Week 7-Long Piston With Cam
Objective:
Perform a transient analysis on a piston and cam mechanism model that has been provided to you. You need to run the analysis with Frictionless contact, Frictional with 0.1 and 0.2 as the frictional contact for a total of 3 cases. Find out the Equivalent Stress, Directional Deformation and Equivalent Elastic Strain and compare them for all the three cases.
Solution:
-Firstly, open ANSYS workbench and drop down the Transient structural to run the analysis.
-Now, check the material which is selected defaulty by ANSYS.
-Now, import geometry in spaceclaim and check for any abnormalities.
-If there are any then fix them and open the geometry in mechanical module.
-Now, change the names of the geometry and make barrel and cams to be of rigid behaviour.
-Now, make connections where there are required.
-Now, we need to provide joints to the geoemtry.
-Fixed Joint
-Revolute Joint
-Translational Joint
-Now, we can mesh the geometry where the contact faces will have 3mm mesh and rest of the regions will have default mesh.
-Now, we have to assign boundary conditions.
-Now, we need to give the output parameters which are needed to run the analysis.
Case-1: Frictionless Contact
Equivalent Elastic Strain:
Equivalent Elastic Strain graph:
Equivalent Stress:
Equivalent Stress graph:
Deformation:
Deformation graph:
Case-2: Frictional CoEfficient 0.1
Equivalent Elastic Strain:
Equivalent Elastic Strain graph:
Equivalent Stress:
Equivalent Stress graph:
Deformation:
Deformation graph:
Case-3: Frictional CoEfficient 0.2
Equivalent Elastic Strain:
Equivalent Elastic Strain graph:
Equivalent Stress:
Equivalent Stress graph:
Deformation:
Deformation graph:
Comparision Table:
Frictionless Frictional coefficient(0.1) Frictional coefficient(0.2)
Equivalent Elastic Strain(mm/mm) 0.009049 0.0094121 0.063036
Equivalent Stress(MPa) 1799.1 1870.4 12512
Deformation(mm) 11.084 11.122 16.159
Simulation Animation:
Conclusion:
From the above table we can see that as the coefficient of friction increases the values of Equivalent elastic strain, Equivalent stress and Deformation increases.