Week 3 Challenge
ANS:1
A)STATE THE PRIMARY LOAD CASES TOOBE CONSIDER FOR DESIGN.
THE PRIMARY LOAD CASES ARE
DEAD LOAD
LIVE LOAD
WIND LOAD
SEISMIC LOAD
B) WHAT IS ONE WAY SLAB?
THE RATIO OF LONGER SPAN TO SHORTER SPAN IS GREATER THAN 2 IS CALLED ONE WAY SLAB
Ly/Lx>2
WHERE Ly=LONGER SPAN
Lx=SHORTER SPAN
C)WHAT IS THE VALUE OF UNIT WEIGHT OF STRUCTURL STEEL AND SOIL?
UNIT WEIGHT OF STRUCTURAL STEEL IS 7850Kg/m^3
UNIT WEIGHT OF SOIL IS 18 KN/m3
D)NAME FEW SECTION THAT CAN BE DEFINED USING PROPERTIES TAB IN STAAD PRO
CIRCULAR SECTION
RECTANGULAR SECTION
TEE SECTION
TRAPEZOIDAL SECTION
GENERAL SECTION
TAPERED SECTION
TAPERED TUBE SECTION
ASSIGN PROFILE SECTION
E) DEFINE PRIMERY BEAMS.
THE BEAMS WHICH ARE DIRECTLY CONNECTED WITH COLUMNS ON BOTH THE ENS ARE CALLED PRIMARY BEAM
THE ROLE OF THIS BEAM IS TO TRANSFER THE LOAD TO COLUMN
THE LOAD COMES FROM SLAB THEN TRANSFER TO SECONDARY BEAM IS IT'S PRESENT THEN TRANSFER TO PRIMARY BEAM THEN TRANSFER TO COLUMN
ANS:2
A)STATE THE FACTORS AND PARAMETER THAT INFLUENCE THE DESIGN PRESSURE INTENSITY OF A HIGH RISE BUILDING.
K1=PROBABILITY FACTOR
K2=TERRIAN ,HEIGHT AND STRUCTURE SIZE
K3=TOPOGRAPY FACTOR
K4=IMPORTANT FACTOR FOR CYCLONIC REGION.
DESIGN WIND PRESSURE
DESIGN WIND PRESSURE IS OBTAINED BY THE RELATIONSHIP BETWEEN THE WIND PRESSURE AND WIND VELOCITY.
Pz=0.6*Vz^2
B)MENTION THE LOAD TRANSFER PROCESS OF A REINFORCED CONCRETE BUILDING.
SLAB
SECONDARY BUILDING
PRIMARY BEAM
COLUMN
FOOTING
ANS:3
A)DIFFERENTIATE ONE WAY AND TWO WAY SLAB. ELOBRATE EACH SLAB TYPE.
ONE WAY SLAB:
THE RATIO OF Ly/Lx IS GREATER THAN 2 THEN IT IS CALLED AS ONE WAY SLAB.
ONE WAY SLAB IS SUPPORTED BY TWO BEAM ON THE OPPOSITE ENDS
THE QUNATITY OF STEEL IS REQUIRED IS LESS.
IN ONE WAY SLAB THE BENDING TAKES PLACE IN ONLY ONE DIRECTION THAT IS IN SHORTER DIRECTION.
TWO WAY SLAB:
THE RATIO OF Ly/Lx IS LESS THAN 2 THEN IT IS CALLED AS TWO WAY SLAB.
TWO WAY SLAB IS SUPPORTED BY FOUR BEAM ON ALL THE YOUR SIDE.
THE QUNATITY OF STEEL IS REQUIRED IS MORE.
IN TWO WAY SLAB THE BENDING TAKES PLACE IN BOTH DIRECTION.
B)EXPLAIN THE CONCEPT OF SECONDARY BEAM WITH PROPER CASE
SECONDARY BEAMS ARE CONNECTED WITH MAIN PRIMARY BEAMS THESE BEAMS ACTS AS A SIMPLY SUPPORTED BEAM
IN THE SECONDARY BEAM THE MOMENT AT THE END SUPPORT IS ZERO
SECONDARY BEAM CARRY CERTAIN AMOUNT OF LOAD FROM THE SLAB THEN TRANSFER INTO THE PRIMARY BEAMS
SECONDARY BEAMS CARRY ONLY THE SHEAR NOT MOMENTS
C)MENTION THE PRIMERY LOAD CASES
1)STATE THE INDIAN STANDARED FOR EACH LOAD CASE
DEAD LOAD
LIVE LOAD
WIND LOAD
SEISMIC LOAD
2)DETAIL THE PARAMETER OF EACH LOAD CASE
MEMBER LOAD
CONCENTRATED LOAD
FLOOR LOAD
PLATE LOAD
3)BRIEF LOAD CASE
DEAD LOAD:
DEAD LOAD IS PERMANENT LOAD ON THE STRUCTURE WHICH IS A SELF WEIGHT OF THE STRUCTURE
THIS LOAD IS CAUSED BY THE BEAM COLUMN SLAB FOOTING LOADS
THIS LOADS IS CALCULATED BY USING THE IS 875 PART -1
LIVE LOAD:
THIS LOAD ARE FULLY VARY FROM TIME TO TIME ON THE STRUCTURE
THIS LOADS ARE NOT CONSTANT THROUGHOUT THE LIFE SPAN OF THE STRUCTURE
LIVE LOAD VARIES BASED ON TYPE OF STRUCTURE.
