Challenge

Week 3 Sheet metal Bending challenge

Case 1:Aluminium Alloy 1199( mentioned in the course video), Copper Alloy NL, and Magnesium Alloy NL. Find out the Equivalent stress, Equivalent elastic strain, and Total Deformation in the Y direction and compare the results for the three materials.
STRESS
STRAIN
DIR. DEFORMATION
Conclusion: It is clear that in Copper material the stress & strain are minimun and are concentrated at the bend area while for other 2 material the stress & strain are distributed at the end locations & are heigher in value. The directional deformation in Y-direction of copper is also heigher in comparision to other two. Hence, one can conclude that to bend copper less force will be required then for the same in other material.
Case 2: With the material as Aluminium Alloy, change the friction coefficient to 0.19 and run the analysis as mentioned in Case 1. Compare the results with that in case 1.

Conclution: As the frictional coefficient is reduced the Stress in the AL. sheet is decreased drastically as compaired to Case 1.
Case 3: Refine the mesh on the plate such that it doesn't cross the academic limit. With Aluminium alloy as material, run the analysis as in Case 1 and compare the results.

Conclution: In case 1 the mesh element size is considered to be 1mm and in case 3 the mesh element size is taken 0.75 mm and it is cleared that if the element size is reducer by 25% of case one more refine and accurate results are generated which are similar to case 2.

Ship work like this
in your own course.