Week 6 - CHT Analysis on a Graphics card

CHT Analysis on a Graphics card

Aim: To perform a steady-state conjugate heat transfer analysis on a model of a graphics card.

Objective:

1. Run the simulation by varying the velocity from 1m/sec to 5m/sec for at least 3 velocities and discuss the results.
2. Find out the maximum temperature and heat transfer coefficient attained by the processor.
3. Prove that the simulation has achieved convergence with appropriate images and plots.
4. Identify potential hotspots on the model.

Theory:

CHT:

Conjugate heat transfer is defined as the heat transfer between two domains by exchange of thermal energy at the interfaces of faces.

Procedure:

Open the Space claim, Import the Grphic card.

Meshing:

Assign the names accordingly to the parts.

Mesh with 10mm element size.

Setup:

Solver

Steady state

K-omega model

Assign the material with particular property

Solid materials:

Base - FR-4
Fin - Aluminium
Processor - Silicon

Fluid materials:

Enclosure - Air

Inlet velocity =1 m/s

Graphics Card Power = 10W
Volume of the card = 8 x 8 x 1 = 64 mm^3

Heat Generated = P /V= 1.5625e8 Wm^3

Temperature contour around materials:

Heat transfer co-effecient:

Heat transfer co-effecient of processor:

Refined Mesh:

Meshing the individual parts with sizes

Fins size: 0.5 mm

Processor: 0.2 mm

Base: 2 mm

velocity = 1m/s

Temperature of proceesor:

Heat co-effecient of processor:

Temperature contour:

(Solution converge)Residuals:

For velocity =3 m/s.

Temperature contours:

Heat transfer co-effecient of processor:

Temperature of processor:

For velocity = 5m/s

Temperature contours:

Heat transfer co-effecient of processor:

Temperature of processor:

Conclusion:

It better to run fine mesh at required to display the temperature and heat transfer co-effecient properties accurately.

It can be observed that the temperature of components decreases as the inlet velocity increases from 1 m/s to 5m/s, also proving that higher velocity results in better cooling.