THIS LOAD IS CALCULATED BY USING THE IS 875 PART 2
WIND LOAD:
WIND LOAD IS A LOAD ON THE STRUCTURE WHICH IS GENERATED BY THE WIND
WIND LOAD IS AN IMPRTANT LOAD WE MUST AND SHOULD CONSIDER THE WIND LOAD IN THE HILLY REGION
IN THE NORMAL FLAT REGION ALSO WE CONSIDER THE WIND LOAD THEN WHEN THE HEIGHT OF THE STRUCTURE IS ABOVE 15M
THIS LOAD IS CALCULATED BY USING THE IS 875 PART 3
SESMIC LOAD:
WE SHOULD COSIDER THE SEISMIC LOAD FOR THE ANALYSIS AND DESIGN OF THE HIGH RISE BUILDING
WE CONSIDER THIS LOAD WHERE THE CHANCE OF EARTHQUAKE OCCUR IS NORMAL AND ALSO WE CONSIDER THIS LOAD IN THE EARTHQUAKE PRONE AREAS.
AS PER THE IS CODE WE CARRIED OUT THE DYNAMIC SEISMIC ANALYSIS BY TWO METHOD THEY ARE SPECTRUM ANALSYIS AND TIMEHISTORY METHOD.
THIS LOAD IS CALCULATED BY USING THE IS 1893:2016
D)DETAIL THE STEPS INVOLVED IN ASSIGNING PROPERTIES AND SUPPORT TO A MODEL USING STAAD PRO SEQUENTIALLY.
ASSIGNING PROPERTIES
AFTER CREATING THE GEOMETRY THEN GO TO THE PROPERTY TAB.
CLICK ON THE DEFINE MATERIAL.
SELECT ANY ONE OF THE SECTION WEATHER IT MAY BE RECTANGULER CIRCULAR TEE ETC.
SELECT THE MATERIAL FOR THE SECTION WEATHER IT MAY BE CONCRETE STEEL ALUMINIUM ETC.
IF THE RECTANGULAR SECTION IS SELECTED THEN PROVIDE THE DIMENSION TO THE SECTION.
THEN SELECT THE MATERIAL FOR THE RECTANGULAR SECTION.
THEN CLICK ADD AND CLOSE.
CLICK ON THE PROPERTY THEN ASSIGN TO THE SELECTED VIEW.
FOR SUPPORT:
CLICK ON THE SUPPORT TAB
THEN CLICK ON THE CREATE
THEN SELECT THE TYPE OF THE SUPPORT WE WANT TO PROVIDE.
CLICK ON ADD THEN CLOSE.
THEN CLICK ON ASSIGN TO THE VIEW PROPERTY.
E)BRIF THE STEP TO BE FOLLOWED TO CREATE AND DESIGN SECONDARY BEAMS IN STAAD PRO.
CREATE THE MODEL BY PROVIDING THE NAME UNITS
THEN THE MODELLING SCREEN OPEN THEN CLICK ON THE GEOMETRY.
THEN CREATE A NODES BY USING THE X,Y,Z CO-ORDINATES
AFTER CREATING THE NODES FROM THE CO-ORDINATES
THEN SELECT THE BEAM THEN CLICK RIGHT BUTTON OF THE MOUSE.
THEN CLICK ON THE INSERT NODE TO PROVIDE THE SECONDARY BEAM
AFTER SELECTING THE INSERT NODE THEN INSERT NODE INTO BEAM DIALOUGE BOX OPEN
CLICK ON THE ADD MID POINT THEN CLICK OK
REPEAT THE SAME PROCEDURE ON ANOTHER BEAM.
AFTER CREATING THE BEAM NODE IN THE MID POINT
DRAW THE BEAM WHICH CONNECTS MID POINT OF ONE BEAM TO ANOTHER BEAM
THIS CALLED SECONDARY BEAM
AFFTER ADDING THE PROPERTIES THEN SELECT THE PROPERTIES AND THEN CLICK ON THE ASSIGN THE SELECT BEAM .THEN CLICK ASSIGN
AFTER ASSIGNING THE PROPERTY THEN PROVIDE MATERIAL
GO TO MATERIAL TAB SELECT THE CONCRETE .THEN CLICK ON ASSIGN TO VIEW THEN CLICK ON ASSIGN.
