased by 0.02 (at the rate of -/+ 0.01 for every ± 0.05 change in water-cement ratio)..

Therefore, corrected proportion of volume of coarse aggregate for the water-cement ratio of 0.44

0.632

For pumpable concrete these values should be reduced up to 10%. Therefore, volume of coarse aggregate

0.632 x 0.9=0.568.

Volume of fine aggregate content

1 0.576=0.431

Volume of fine aggregate and coarse aggregate

is 0.431 and.568 respectively

STEP 8: MIX CALCULATIONS

The mix calculations per unit volume of concrete shall be

as follows:

a) Volume of concrete

b) Volume of cement = [Mass of cement] / [Specific Gravity of Cement] x 1/1000

(359/3.15) X (1/1000) =0.114m³

c) Volume of water = [Mass of water] / [Specific Gravity of water] x 1/1000

(158/1) X (1/1000) = 0.158m³

d) Volume of chemical admixture = [Mass of admixture] / [Specific Gravity of admixture] x 1/1000

(7.6/1.145) X (1/1000) =0.006 m³

e) Volume of all in aggregate =

[a-(b+c+d)]

[1-(0.114+0.158+0.006)] = 0.722m³

f) Mass of coarse aggregate= e x Volume of Coarse

Aggregate x Specific Gravity of Fine Aggregate x 1000

0.722x 0.568 x 2.74 x 1000 = 1123 kg/m³

g) Mass of fine aggregate= e x Volume of Fine Aggregate x Specific Gravity of Fine Aggregate x 1000

0.722x 0.431x 2.64 x 1000 = 821 kg/m³

STEP 9: MIX PROPORTIONS

Cement=359 kg/m³

Water=158 1/m³

Fine aggregate=821 kg/m/m³

Coarse aggregate 20mm=1123 kg/m³

Chemical admixture=7.18kg/m³

Water-cement ratio=0.44

Mix Proportion By weight=1:2.28:3.12

STEP 10: The slump shall be measured, the water content and dosage of admixture shall be adjusted for achieving the required slump on trial. The mix proportion shall be reworked for the actual water content and checked for durability requirements

STEP 11: Two more trials having variation of 10% of water cement ratio shall be carried out and a graph between three water- cement ratios and corresponding strengths shall be plotted to work out the mix proportions for the given target for field trials.

RESULTS:

  • Mix Proportion by weight of M35 grade of concrete with fly ash is 1:2.08:2.72 and its water-cement ratio was found to be 0.4.
  • Mix Proportion by weight of M50 grade of concrete without fly ash is 1:2.28:3.12 and its water-cement ratio was found to be 0.44.

APPENDIX

1) PHYSICAL CHARACTERSTICS OF DIFFERENT TYPES OF OPC CEMENT

Table 2 of IS 10262:2009: maximum water content for 20 mm aggregate

  • Nominal Maximum Size of Aggregate=20 mm
  • Maximum Water Content kg/m³=189

CONCLUSION:

  • The slump should be measured and the water content and admixture can be adjusted to obtain the required slump. The mix proportion can be adjusted and reworked as per requirement.

Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.