Challenge

Project 1 Mechanical design of battery pack

To prepare a detailed battery pack with capacity of 18 kWh drawing along with its enclosure. State your assumptions

Battery information

  • A123's high-performance Nanophosphate lithium iron phosphate(LiFePO4)battery technology delivers high power and energy density combined with excellent safety performance and extensive life cycling in a lighter weight,more compact package.
  • Our cells have low capacity loss and impedance growth over time as well as high usable energy over a wide state of charge(SOC)range, allowing our systems to meet end-of-life power and energy requirements with minimal pack oversizing.
  • Applications
    • COMMERCIAL SOLUTIONS
      • Datacenter UPS
      • Telecom backup
      • IT backup
      • Autonomously guided vehicles(AGVS)
      • Industrial robotics and material handling equipment
      • Medical devices
    • GOVERNMENT SOLUTIONS
      • Military vehicles
      • Military power grids
      • Soldier power
      • Directed energy
    • GRID SOLUTIONS
      • Versatile,flexible and proven storage solutions for the grid:
      • Frequency regulation
      • Renewables integration
      • Reserve capacity
      • Transmission and distribution
    • TRANSPORTATION SOLUTIONS
      • Hybrid,plug-in hybrid and electric vehicle battery systems for:
      • Commercial vehicles
      • Off-highway vehicles
      • Passenger vehicles

Battery pack for EV

  • Given
    • Energy = 18 kWh
    • From the battery specifications we can find
      • Capacity of the battery = 2.5 Ah
      • Nominal voltage of the battery = 3.3 V
    • From that we are assuming that the battery voltage should be 500 V
  • No of cells needed (N)
    • N = Energy / (Nominal voltage * Capacity of the battery)
    • N = 18000 / (3.3 * 2.5)
    • N = 2181.8
    • Number of cells are cannot be in decimal so by rounding the cells we can get
    • N= 2182
  • Series parallel configuration of EV battery pack
    • Cells in series (Ns) = Voltage required / nominal volatge
    • Ns = 500 / 3.3 = 151.5
    • Ns = 152 needed to be connected in series
    • With the help of 152 series configuration of cells we can achieve 500 V
    • Cells in parallel (Np) = Total cell (N) / No of series cells (Ns)
    • Np = 2182 / 152 = 14.3
    • Np = 15 nedded to be connected in parallel for the battery pack
    • The architecture of the battery is 152S15P
    • This combination of cells is higher than required cells (2182) , which exceeds the required amount of cells.
  • Battery pack capacity
    • For series combination only the voltage is added and the current remains same.
    • For paralled configuration the volatge reamins same anfd the current gets added.
    • So the capacity of the battery is = Number of cells in parllel (Np) * Battery capacity
    • Capacity of the pack = 15 * 2.5
    • Capacity of the pack = 37.5 Ah
    • The battery packs delivers 37.5 A for an hour with an 0.5 C rate
    • Lets assume the powertarin effiency to 85 % so the vehicle consumes 90 Wh/km
    • Range = Energy delivered by the pack / Energy consumed per kilometer = 18000/90
    • Range = 200 km
    • So the battery pack can deliver upto 200 km per charge
  • Charging time of the battery pack
    • The capacity of the battery is 37.5 Ah
    • The Charging current for 37.5 Ah pack
      • Charging current for 37.5 Ah Battery = 37.5 x (10/100) = 3.75 Amperes
      • But due to losses, we can take 3.75 - 4.5 Amperes for charging purpose.
    • Charging time required
      • Charging current = 4.5 A
      • We took 4.5 Amp for charging purpose,
      • Then charging time for 37.5 Ah battery = 37.5 / 4.5 = 50 minutes .
  • Thermal management of the pack
    • Indirect liquid cooling
      • To avoid the short-circuit issue, indirect methods are effective to avoid electrical conduction with cells while maintaining high thermal diffusion
      • The addition of electrical resistance may resist thermal diffusion. But its effects on cooling is not significant.
      • Some EV manufacturers such as General Motors, and Tesla are using indirect cooling in their cars.
  • Battery pack Enclosure
    • For the ANR26650 the length of the battery is 65.15 mm and the diameter of the battery is 25.96 mm
    • Lets assume that clearnce of the cell sholud be 65 mm
    • Length of the casting (L) = no of cells at series * (cell diameter + margin at both sides of the cell ) + clearance at side (diameter of edged + margin)
    • L = (152 * (26.01+4)) + 65
    • L = 4626.5 mm
    • Breadth of casting (B) = no of cells at parallel * (cell diameter + margin at both sides of the cell ) + clearance at side (diameter of edged + margin)
    • B = (15 * (26.01+4)) + 65
    • L = 515.2 mm
    • Height of the encloser = Height of cell+margin for wiring,Cell holders and metal strips
    • H = 65.15 + 40
    • H = 105 mm
  • Weight of the pack (W)
    • Pack weight = weight of each cell * total nop of cells
    • Pack weight = 76 * 2182
    • Pack weight = 166 kg
    • W = Pack weight + (Enclosure weight + metal straps)
    • W = 166 + (0.5+3)
    • W = 169.5 kg
  • Assembling the ANR26650M1-B Cells
    • From the previous step, it is clear that our battery pack is made up of 152S15P ( 15 x 3.3V = 500V ), and each parallel group has 152 cells
    • We can assemble the cells to make the pack by using hot glue or by using a plastic ANR26650M1-B battery holder.
      • We can make a custom pack of any size according to your requirement . It is obtained from Battery pack Enclosure
      • It provides space between the cells, which allow fresh air to pass and the battery gets cooled easily.
      • It makes your battery pack solid and reliable.
      • It provides safety anti-vibration to your battery pack
  • Choosing the right componemts for encloser
    • Metal strips
      • To make the battery pack, you have to connect the 2182 cells together by means of Nickel strips or thick wire.
      • Generally, Nickel strips are widely used for this.
      • In general two types of nickel, strips are available in the market:
        • Nickel-plated steel strips
        • Pure nickel strips.
      • I will suggest buying a pure nickel.
        • It is a little bit costlier than nickel-plated steel, but it has much lower resistance.
        • Low resistance means, less heat generation during the charging and discharging, which leads to longer useful battery life.
      • Nickel strips come with different dimensions and lengths. Choose the strips according to the current rating.
  • Spot Welding Vs Soldering
    • We have two options two connect the ANR26650M1-B cells together
      • Soldering
      • Spot Welding
    • The best choice is always Spot welding, but Spot Welder is much costlier than a good quality Soldering Iron.
    • Soldering :
      • We should know why Spot welding is preferred over soldering, the problem with soldering is that you apply a lot of heat to the cell and it doesn’t dissipate very quickly.
      • This enhances the chemical reaction in the cell which damages the cell's performance.
      • Ultimately you will lose some capacity and life the cells.
    • Spot Welding :
      • The reason we spot weld because it securely joins the cells together without adding much heat to them.

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