Challenge

To calculate the dead , live and wind load for RC residential structure and to apply them using TSD

1.

Aim: To calculate the dead load in design report based on IS code and to apply dead load on the model.

Solution:

  • Self weight = finish* unit weight of concrete = 0.05*25 = 1.25KN/m^3
  • Service load = 0.3 KN/m
  • Brick wall load (Ground floor to first floor) = thickness * unit weight of concrete * height = 0.155*20*3.6 = 11.16 KN/m^3
  • Brick wall load ( First floor to roof ) = thickness * unit weight of concrete * height = 0.155*20*3.6 = 11.16 KN/m^3
  • From IS 875-3, Roof load = 1.5KN/m
  • Now lets apply the self weight of 1.25 KN/m to slabs of ground, first floor and roof
  • After applying the dead loads, apply the brickwall loads (11.16 KN/m) to all the beams of different floors.

2.

Aim: To calculate the live load in design report based on IS code and to apply the live load on the model.

Solution:

  • Roof = 1.5 KN/m
  • Meeting room = 2KN/m
  • Toilet = 2KN/m
  • Office room = 2.5 KN/m
  • Maintenance room = 2.5 KN/m
  • Pantry = 5 KN/m
  • Staircase = 5 KN/m
  • Now we have to apply these live loads to the slabs.
  • Apply a service load of 0.3 KN/m^2 to the slabs after applying the live load.
  • Now apply the dead load of 1.25 KN/m on the staircase slab, and live load of 5 KN/m^2 and service load od 0.3 KN/m^2 on the staircase slab.

3.

Aim: To generate manual wind loading in the design report based IS code as per given in the question.

Solution:

  • Vb=50m/s
  • Terrain category 2
  • From table 1 of IS 875-3, k1 =1
  • From table 2 of IS 875-3, k2 =1.05
  • k3 = 1
  • Since its a residential building k4= 1
  • Vz = Vb*k1*k2*k3*k4 = 50*1*1.05*1*1 = 52.5m/s
  • Pz = 0.6Vz^2 = 0.6*52.5^2 = 1.635 KN/m
  • Along face A

  • Along face B

  • Along face C

  • Along face D

  • Along EF

  • Along GH

4.

  • Now we have to apply the calculated loads to the model
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