Project 1

THE SIMULINK MODEL:     WORKING OF EV-CAR MODEL: The Drive Cycle Source block generates a FTP75 longitudinal drive cycle and give specified vehicle longitudinal speed.It Produce realistic velocity and shift references for closed loop acceleration and braking commands for vehicle control according to FTP75 drive…

The simulink model: The battery parameters of each one: for coulomb counting the gain used is: output:   coulomb couts behaviour: we can observe that: SOC decreases with increasing time, current follows the controlled current source value given by a pulse generator , voltage decreases with increase in time. The behavious…

Motor ratings given: 1200Wh,65V current withdrawn by motor : P=V*I I = 1200/65 =18.4A Assuming current loss to be 5$% : 18.4*1.05 = 19.32A  So, motor current (Inew)= 19.3A Now, the power required at max. speed = V*I new = 65*19.3 = 1256W Travel factor = total range/ total speed = 225/60 = 3.75 Power required based on travel…

step 1: sldd file has to be inserted  step 2: signals and parameters are to be added   step 3: block modeling is being done:   Requirement-1 subsystem: Steering wheel input as  SteeringWheel_YawDegreeInput This is compared against 3 angular values, one each for left turn, right turn & straight drive: Right_Turn_AngularLimit,…

step 1: create new sldd file step 2: add new signals and parameters from model explorer step 3: Requirement 1– Lead Vehicle: Lead Vehicle is a vehicle which is driving in the road ahead of our drive vehicle. Two input signals (Signal Name: CameraInput_LeadVehicle & RadarInput_LeadVehicle). Ideally sensor…

  output:  torque vs speed In this system, the input is provided by a voltage controlled source using a pulse generator. It then goes to the PWM pulse generstor and then passes to H bridge. From there, DC voltage is fed into a DC motor. A torque source and a motion sensor is used for the detection of rotation of fan. The…

1. Input voltage = 48 , output voltage: 12 V assume fs=100khz , ripple voltage = 5% duty ratio: 12/48 = 0.25 load(R) = Vout/Iout = 12/10 = 1.2 ohm Lmin = (1-D)*R/2*fs = 4.6millihenry Cmin = (1-D)/(8*L*fs^2(deltavo/v)) = 0.407millifarad the output is lower than the voltage and current should be there because of the losses…

PCB can have single multiple layers of dielectric and conductive materials. These layers when attached with each other, they carry electrical circuits which sometimes linked with each other. According to applications like home electronics, alarm clocks, other household appliances, computers and mobiles. Printed circuit…

PCB can have single multiple layers of dielectric and conductive materials. These layers when attached with each other, they carry electrical circuits which sometimes linked with each other. According to applications like home electronics, alarm clocks, other household appliances, computers and mobiles. Printed circuit…

  Vdq to lambda conversion: From the above inputvoltage images we could see that the motor is powered by a 230V 3-phase suply with 60Hz. Sator resistance is set to 0.531ohms Rotor resistance is set to 0.0408ohms Stator and Rotor inductance is set to 2.52mH mutual inductance is also  set as 84.7mH Moment of inertia…

1. The BLDC and Induction motor power rating is 1100W and stator and rotor material is steel_1010 for both the machines as per question. BLDC: parameters:   setup ratings: outputs: DATASHEET:   PERFORMANCE: graphs: various graphs as output has been plotted  1. 2. 3. 4. 5. 6. 7. 8. for the same case 2. 3 phase Induction…

1.    Vref: System: voltage loop gain: Lin; Load: PID controller current loop: PID controller voltage loop: DC link capacitor: Cout: output: The outputs have been showed and we can see that the output voltage iis not reaching to 350V and output current is not reaching as per required criteria. fromt the fft analysis…

Part A: Vll=208 , F=60 hz, Ls=1mH, Cd=1100e-6, Load=2.2e3; Source inductance: Vin: DC link capacitance: load resistance: OUTPUTS: Output current and voltage: Average output voltage : The average output voltage can be seen from the waveform as 157.4V Diode blocking voltage :  The selecton of diode should be with a blocking…

This is the most popular method for controlling the speed of an induction motor. if the supply frequency is reduced while maintaining the rated supply voltage, the air gap flux will tend to saturate. This will cause excessive stator current and distortion of the stator flux wave. Therefore, the stator voltage should also…

Input parameters: load resistance: L(inductor): Capacitor: Pulse generator: outputs graph: 1. Diode volage and current: From the graph we can see that diode withstand voltage and current should be 35V and 20A. So we have chosen the diode MBR2050CT with specifications:  2. Mosfet voltage and current: The mofet chosen…

 1. Buck converter CCM mode: Input voltage- 40-50V; output voltage-30V, Power=500W; Fs=100khz; D=vout/vin=30/50=0.6; Il=Iout=500/30=16.66A; Rload=Vout/Iout=30/16.66=1.8ohm; let us take ripple current <40%, L=Vout(1-D)/Fs*del(Il)=30*(1-0.6)/100k*(0.4*16.66)=0.18uH; Assume voltage ripple = 5% C=0.55mF; Case 1: This…

1. Forward converter is a popular switched mode power supply (SMPS) circuit that is used for producing isolated and controlled dc voltage from the unregulated dc input supply. The forward converter, when compared with thefly-back circuit, is generally more energy efficient and is used for applications requiring littlehigher…

%dc motor parameters J=0.02; %moment of inertia of rotor B=0.05; %motor viscous friction Km=0.1; %back emf Kt=0.1;%motor torque constant Ra=2;%resistance of armature La=0.5; %inductance of armature %the motor equations theta_dot_dot= kt*i-B*theta_dot/J; i_dot=V-Km*theta_dot-Ra*i/La; %these two equations govern modeling…