Week 3 Challenge
Q1). 1. State the primary load cases to be considered for design.
2. What is One – Way slab?
3. What is the value of unit weight of structural steel and soil?
4. Name few sections that can be defined using Properties tab in STAAD Pro.
5. Define Primary Beams.
Answer:
1. State the primary load cases to be considered for design.
The primary load cases that are to be considered for design are listed below:
- Dead Load (IS 875: Part I).
- Live Load (IS 875: Part II).
- Wind Load (IS 875: Part III).
- Snow Load (IS 875: Part IV).
- Seismic Load (IS 1893: 2016).
2. What is One – Way slab?
- The one-way slab is a slab, which is supported by parallel walls or beams, and whose length to breadth ratio is equal to or greater than two and it bends in only one direction (spanning direction) while it is transferring the loads to the two supporting walls or beams, because of its geometry.
- In short one-way slab is a slab whose length to breadth ratio is equal to or greater than two.
- One-way slab is a plane surface of uniformly loaded which deforms into a cylindrical shape and hence the bending moment develops only in one direction. These type of slab is called one-way slab.
- One-way slab load distribution takes place along its shorter span.Hence bending also happens at the shorter span of the slab.
3. What is the value of unit weight of structural steel and soil?
- Unit weight of Steel = 7850 Kg/m^3
- Unit weight of soil = 1800 Kg/m^3
4. Name few sections that can be defined using Properties tab in STAAD Pro.
Few sections that can be defined using Properties tab in STAAD Pro are listed below:
- Circular sections.
- Rectangular sections.
- I-Sections.
- T-Sections.
- Tapered-I sections.
- Trapezoidal sections.
- Custom Geometric Sections
5. Define Primary Beams.
- Primary Beam is a horizontal flexural (beam) structure member which directly connected to supporting compressive structure member that is column.
- It transfer the loads to the Columns.
- The primary beams are the beams that are directly connected with the column on both the ends.
- The function of the primary beams are to transfer the load of the slab directly to the column that they are resting on.

Q2). 1. State the factors and parameters that influence the design pressure intensity of a high-rise building.
2. Mention the load transfer process of a Reinforced Concrete Building.
Answers:
1. State the factors and parameters that influence the design pressure intensity of a high-rise building.
Pz = 0.6 Vz^2
Where; Pz = Design wind pressure
Vz = Design Speed
Vz = Vb x K1 x K2 x K3
Vb = Wind Speed
K1 = Probability Factor
K2 = Terrain, Height and Structure size factor
K3 = Tropography Factor
The factors and parameters that influence the design pressure intensity of a high-rise building has been discussed below:
So the design speed can be goverened by the below given formula:
Vz = Vb X k1 X k2 X k3 X k4.
where, Vz = Basic wind speed,that is based on the location of the project in India.
k1 = Risk Co-efficient factor.
k2 = Terrain and height factor.
k3 = Topography factor.
k4 = Imfortance factor.
And then the,design wind pressure is given by the below formula:
Pz =0.6Vz^2
2. Mention the load transfer process of a Reinforced Concrete Building.
Gravity load (Dead + Live) on the floor and roof slabs is transferred to the columns , down to the foundations, and then to the supporting soil beneath.

Q3). 1. Differentiate One-Way and Two way slabs. Elaborate each slab type.
2. Explain the concept of secondary beams with proper sketch.
3. Mention the Primary load cases.
a. State the Indian Standards for each load case
b. Detail the parameters of each load case
c. Brief each load case
4. Detail the steps involved in assigning Properties and Support to a model using STAAD Pro sequentially.
5. Brief the steps to be followed to create and assign secondary beams in STAAD Pro
Answer:
1. Differentiate One-Way and Two way slabs. Elaborate each slab type.
| One-Way Slabs | Two-Way Slabs |
| a. One-way slab is supported by a beam on two opposite sides only. | a. Two-way slab is supported by beam on all the four sides. |
| b. in one-way slab load is carried in one direction perpendicular to the supported beam. | b. And in two-way slab load is carried in both directions. |
| c. If L/b ratio is greater than or equal to 2,then the slab is considered as the One-way slab. | c. If L/b ratio is less than or equal to 2,then the slab is considered as the Two-way slab. |
| d. The deflected shape of the one-way slab is cylindrical. | d. The deflected shape of the two-way slab is saucer-like shape. |
| e. In one-way slab the quantity of steel is less. | e. In two-way slab the quantity of steel is more as compared to the onw-way slab. |
| f. In one-way slab,bending takes place only in one direction that is along the shorter span. | f. In two-way slab,bending takes place along the both span. |
2. Explain the concept of secondary beams with proper sketch.
- A horizontal beam connecting primary beams (simply supported or shear connected.)
- It will transfer the load to the primary beam.
- The secondary beams are primarily connected to the primary beams mainly simply supported beams.
- The secondary beams are provided for the better distribution of slab loads along with the primary beams which rests on thed slabs.
- So mainly the secondary beams are the beams that are not directly connected to the columns. The secondary beams rest on the other beams that are directly rest on the column and those beams are known as the primary beams.
- So the secondary beams carries a certain amount of total load and help them to distribute the loads in the respective manner.
- In secondary beams,it is important to release the end moments at the supports,because of this all the secondary beams are provided with the pinned connection.

