Challenge

Design of Shallow Foundation (Isolated Footings)

AIM:

PROCEDURE AND DETAIL:

Gross bearing capacity
Assuming the unit weight of the soil to be 18kN/m³
Load on the footing= 1333.3kN
Weight of the footing,g = 3.5 X 3.5 X 25 X 0.8 = 245KN
weight of the soil= 3.5 X 3.5 X (2 - 0.8) X 18 = 261.6kN
Total load= 1852kN
Gross bearing capacity= 1852/3.5 X 3.5 =257KN/m2
As 257 kN/m² >150kN/m², hence we need to increase the size of the footing to 3.8m X 3.8m
Now total load=1934KN
gross bearing capacity=1934/3.8*3.8=133.9KN/mm2
133.9 kN/m² <150kN/m², hence safe
Corrected net soil pressure = 2000/3.8*3.8= 138.5kn

Reinforcement Bars Placement Plan

Section of the Footing

RESULT:

Ship work like this
in your own course.