Centrifugal pump design and analysis
PROJECT NAME
CENTRIFUGAL PUMP DESIGN AND ANALYSIS
AIM TO model a centrifugal pump and simulate them by the help of solidworks.
OBJECTIVE
- TO DESIGN A 3D MODEL OF CENTRIFUGAL PUMP
- Run a baseline simulation @10m/s outlet velocity.
- To obtained plot of inlet and outlet velocity.
- To obtained plot of inlet and outlet total pressure.
- To obtained plot of mass flow rate at outlet .
- To obtained trajectory of fluid flow .
- To obtained the relationship between pressure ratio (outlet pressure/inlet pressure) and mass flow rate.
- AND LASTY WE RUN A PARAMETRIC STUDY INPUT AS A OUTLET VELOCITY.
INTRODUCTION
Centrifugal pumps are used to induce flow or raise a liquid from a low level to a high level. These pumps work on a very simple mechanism. A centrifugal pump converts rotational energy, often from a motor, to energy in a moving fluid.
In simple words, it is a pump that uses a rotating impeller to move water or other fluids by using centrifugal force.
The two main parts that are responsible for the conversion of energy are the impeller and the casing. The impeller is the rotating part of the pump and the casing is the airtight passage which surrounds the impeller. In a centrifugal pump, fluid enters into the casing, falls on the impeller blades at the eye of the impeller, and is whirled tangentially and radially outward until it leaves the impeller into the diffuser part of the casing. While passing through the impeller, the fluid is gaining both velocity and pressure.
PROCEDURE
- CREATING 3D CAD MODEL OF CENTRIFUGAL PUMP
NOTE :- (Be careful when you applying extrude boss . make sure that merge option will unchecked )
In this case we also create a special rotating region which cover the impeller completely. Because in solidworks we can’t have the to rotate the impeller automatically or manually. for overcomes this problem we use this region which rotate @ 1000 rpm.
2.APPLYING LID ON INLET AND OUTLET FACE
3.CREATE NEW PROJECT AND APPLY WIZARD AS DEFFAUT WITH SOME CHANGE
WORKING FLUID AS WATER
FLOW AS INTERNAL WITH ROTATION
- APPLYING BOUNDARY CONDITION AS
ENVIROMENTAL PRESSURE AT INLET.
VELOCITY @ 10m/s AS A OUTLET .
4.APPLYING GLOBAL MESH WITH ADV. CHANNEL REFINEMENT OPTION CHECK.\
- MAKE SURE TO UNCHECKED THE REGION FROM THE COMPONENT OPTION IN INPUT DATA.
6.ADD SURFACE GOAL AS MASS FLOW RATE ,TOTAL PRESSURE AT INLET AND OUTLET.
- ALSO WE ADD CUT PLOT FOR GETTING VELOCITY AND PRESSURE VARAISION CONTOUR.
AND HIT THE RUN BOTTON
FOR THE PARAMETRICE STUDY
WE CREATE NEW PARAMETRIC STUDY INPUT PARAMETER AS OUTLET VELOCITY AS 10m/s,15m/s,20m/s,25m/s,30 m/s
FOR OUTPUT PLOT GOAL AND RESULT WE CHECKED THE ALL ABAVE PARAMETER
RESULT :-
CASE 01
FOR BASELINE OUTLET VELOCITY @10m/s.
i.Pressure cut plot contour
ii.velocity cut plot contour
iii.flow trajectoy contour
video link for flow trajectory
in this video we clearly see that velocity at the junction of cashing and suction are high and on going for from the centre the velocity decreses.
in this video we also see on some spot the trajectory revolve on its own axis or bounce back at the joint point it is due geomerty condition of the CAD MODEL .
CASE 02
PARAMETRIC STUDY
AFTER FINISHED THE CALCULATION
FOR OUTLET VELOCITY = 10m/s
i.pressure cut plot contour
ii.velocity cut plot contour
iii.flow trajectory contour
FOR OUTLET VELOCITY = 15m/s
i.pressure cut plot contour
ii.velocity cut plot contour
iii.flow trajectory contour
FOR OUTLET VELOCITY = 20m/s
i.pressure cut plot contour
ii.velocity cut plot contour
iii.flow trajectory contour
FOR OUTLET VELOCITY = 25m/s
i.pressure cut plot contour
ii.velocity cut plot contour
iii.flow trajectory contour
FOR OUTLET VELOCITY = 30m/s
i.pressure cut plot contour
ii.velocity cut plot contour
iii.flow trajectory contour
COMPARISION TABLE (GOAL PLOT)
|
Goal (Value) |
Design Point 1 |
Design Point 2 |
Design Point 3 |
Design Point 4 |
Design Point 5 |
|
Outlet Velocity(m/s) |
10 |
15 |
20 |
25 |
30 |
|
Total Pressure outlet (pa) |
4113654.34 |
4206978.214 |
3307745.299 |
5005033.201 |
7581346.662 |
|
Total Pressure inlet(pa) |
421817.6354 |
426358.807 |
345397.8512 |
424628.5422 |
617127.8456 |
|
Mass Flow Rate(kg/s) |
-0.496112293 |
-0.743532068 |
-0.992264796 |
-1.238589829 |
-1.485941831 |
|
Pressure Ratio |
9.752210422 |
9.867224848 |
9.576623849 |
11.78685063 |
12.28488832 |
Note Design Point 1 represent the value corresponding to outlet velocity @10 m/s
Design Point 2 represent the value corresponding to outlet velocity @15 m/s
Design Point 3 represent the value corresponding to outlet velocity @20 m/s
Design Point 4 represent the value corresponding to outlet velocity @25 m/s
Design Point 5 represent the value corresponding to outlet velocity @30 m/s
Here we see that pressure at outlet increase gradually but suddenly its drop and again it increase at a very sharp slope magnitude.
In this plot, its seem to the flow rate will decreasing on increasing the velocity but actually we focus on magnitude it seem to increase. Its is negative due to the flow direction. So velocity is directly proportional to mass flow rate.
Here we see that pressure at outlet increase gradually but suddenly its drop and again it increase at a very sharp slope magnitude
PLOT OF PRASSURE RATIO VS MASS FLOW RATE
here also mass flow rate (neglecting the minus sign only focus on magnitude) directly proportional to the pressure ratio.
Secand point the pressure ratio will also increasing with increase in outlet velocity.