Project 2

Using MATLAB/simulink and the drive cycle from the attached excel sheet, find-

1. The max heat generation of the battery
2. The SOC of the battery at 2 *104second of the battery operation

Time	Time Step	Battery Current
00:00.4	0.1	-0.9632
00:00.5	0.2	-0.952
00:00.6	0.3	-0.9072
00:00.7	0.4	-0.9632
00:00.8	0.5	-1.0304
00:00.9	0.6	-0.9632
00:01.0	0.7	-1.0304
00:01.1	0.8	-1.008
00:01.2	0.9	-0.9856
00:01.3	1	-0.9632
00:01.4	1.1	-0.9184
00:01.5	1.2	-0.9296
00:01.6	1.3	-0.9296
00:01.7	1.4	-0.9296
00:01.8	1.5	-0.9184
00:01.9	1.6	-0.9408
00:02.0	1.7	-0.896
00:02.1	1.8	-0.9072
00:02.2	1.9	-0.9072
00:02.3	2	-0.9408
00:02.4	2.1	-0.9296
00:02.5	2.2	-0.9296
00:02.6	2.3	-0.9968
00:02.7	2.4	-0.9968
00:02.8	2.5	-0.9408
00:02.9	2.6	-0.9408

Consider the battery resistance is 0.5 mOhm and entropic factor is 2

entropy heat is 2.because entrophic factor is given as 2

MAximum current in the table is -0.896A,resistance is 0.5mohm and total time is 120seconds.

So,

`Max\ heat\ g en erated=(Imax)^2**R**t+2`

`Max\ heat\ g en erated=-0.896^2**(0.5**10^-3)**120+2`

`Max\ heat\ g en erated=2.048J`

SOC of the battery for 208s of the battery operation

we can see in above model battery is connected to 1ohm resistor and controlled current source and its soc is extracted from bus selector.

battery specification before simualtion

signal builder is used for to show currents which are given above

this simulation using negative currents is simulated till 208seconds and it is charging the battery that we can see below

before simulation SOC is 50% and after the simulation SOC is 51%