Challenge

Flow over a cylinder

AIM TRANSIENT FLOW SIMULATION OF FLOW OVER A CYLINDER USING SOLIDWORKS FLOW SIMULATION

INTRODUCTION

IN THIS PROJECT WE ARE GOING TO RUN A SIMULATION OF FLUID FLOW (AIR) OVER A PIPE WITH DIFFERENT VELOCITY OR HAVING DIFFERENT REYNOLDS NUMBER ACC. TO GIVEN DATA.

ABOUT CFD CFD simulation was applied to analyse the dynamic behaviour of stirred systems with different impeller geometries. An offline video processing method was developed to compute mixing time and validate simulation results. The CFD simulation results, and the video processing based mixing times were compared to the naked eye experiment. The developed method is a good way to validate CFD models in laboratory environments by using only a camera and suitable video processing tool. However further research might be necessary to eliminate minor data processing problems, and further simulation studies will be conducted and compared to a wider range of experimental data.

FOR NOW, we are using solidworks flow simulation its helps the visualize the flow on our computer this is much much closer to rael world example if we apply all equation and condition properly.so now we start,

WE KNOW THAT

REYNOLDS NUMBER (Re) = inertia force/viscous force

= rho * V * D /Mu

=(ρ* V*D)/μ

Where

ρ is mass density

V is the velocity of fluid

D diameter of cylinder

μ is dynamic viscosity of flowing fluid

Fluid taken as air

Density of air (rho air) = 1.225 kg/m^3

Kinematic viscosity of air @ 293k = 1.516x10^-5 m^2/s

We are going to assumed the air velocity = 10m/s

Length of computational domain taken as (l) = 0.5m

CALCULATION

DIAMETER OF CYLINDER (D) = 0.04 M

LENGTH OF CYLINDER (L) = 0.05M

Re = rho * V * D /Mu

Re = V D/v ( kinematic viscosity (v) = mu/rho)

CASE 01

BASELINE CASE

Re =VD/v

= 10*0.04/1.516X10^-5

=26385.22

=26385(APPORX)

CASE 02

Increasing value of Reynolds number by 20%

So,

New Re value = 26385 + 26385 *20/100

=31662

Velocity corresponding to new Re value

V = Re*v/D

Putting value,we get

V = 31662*1.516x10^-5/0.04

V = 11.999

V=12

CASE 03

Increasing value of Reynolds number by 40%

So,

New Re value = 26385 + 26385 *40/100

= 26385+10554

=36939

Velocity corresponding to new Re value

V = Re*v/D

Putting value,we get

V = 36939*1.516x10^-5/0.04

V = 13.9999

V=14

CASE 04

Increasing value of Reynolds number by 100%

So,

New Re value = 26385 + 26385 *100/100

= 26385+26385

=52770

Velocity corresponding to new Re value

V = Re*v/D

Putting value,we get

V = 52770*1.516x10^-5/0.04

V = 19.999

V=20

CALCULATION FOR SIMULATION TIME

FLOW THROUGH TIME = COMPUTATIONAL DOMAIN LENGTH / VELOCITY

SIMULATION TIME = 2* FLOW THROUGH TIME

TABLE FOR CALCULATED DATA

VELOCITY(M/S)

REYNOLD’S NO

FLOW THROUGH TIME (l/V) IN SEC

SIMULATION TIME IN SEC

CASE 01

10

26385

0.0500

0.1000

CASE 02

12

31662

0.0416

0.0832

CASE 03

14

36939

0.0357

0.0714

CASE 04

20

52770

0.0250

0.0500

PROCEDURE

  1. MODELING PART OF PIPE IN SOLIDWORKS

Dia of pipe is 0.04 m

Length of pipe is 0.05 m

2.CREATE NEW PROJECT BY USING WIZARD OPTION

3.SELECT THE EXTERNAL FLOW CONDITION

4.SELECT AIR AS FLOWING FLUID

5.WE ARE GOING TO ENTER THE FLOW VELOCITY ( 10 m/s ) IN ONLY X DIRECTION

6. mesh Now we create the mesh . its helps the model to divide into many smaller cube so we can see the flow of fluid very close partical level real world example and also helps us to find the fine contour. So we set the golobal mesh setting to 5 . it means , solidworks going to create very fine mesh in computational domain

FINALLY RUN THE SIMULATION FOR DIFFERENT VELOCITY AND FIND VARIOUS PLOT AS WELL AS ANIMATION OF FLOWING FLUID

RESULT

HERE WE REPRESENT THE FOLLOWING PLOT AND ANIMATION ONE BY ONE

CASE 01 VELOCITY ALONG X AXIS 10 m/s

Cut plot for velocity contour

Animation link for velocity variation

https://youtu.be/EFEr3vqnxuM

Cut plot for pressure contour

Animation link for pressure variation

https://youtu.be/an_0IOkOl-I

EXPLANATION

when air hit the cylinder surface due to the circular cross section of cylinder the air get diverges and that result increase in pressure in the contact area region and decrease in velocity of airon other hand the velocity after the impact or a distance from the cylinder vlocity get normal or uniform.

we see the pressure at the top or bottom side have min. value on other hand velocity is maxmium at that region.

from above observation we see that pressure is inversly proportional to the velocity

CASE 02 VELOCITY ALONG X AXIS 12 m/s

Cut plot for velocity contour

Animation link for velocity variation

https://youtu.be/avM7nyrGpSc

Cut plot for pressure contour

Animation link for pressure variation

https://youtu.be/LrgZtkgavT0

EXPLANATION

when air hit the cylinder surface due to the circular cross section of cylinder the air get diverges and that result increase in pressure in the contact area region and decrease in velocity of airon other hand the velocity after the impact or a distance from the cylinder vlocity get normal or uniform.

we see the pressure at the top or bottom side have min. value on other hand velocity is maxmium at that region.

from above observation we see that pressure is inversly proportional to the velocity

CASE 03 VELOCITY ALONG X AXIS 14 m/s

Cut plot for velocity contour

Animation link for velocity variation

https://youtu.be/s3ayDFlvFRA

Cut plot for pressure contour

Animation link for pressure variation

https://youtu.be/3ShvRDZL108

EXPLANATION

when air hit the cylinder surface due to the circular cross section of cylinder the air get diverges and that result increase in pressure in the contact area region and decrease in velocity of airon other hand the velocity after the impact or a distance from the cylinder vlocity get normal or uniform.

we see the pressure at the top or bottom side have min. value on other hand velocity is maxmium at that region.

from above observation we see that pressure is inversly proportional to the velocity

CASE 04 VELOCITY ALONG X AXIS 20 m/s

Cut plot for velocity contour

Animation link for velocity variation

https://youtu.be/OQkM7II6nYM

Cut plot for pressure contour

Animation link for pressure variation

https://youtu.be/Y2QuhhxlBO8

EXPLANATION

when air hit the cylinder surface due to the circular cross section of cylinder the air get diverges and that result increase in pressure in the contact area region and decrease in velocity of airon other hand the velocity after the impact or a distance from the cylinder vlocity get normal or uniform.

we see the pressure at the top or bottom side have min. value on other hand velocity is maxmium at that region.

from above observation we see that pressure is inversly proportional to the velocity

CONCLUSION

AS WE INCREASE THE VELOCITY OF AIR WE GET WELL UNIFORM FORM OF SIMULATION AND THE THE FLOW WILL GET UNIFORM IN SHOT RANGE LENGTH.

AFTER IMPACT INCREASE IN VELOCITY LEAD THE DECREASE IN PRESSURE DUE TO IMPACT AT CYLINDER SURFACE

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