3. Mention the Primary load cases.
a. State the Indian Standards for each load case
b. Detail the parameters of each load case
c. Brief each load case
Dead Load ( IS 875 Part 1)
Dead Load ( Unit Weight) of following Materials are
Cement = 1440 Kg/m^3
Steel = = 7850 Kg/m^3
Sand = 1600 Kg/m^3
Concrete = 2400 Kg/m^3
RCC = 2500 Kg/m^3
Soil = 1800 Kg/m^3
Timber = 700 Kg/m^3
Factor for Dead Load is 1.
Live Load ( IS 875 Part 2)
Live loads on floors and roofs consists of all the loads which are temporarily placed on the structure,
All rooms and kitchens = 2 KN/m^2
Bathroom and Toilets = 2KN/m^2
Corridors / Stair case= 3 KN/m^3
Balcony = 3KN/m^3
Wind Load :The force exerted by the horizontal component of wind is to be considered in the design of building. Wind loads depends upon the velocity of wind, shape and size of the building. The method of calculating wind loads on structure is given in IS 875 (Part-3):1987.
Snow Load : The building which are located in the regions where snowfall is very common, are to be designed for snow loads. The code IS 875 (Part-4):1987 deals with snow loads on roofs of the building.
Earthquake Load : Earthquake loads depend upon the place where the building is located. As per IS 1893-2016 (Part-I) (General Provisions for Buildings), India is divided into four seismic zones. The code gives recommendations for earthquake resistant design of structures.
4. Detail the steps involved in assigning Properties and Support to a model using STAAD Pro sequentially.
- Go to Properties Tab
- Click on Define Material
- Choose Section and Material
- Click on Add and Close.
- Now Click on Assign to view and assign the Property
- Go to Support Tab
- Click on Create
- Choose Support and click on Add and close
- Now Click on Use Cursor to Assign.
5. Brief the steps to be followed to create and assign secondary beams in STAAD Pro.
Add node at the desired location of the beam. New Add beam between Nodes.
- Now go to the Specification
- Select Beam
- Click on Release
- Click on Start and Tick on Fx and Mz and click Add.
- Now Click on End and Tick Fx and Mz and click Add
- Now Assign to the selected Beam
Practical
Q1). Calculate the wind pressure for the given building
a. Building Dimension : 20m x 30m x 20m height RCC
b. Building usage : Hospital block in city centre
c. Location : Darjeeling
Answer:
For Wind Pressure (Pz) = 0.6 Vz^2
Where Vz = Vb x k1 x k2 x k3
The Structure in category - 4 and Class B and designed for 100 years.
From IS 875 Part 2
Vb = 47 m/s
K1 = 1.07 (Table 1, Clause 5.3.1)
K2 = 0.76 (Table 2, Clause 5.3.2.2) (Categort- 4 ; Class - B)
k3 = 1 (Clause 5.3.3.1)
Hence; Vz = 47 x 1.07 x 0.76 x 1
= 38.22 m/s
And Pz = 0.6 (38.22)^2
= 0.87 N/m^2
| Height | K2 | Vz | Pz |
| 3 | 0.76 | 38.22 | 876.47 |
| 6 | 0.76 | 38.22 | 876.47 |
| 9 | 0.76 | 38.22 | 876.47 |
| 12 | 0.76 | 38.22 | 876.47 |
| 15 | 0.76 | 38.22 | 876.47 |
| 18 | 0.76 | 38.22 | 876.47 |
| 20 | 0.76 | 38.22 | 876.47 |
Q2). Calculate the Dead load and Live load for the above building with reference to IS standards ( assume suitable sections )
Answer:
Dead Load due to Slabs:
Assuming the slab thickness of 150mm.
Dead Load due to the Slabs = Length X Breadth X Height X Slab Thickness.
Dead Load due to the Slabs = 20 X 30 X 25 X 0.15
Dead Load due to the Slabs = 225 KN.
In this project we have total of five floor slabs,therefore:
Total dead load due to all the slabs = 5 X Dead Load due to the Slabs.
Total dead load due to all the slabs = 5 X 225.
Total dead load due to all the slabs = 1125 KN.
Dead Load due to the beams:
Assume the beams of cross-section 350X450mm.
Dead load due to the beams = Size of the beam X Height.
Dead load due to the beams = 0.35 X 0.45 X 25.
Dead load due to the beams = 3.94 KN/m.
Dead load due to the beams = 4 KN/m.
Superimposed Loads due to the Partition walls:
Assuming 150mm thickness of brickwork.
Height of brickwork = Floor height - depth of the beam.
Height of the brickwork = 3.75 - 0.45.
Height of brickwork = 3.3 meters.
Therefore,the dead load due to the brick masonary partition = 3.3 X 0.15 X 18.
The Dead Load due to the brick masonary partition = 8.91 KN/m.
Live Load:
We can calculate the live load of a given structure by using the IS 875:Part 2,which states different live loads values for different rooms.
As our building is the Hospital building,the all the proposed live load values for hospital building according to the IS 875:Part 3 has been listed below:
| OCCUPANCY |
LIVE LOAD |
| For ward rooms,dressing rooms,dormitories and lounges |
2.0 KN/sq.m. |
| Kitchen and Laboratory |
3.0 KN/sq.m |
| Dining room and Cafeteria |
3.0 KN/sq.m |
| Toilets and Bathrooms |
2.0 KN/sq.m |
| X-ray rooms and Operating Rooms |
3.0 KN/sq.m |
| Office and OPD Room |
2.5 KN/sq.m |
| Corridor and Passages |
4.0 KN/sq.m |