Challenge

Week 8 Challenge

AIM

To calculate the Dead load, live load, and wind load at manual with a reference of Indian standard code and apply to the model by using TEKLA Software.

PROCEDURE

  • To add the load cases of all categories.
  • To calculate the Dead load calculation of Finishes, Brick wall, services.
  • To add the Load at a model with reference of the given layout.

Calculation of Dead Load

  • Finishes Loading ( 50mm thick )

= 0.05 x 24

= 1.2 KN/m^2.

  • Brick wall load with cement plaster thickness.

Unit weight of brick wall = 20KN/m^3

@ Ground floor to First Floor ( 3.5m height )

  • Exterior wall ( 230 mm thickness )

= 0.230 x 20 x 3.5

= 16.56 KN/m.

  • Interior wall ( 125 mm thickness )

= 0.125 x 20 x 3.5

= 8.75 KN/m.

@ First floor to Top Floor ( 3.5m height )

  • Exterior wall ( 230 mm thickness )

= 0.230 x 20 x 3.5

= 16.56 KN/m.

  • Interior wall ( 125 mm thickness )

= 0.125 x 20 x 3.5

= 8.75 KN/m.

  • Roofing load.

= 1.5 KN/m^2.

  • Similarly, to find the live load

Calculation of Live Load

As we taken the value of all areas of Live Load from IS 875, PART-2, TABLE-1.

  • Store room = 5 KN/m^2.
  • Office room = 3 KN/m^2.
  • Rest room = 2 KN/m^2.
  • Toilets = 2 KN/m^2.
  • Staircase = 5 KN/m^2.
  • Equipment Room = 10 KN/m^2.
  • Conference Room = 5 KN/m^2.
  • Flat roof = 0.75 KN/m^2.
  • Workshop = 5 KN/m^2.

To Generate the wind load to a model as per Indian standard code reference Data

  • Basic wind speed, Vb = 50 m/s.
  • Terrain category = 2
  • Class of structure = A
  • One horizontal dimension of structure, L = 19.225 m
  • Another horizontal dimension of structure, W = 10.70 m
  • Height of structure, h = 8.7 m

SOLUTION

  • Ratio of wall and Roof Co-efficient

Wall , L/W = 1.79

h/w = 0.81

ROOF, h/w = 0.81

  • As per reference of IS 875, Part – 3, Table =5.
  • To find external pressure co-efficient(CPe) for walls.

The condition is satisfied in,

  • To find Design Wind pressure (Pz).

Pz = 0.6*Vz^2.

  • To find Vz,

Vz = Vb * k1 * k2 * k3* k4

Therefore,

As we take value of k1, k2, k3, k4 from IS 875.

K1 = 1 ( under basic wind speed)

K2 = 1.0 ( height upto 10m)

K3 = 1

K4 = 1.15 ( for industrial building )

Vz = 50 *1*1*1*1.15

Vz = 57.5 m/s

Then to find,

Pz = 0.6 * (57.5) ^2

Pz = 1.983 KN/m^2.

  • To add the load cases of wind at all direction

  • Go to Load > choose patch load > to change the load case property > to change the value of Wind load at direction.
  • To add wing load direction X and Y Both positive and negative .

RESULTS

Finally, we calculated the dead load, live load, wing load and also to applied the model successfully.

Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.