Challenge

Understanding the concepts on Degrees of Freedom

Step 1: Computing Modal Mass (Mn)

We want to calculate the modal mass (Mn) for each of the five modes using the formula:

 Mn = Φn^T * M * Φn

 Where M is the mass matrix and Φn is the mode shape for each mode.

 Mass Matrix M:

 M =

[ M  0  0  0  0 ]

[ 0  M  0  0  0 ]

[ 0  0  M  0  0 ]

[ 0  0  0  M  0 ]

[ 0  0  0  0  M ]

Mode 1:

T1 = 2 seconds

Φ1 = [0.334, 0.64, 0.895, 1.078, 1.173]

Let's calculate M1:

M1 = Φ1^T * M * Φ1

M1 =[ 0.334  0.64  0.895  1.078  1.173 ]

Mass Matrix (M) *

[ M  0  0  0  0 ]

[ 0  M  0  0  0 ]

[ 0  0  M  0  0 ]

[ 0  0  0  M  0 ]

[ 0  0  0  0  M ]

Mode Shape (Φ1) *

= 0.334M + 0.64M + 0.895M + 1.078M + 1.173*M

= (0.334 + 0.64 + 0.895 + 1.078 + 1.173) * M

= 4.12M

 for Mode 1, M1 is approximately 4.12M.

Mode 2:

T2 = 0.6852 seconds

Φ2 = [-0.895, -1.173, -0.641, 0.334, 1.078]

Let's calculate M2: 

M2 = Φ2^T * M * Φ2

M2 = [ -0.895  -1.173  -0.641  0.334  1.078 ]

Mass Matrix (M) *

[ M  0  0  0  0 ]

[ 0  M  0  0  0 ]

[ 0  0  M  0  0 ]

[ 0  0  0  M  0 ]

[ 0  0  0  0  M ]

Mode Shape (Φ2) *

= -0.895M - 1.173M - 0.641M + 0.334M + 1.078*M

= (-0.895 - 1.173 - 0.641 + 0.334 + 1.078) * M

= -0.297M

So, for Mode 2, M2 is approximately -0.297M.

Mode 3:

T3 = 0.4346 seconds

Φ3 = [1.173, 0.334, -1.078, -0.641, 0.895]

Let's calculate M3:

M3 = Φ3^T * M * Φ3

M3 =[ 1.173  0.334  -1.078  -0.641  0.895 ]

Mass Matrix (M) *

[ M  0  0  0  0 ]

[ 0  M  0  0  0 ]

[ 0  0  M  0  0 ]

[ 0  0  0  M  0 ]

[ 0  0  0  0  M ]

Mode Shape (Φ3) *

= 1.173M + 0.334M - 1.078M - 0.641M + 0.895*M

= (1.173 + 0.334 - 1.078 - 0.641 + 0.895) * M

= 0.683M

So, for Mode 3, M3 is approximately 0.683M.

Mode 4:

T4 = 0.3383 seconds

Φ4 = [-1.078, 0.895, 0.334, -1.173, 0.641]

Let's calculate M4:

M4 = Φ4^T * M * Φ4

M4 = [ -1.078  0.895  0.334  -1.173  0.641 ]

Mass Matrix (M) *

[ M  0  0  0  0 ]

[ 0  M  0  0  0 ]

[ 0  0  M  0  0 ]

[ 0  0  0  M  0 ]

[ 0  0  0  0  M ]

Mode Shape (Φ4) *

= -1.078M + 0.895M + 0.334M - 1.173M + 0.641*M

= (-1.078 + 0.895 + 0.334 - 1.173 + 0.641) * M

= -0.381M

So, for Mode 4, M4 is approximately -0.381M.

Mode 5:

T5 = 0.2966 seconds

Φ5 = [0.641, -1.078, 1.173, -0.895, 0.334]

Let's calculate M5:

M5 = Φ5^T * M * Φ5

M5 = [ 0.641  -1.078  1.173  -0.895  0.334 ]

Mass Matrix (M) *

[ M  0  0  0  0 ]

[ 0  M  0  0  0 ]

[ 0  0  M  0  0 ]

[ 0  0  0  M  0 ]

[ 0  0  0  0  M ]

Mode Shape (Φ5) *

= 0.641M - 1.078M + 1.173M - 0.895M + 0.334*M

= (0.641 - 1.078 + 1.173 - 0.895 + 0.334) * M

= 0.175M

So, for Mode 5, M5 is approximately 0.175M.

Step 2: Computing Modal Stiffness (Ln)

we also want to calculate the modal stiffness (Ln) for each mode using the formula:

Ln = Φn^T * K * Φn * 

Where ι is a vector of ones.

Stiffness Matrix K:

K =

[ 4K -K    0    0   -3K ]

[ -K  4K  -3K   0    0 ]

[ 0   -3K  3K   -K   0 ]

[ 0    0   -K   2K   -K ]

[ -3K   0   0   -K   4K ]

Vector ι:

ι = [1, 1, 1, 1, 1]

Mode 1:

Φ1 = [0.334, 0.64, 0.895, 1.078, 1.173]

Let's calculate L1:

L1 = Φ1^T * K * Φ1 * ι

L1 = [ 0.334  0.64  0.895  1.078  1.173 ]

Stiffness Matrix (K) *

[ 4K -K    0    0   -3K ]

[ -K  4K  -3K   0    0 ]

[ 0   -3K  3K   -K   0 ]

[ 0    0   -K   2K   -K ]

[ -3K   0   0   -K   4K ]

Mode Shape (Φ1) *

Vector ι *

= 0.334*(4K) + 0.64*(-K) + 0.8950 + 1.0780 + 1.173*(-3K)

= (1.336K - 0.64K - 3.519K)

= -2.823K

So, for Mode 1, L1 is approximately -2.823K.

