Challenge

Week - 2 - Explicit and Implicit Analysis

AIM:

To solve a non- linear dynamic analysis using both implicit and explicit methods.

To solve the equation F(u) = u3+9u2+4u, using both implicit and explicit method.

Implicit and Explicit analysis are used to solve dynamics problems.

EXPLICIT ANALYSIS :-

Explicit analysis are the analysis where there is dynamic equilibrium, the explicit method should be used where the strain rates are higher, eg in automotive crash, meteor impact.

IMPLICIT ANALYSIS :-

Implicit analysis should be used where the events are much slower and the effects of strain rates are minimal. Implicit analysis involves matrix inversions that are extremely complicated and do not directly scale with the number of processors.

Explicit method:

F(u) = u3+9u2+4u

Stiffness of the bar k(u) is :

dF(u)/du = K(u) = d\du{u3+9u2+4u}

dF(u)/du = K(u) = 3u2+18u+4

Step 1 :

u = 0

k(u0) = 4 , delta F = 1

delta u1 = delta F/k(u0)

= ¼ = 0.25

F_int = f(u1) = (0.25)3 +9(0.25)2 + 4*0.25

= 0.015625+ 0.5625 + 1 = 1.578125

Residual = f_int – f_ext = 1.578125 – 1

= 0.578125

Step 2:

F(u1) = 1.578125

U1 = 0.25

K(u1) = 3*(0.25)2 + 18*0.25 + 4 = 0.1875 + 4.5 + 4 = 8.6875

delta u2 = delta F/k(u1) = 1/8.6875 = 0.1151

u2 = u1 + delta u2 = 0.25+0.1151 = 0.3651

f_int = f(u2) = (0.3651)3 + 9*(0.3651)2 + 4*0.3651 = 2.70806

f_ext = 1+1 = 2

Residual = f_int = f_ext = 2.70806-2 = 0.70806

Step 3:

F(u2) = 2.70806

K(u2) = 3*(0.3651)2 + 18 *0.3651 + 4 = 0.4 + 6.5718 + 4 = 10.9718

u2 = 0.3651

delta u3 = 1/10.9718 = 0.0911

u3 = u2+delta u3 = 0.3651+0.0911 = 0.4562

f_int = f(u3) = (0.4562)3 + 9(0.4562)2 + 4*0.4562 = 0.095+1.873 + 1.8248

= 3.7928

F_ext = 1+1+1 = 3

Residual = f_int-f_ext = 3.7928-3 = 0.7928

U (exp)

F(u) (exp)

0

0

0.250

1.578125

0.3651

2.7081

0.4562

3.7928

Implicit Method :

Implicit analysis is the same as explicit, except that at the end of each step a newton-raphson iterations are used to enforce equilibrium.

Step 1:-

Consider , U(0) = 0

K(u0) = 9u2 +18u+4 = 4

Delta u = deltaf/k(0) = ¼ = 0.25

U1= u(0)+delta u = 0.25

F_ext = 1

F _int = (u1)3 + 9(u1)2 + 4u1 = (0.25)3 + 9(0.25)2 + 4*0.25

= 1.518

Residual = R0 = f_int – f_ext = 1.518 – 1

= 0.518

Which is greater than 0.01 thus newton raphson model has to be followed,

U1 = U10

Delta U1 =[-k(u1)0]-1 *R0 = -0.06

Then the value of u1 will be

U11 = u10 +delta u1 = 0.25 -0.06 = 0.19

R1 = f_int – f_ext = 1.0469-1 = 0.0469 > 0.01

U1 = U10

Delta u2 = delta u1- [ku11]-1 *r1 = -0.06 - 0.005 = -0.0713

U12 = u10 + delta u2 = 0.25 – 0.0713 =0.178

F_int = (u13)+9(u2)+4u

= (0.178)3 + 9*(0.178)2 + 4*0.178

=1.007

R2 = 1.007-1 = 0.007

The R2 value is less than 0.01, thus the value of u1 = 0.178

Step 2:

U = u1 = 0.178

K(u1) = 9*(0.178)2 + 18*0.178 + 4 = 7.489

Delta u2 = delta f / k(u1) = 1/7.489 = 0.133

u2 = u1 + delta u2 = 0.178+0.133 = 0.311

f_ext = 1+1 = 2

f_int = (0.311)3 + 9*(0.311)2 + 4*0.311 = 2.144

Residula R0 = f_int – f_ext = 2.144-2 = 0.144 > 0.01

Thus solving for newton raphson method

U2 = 0.296

Step 3 :

u=u2 = 0.296

K(u2) = 9(0.296)2 + 18*0.296 + 4 = 10.116

`delta` u3 = delta F/k(u2) = 1/10.116 = 0.098

U3 = u2+delta u3 = 0.296 + 0.098 = 0.394

F_ext = 1+1+1 = 3

F_int = (u3)3 + 9(u3)2 + 4 u3

= (0.394)3 + 9(0.394)2 + 4*0.394 = 3.034

Residual R0 = f_int - f_ext = 3.034-3 = 0.034 >0.01

Thus solving using newton raphson method :

U3 = 0.391

K(u)

F_ext

F_int

u

4

1

1.077

0.178

7.489

2

2.144

0.296

10.116

3

3.034

0.391

CONCLUSION :-

Implicit method requires and extra computation and can be hard sometimes to calculate. On the other hand explicit method can be used for problems where a short duration analysis has to be done, such as an automotive crash, etc .

For implicit analysis it takes much less computational time because of its larger time step, which in case of explicit analysis takes greater computational time because of smaller time step in explicit.

The choice of analysis depends upon the results to be obtained and also the problem which need to be solved. For some cases implicit analysis suits good, whereas for some cases explicit analysis suits best.

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