Challenge

Project 2

PROJECT- part(a)

There are 2 heat sources for the battery heat generation

  1. Joules heat
  2. Entropy heat

Heat generated = Joules Heat + Entropy Heat

when a current flowing through a resistance, there is a heat dissipated in the resistor. This heat dissipation is called Joule heating. Joule heating is also known as ohmic heat

Joule heat,

H = I^2*R*t

where. I = Current

R = Resistance

H = Heat

t = Time

Entropy Heat:

The heat generation due to entropy change inside a battery occurs when electro chemical reactions are performed. The entropy heat is reversible heat resulting from change in open circuit voltage with respect to temperature at two Electrodes.

Given data

Battery resistance = 0.5 mOhm = 0.0005 Ohm

Maximun current = -0.896 A

Max current time = 1.7 sec

Entropic factor = 2

Total heat generation = Jouleheat + Entropy heat

The maximum heat generation in the battery pack

Max heat generation = Max Joule Heat + Entropy factor

Max Joule Heat = I^2 *R*t

Max Joule Heat = (-0.896)^2*1.7*0.0005

Max Joule Heat = 0.0006823936

Max heat generation = 0.0006823936 + 2 = 2.0006823936 Jouls

part(b)

CONCLUSION: here as one can see soc of the battery comes out to be 100% while running for 208sec it is happened because all current value is negative means regenerative braking has occurred which lead to charging the battery instead of discharging.

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