AFTER PROVIDING THE MATERIAL THEN ASSIGN THE SUPPORT FOR THE COLUMN
THEN PROVIDE THE DEAD LOAD IN DEAD LOAD PROVIDE THE SELF WEIGHT.
THEN PROVIDE LIVE LOAD IN LIVE LOA PROVIDE MEMBER LOAD AT 3KN/M.
THEN ANALYSIS THE MODEL THEN WE WIL SEE THE SECONDARY BEAMS CARRIES THE HOGGING MOMENT SO WE NEED TO RELEASE THE MOMENT.
THEN GO TO ANALYTICAL MODEL THEN GO TO SPECIFICATION THEN RELEASE THE BEAM FORCE AND MOMENT
THEN ANALYSIS THE MODEL THEN WILL GET THE 0 MOMENT AT THE SUPPORT.
PRACTICAL:
CALCULATE THE WIND PRESSURE FOR A GIVEN BUILDING
A)BUILDING DIMENSION:20M*30M*20M HEIGHT RCC
B)BUILDING USAGE:HOSPITAL BLOCK IN CITY CENTER
C)LOCATION:DARJEELING
FROM IS 875 PART -3 2015
DESIGN WIND SPEED(Vz)
Vz=Vb*K1*K2*K3*K4
WHERE
Vz=DESIGN WIND SPEED AT HEIGHT Z IN m/S
K1=PROBABILITY FACTOR
K2=TERRAIN ROUGHNESS AND HEIGHT FACTOR
K3=TOPOGRAPY FACTOR
K4=IMPORTANCE FACTOR FOR CYCLONIC REGION
THE WIND SPEED IS 47m/s FOR DARJELLIG
SO FOR 47m/s WIND SPEED K1=1.07
OUR BUILDING LIES IN CATEGORY 4
HEIGHT OF THE BUILDING IS 20M
FROM TABLE 2 FOR THE CATEGORY 4 AND 20M HEIGHT K2=0.80
FROM TOPOGRAPHY FACTOR K3=1
FROM IMPORTANCE FACTOR FOR CYCLIC REGION K4=1.3
Vz=Vb*K1*K2*K3*K4
Vz=47*1.07*0.80*1*1.3
Vz=52.30m/s
CALCULATION OF WIND PRESSURE:
Pz=0.6*Vz^2
Pz=0.6*52.30^2
Pz=1641.174N
Pz=1.64KN
HERE WE CAN CALCULATE FOR DIFFERENT HEIGHT
B)CALCUALTE THE DEAD LOAD AND LIVE LOAD FOR THE ABOVE BUILDING WITH REFERENCE TO IS STANDARED
CALCULATING DEAD LOAD FOR THE SLAB
ASSUME THE THICKNESS OF THE SLAB IS 150MM
DEAD LOAD FOR THE SLAB=THICKNESS*UNIT WEIGHT OF RCC
LENGTH=20M
BREADTH=30M
DEAD LOAD FOR THE SLAB=THICKNESS*UNIT WEIGHT OF RCC
=0.15*25
=3.75KN/m^2
CALCULATING DEAD LOAD FOR BEAM
ASSUME THE BEAM DIMENSION IS 300*500MM
ASSUME THE LENGTH OF THE BEAM IS 10M
DEAD LOAD FOR THE BEAM=VOLUME*UNIT WEIGHT OF RCC
=10*0.3*0.5*25
=37.5KN
CALCULATING DEAD LOAD FOR PARTITION WALL
ASSUME
UNIT WEIGHT OF BRICK=20KN/m^2
HEIGHT OF THE WALL=3M
WIDTH OF THE BRICK=0.3M
PARTITION WALL WIDTH=0.15M
LENGTH OF WALL=10M
DEAD LOAD FOR PARTITION WALL=AREA OF BRICK*UNIT WEIGHT OF BRICK
=THICKNESS*HEIGHT OF WALL* UNIT WEIGHT OF BRICK
=0.15*3*20
=9KN/m
LIVE LOAD
CALCULATING LIVE LOAD AS PER IS 875 PART 2
OCCUPACY LIVE LOAD
FOR WARDS ,DRESSIGN ROOM AND LOUNGES=2KN/m^2
KITCHEN AND LABORATORIES=3KN/m^2
DINING ROOM AND CAFETERIANS=3KN/m^2
TOILET AND BATHROOMS=2KN/m^2
X-RAYS ROOM AND OPRATING ROOMS=3KN/m^2
OFFICE ROOMS AND OPD ROOMS=2.5KN/m^2
COORIDORS PASSAGE LOBBIES AND STAIR=4KN/m^2