Challenge

Week 3 Sheet metal Bending challenge

OBJECTIVE:

  • Set up the model for sheet metal bending with respective contact and loads defined
  • Compare the results of different materials
  • See the results for same material with different mesh size and different friction co-efficient

STEPS:

Import material:-

  • First import the material from engineering data sources
  • Import the all the required materials for the analysis
  • Import Aluminium alloy and duplicate it and rename it as aluminium alloy 1199
  • Change few mechanical properties like Youngs modulus=62000Mpa; Yield strength=140Mpa;Tangent Modulus=209.46

Import geometry:-

  • Import the model to the software
  • Open it in space claim and look for any damage in the model
  • If there is no issue with the model , open it in mechanical module and start setting up for analysis

Mechanical Module:-

  • Update and enter the mechanical module
  • Initially delete all the default contact
  • Rename all the geometry for convinince
  • First case assign the material as aluminium alloy 1199 to sheet geometry

Generate contacts:-

  • Contact>Insert>Manual contact region
  • First establish connection between punch and sheet,
    Contact=Bottom faces of punch
    Target=Top face of sheet
  • Establish contact between sheet and die
    Contact=Bottom face of sheet
    Target=Die face

Define contact:-

  • For both the generated contacts , define the contact
    Type=Frictional
    Friction co-efficient=0.1
    Behaviour=Assymetric
    Formulation=Argumented lagarange
    Normal stiffnes factor=0.1
    Interface treatment=Add offset, ramped effects

Meshing:-

  • Initially use sizing option for punch and die body with 4mm element size
  • Do sizing for sheet with 2mm element size
  • Perform sizing for Contact faces of punch and die with 1mm element size
  • Before generating the mesh, Only for sheet use tetrahedron element

Analysis Setting:-

  • Create 10 steps for the analysis, apply the below settings for all the step
  • Number of steps=10
    Large deflection=on
    Energy disipation ratio=0.1
    Stabilization=Constant
    Sover type=Direct

Define Load:-

  • Define the displacement load for punch by selecting the top faces
  • The punch has to bend the sheet and has to retrived back
  • Static structural>Insert>Displacement
    Type=Displacement
    Defined by=Components
    X=Y=Z=Tabular data
  • Now define the Displcement load for sheet, the sheet should not move in global Z direction
  • Select the side faces of sheet, insert displacement load
    Type=Displacement
    X=Y=Free
    Z=Tabular data(Where all the Z values should be zero , in order to loction the motion of sheet wrt Z direction)
  • Define the displacement load for Die, The die should not move untill the bending happens
  • Once the bending is done the, die should move in global negative z direction
  • Select the bottom faces of Die to give the load
    Type=Displacement
    X=Y=Z=Tabular data

OUTPUT REQUEST:-

  • Request the solution for von-mises Stress, Von-mises strain, Directional deformation with respect to Z direction , Von-mises stress for sheet
  • Repeat All the steps and change only the sheet material for case 1
  • For case 2, All the above steps remains same, change the friction co-efficient=0.19 for aluminimum alloy
  • For case 3, Aluminium alloy as the material but the sheet mesh will be finer, i have used element size=0.75mm, so that the nodes did not cross academic limit

RESULTS:

Aluminium Alloy 1199:-

  • Von-mises Stress
  • Von-mises Strain
  • Directional Deformation
  • Von-mises Stress for sheet

Copper Alloy:-

  • Von-mises stress
  • Von-mises Strain
  • Directional deformation
  • Von-mises stress for sheet

Magnesium Alloy:-

  • Von-mises stress
  • Von-mises Strain
  • Directional deformation
  • Von-mises stress for sheet

CASE 2:
Aluminium Alloy(Friction=0.19):-

  • Von-mises stress
  • Von-mises Strain
  • Directional deformation
  • Von-mises stress for sheet

CASE 3:
Aluminium Alloy(Finer mesh):-

  • Von-mises stress
  • Von-mises Strain
  • Directional deformation
  • Von-mises stress for sheet
  • Material Von-mises stress(Mpa) Von-mises Strain(mm/mm) Directional Deformation(mm) Von-mises Stress(Mpa)

    Aluminium Alloy 1199

    2664.8 0.043145 0.75954 2664.8
    Copper Alloy 4770.7 0.043536 0.7553 4770.7
    Magnesium Alloy 1963.7 0.04380 0.75259 1963.7
    Aluminium Alloy(friction=0.19) 3041.3 0.042998 0.75804 3041.3
    Aluminum Alloy(mesh=0.75mm) 2706.4 0.043692 0.76628 2706.4

CONCLUSION:

  • From the above results we can see the max von-mises stress of the model is equal to max von-mises stress of sheet, this tells us the maximum stress occurs in the sheet comparing whole model
  • Copper alloy has the higher stress value among all the material, strain is almost equal to all the material
  • Comparing Case 1 and 2, the stress is more in case 2, this shows that the friction co-efficient plays a major role. Higher the friction co-efficient higher the stress generated
  • Comparing Case 1 and 3, the difference in the stress is 1.55% which is not much, but the differences between other factors are negligble
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