Week 10 Challenge

Q1. Purlin & Girts number determination
Given data :

Rafter span = 50 m

Bay spacing = 8 m

Roof slope = 1 in 10

Height of column = 12 m

Brick wall height = 2 m

Purlin spacing = 1.2 m

Girt spacing = 1.5 m

Frame designed according to the dimensions specified.

Number of purlins on one side of the frame = Length / Spacing + 1
= 25 / 1.2 + 1
~ 22 purlins on one side
Therefore total number of purlins be = 22 X 2 = 44 PURLINS

Number of grits on one side of the frame = Length / Spacing + 1
Length = column height - brickwall height
= 12-2
= 10 , required length

Number of grits = 10 / 1.5 + 1
~ 8 purlins on one side
Therefore total number of purlins be = 8 X 2 = 16 GRITS

Stadd file attached below

Q2) Taper the beam according to BMD envelope


Given a stadd file.

Analysis is run and utilization ratio of the structural members are reported.

Left column - 0.634
right column - 0.598
Middle column - 0.863
Left beam - 0.866
Right beam - 0.866

Sections are being optimized using tapered sections as per BMD and each member is utilized upto 90% .

Left column - 0.908
right column - 0.946
Middle column - 0.943
Left beam - 0.954
Right beam - 0.903

Bending moment diagram for the tapered section is given as.

3D rendered view of the frame be like

Stadd file attached below.

Q3) Determining Wind load

Given data : An Industrial building of plan dimension 10m x 5m
wall opening as 15 %
Bay spacing = 2.5m
Height = 6m
As per IS 875 Part 3 :2015
Basic wind speed = 50m/s
Basic frame is designed with support conditions and given dimensions of the building

Q4 ) Determination for support reactions
Given data:
Mono sloped structure , fully open
Slope - 20 degree
width 10 m & length 30 m with bay spacing of 6 m

Self Weight factor – 1.1

Roof Sheet loading = 0.5 kN/m²

Purlin load = 6 kN/m²

Live Load on Roof = 1.5 kN/m2

Wind Load on rafter (Pressure) = 2 kN/m²

^{Frame designed with all properties ans support conditions.}

^{Next step to assign loads as per given conditions.}

^{Loading on the Gable frame is half of the main frame. Load have been multiplied with the bay width in order to arrive loading in KN/m for assigning it on members. Staad fille for refrence is attached.}

^{Run analysis command has been performed successfully with 0 Errors, 1 Warning & 0 Note}

^{Static Load Analysis:}

^{Vertical download forces for various loadin are equal to Upward forces , and Forces on left side are equal to forces on Right side .Thus static equlibrium is maintained.
Stadd file attached below.}