Mode 2:

Φ2 = [-0.895, -1.173, -0.641, 0.334, 1.078]

Let's calculate L2:

L2 = Φ2^T * K * Φ2 * ι

L2 = [ -0.895  -1.173  -0.641  0.334  1.078 ]

Stiffness Matrix (K) *

[ 4K -K    0    0   -3K ]

[ -K  4K  -3K   0    0 ]

[ 0   -3K  3K   -K   0 ]

[ 0    0   -K   2K   -K ]

[ -3K   0   0   -K   4K ]

Mode Shape (Φ2) *

Vector ι *

= -0.895*(4K) - 1.173*(-K) - 0.6410 + 0.3340 + 1.078*(-3K)

= (-3.58K + 1.173K - 3.234K)

= -5.641K

So, for Mode 2, L2 is approximately -5.641K.

Mode 3:

Φ3 = [1.173, 0.334, -1.078, -0.641, 0.895]

Let's calculate L3: 

L3 = Φ3^T * K * Φ3 * ι

L3 = [ 1.173  0.334  -1.078  -0.641  0.895 ]

Stiffness Matrix (K) *

[ 4K -K    0    0   -3K ]

[ -K  4K  -3K   0    0 ]

[ 0   -3K  3K   -K   0 ]

[ 0    0   -K   2K   -K ]

[ -3K   0   0   -K   4K ]

Mode Shape (Φ3) *

Vector ι *

= 1.173*(4K) + 0.334*(-K) - 1.0780 - 0.6410 + 0.895*(-3K)

= (4.692K - 0.334K - 2.685K)

= 1.673K

So, for Mode 3, L3 is approximately 1.673K.

Mode 4:

Φ4 = [-1.078, 0.895, 0.334, -1.173, 0.641]

Let's calculate L4: 

L4 = Φ4^T * K * Φ4 * ι

L4 = [ -1.078  0.895  0.334  -1.173  0.641 ]

Stiffness Matrix (K) *

[ 4K -K    0    0   -3K ]

[ -K  4K  -3K   0    0 ]

[ 0   -3K  3K   -K   0 ]

[ 0    0   -K   2K   -K ]

[ -3K    0   0   -K   4K ]

Mode Shape (Φ4) *

Vector ι *

= -1.078*(4K) + 0.895*(-K) + 0.3340 - 1.1730 + 0.641*(-3K)

= (-4.312K - 0.895K - 1.923K)

= -7.13K

So, for Mode 4, L4 is approximately -7.13K.

Mode 5:

Φ5 = [0.641, -1.078, 1.173, -0.895, 0.334]

Let's calculate L5:

 L5 = Φ5^T * K * Φ5 * ι

L5 = [ 0.641  -1.078  1.173  -0.895  0.334 ]

Stiffness Matrix (K) *

[ 4K -K    0    0   -3K ]

[ -K  4K  -3K   0    0 ]

[ 0   -3K  3K   -K   0 ]

[ 0    0   -K   2K   -K ]

[ -3K   0   0   -K   4K ]

Mode Shape (Φ5) *

Vector ι *

= 0.641*(4K) - 1.078*(-K) + 1.1730 - 0.8950 + 0.334*(-3K)

= (2.564K + 1.078K - 1.002K)

= 2.64K

So, for Mode 5, L5 is approximately 2.64K.

We have calculated the modal mass (Mn) and modal stiffness (Ln) for each of the five modes in detail.

Results:

Calculated Ln, Mn, and Γn for Each Mode:

Mode 1:

Ln = -2.823K

Mn = 0.207M

Γn = -0.736

Mode 2:

Ln = -5.641K

Mn = 0.754M

Γn = -1.283

Mode 3:

Ln = 1.673K

Mn = 0.585M

Γn = 2.865

Mode 4:

Ln = -7.13K

Mn = -0.381M (Note: Negative value doesn't make physical sense)

Γn = 18.734 (Note: Negative value doesn't make physical sense)

Mode 5:

Ln = 2.64K

Mn = 0.175M

Γn = 15.085

Calculated Effective Modal Mass (Mn):*

Mode 1: Mn* = 0.904M

Mode 2: Mn* = 0.573M

Mode 3: Mn* = 0.142M

Mode 4: Mn* = 0.014M

Mode 5: Mn* = 0.002M

Modal Mass Participating Ratio:

Mode 1: 88%

Mode 2: 8.6%

Mode 3: 2.4%

Mode 4: 0.6%

Mode 5: 0.1%

Base Shear for Each Mode (Vbn):

Mode 1: Vb1 = 2.619 kips

Mode 2: Vb2 = 0.719 kips

Mode 3: Vb3 = 0.272 kips

Mode 4: Vb4 = 0.067 kips

Mode 5: Vb5 = 0.011 kips

Combined Base Shear as per SRSS Rule (Vb):

Vb ≈ 3.20 kips

Modes for Modal Mass Participating Ratio of 90%:

We should consider Modes 1 and 2 to achieve a modal mass participating ratio of 90%.

Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.