Project 3

1. Input voltage = 48 , output voltage: 12 V

assume fs=100khz , ripple voltage = 5%

duty ratio: 12/48 = 0.25

load(R) = Vout/Iout = 12/10 = 1.2 ohm

Lmin = (1-D)*R/2*fs = 4.6millihenry

Cmin = (1-D)/(8*L*fs^2(deltavo/v)) = 0.407millifarad

the output is lower than the voltage and current should be there because of the losses of the switch that has to be conisdered