To calculate dead and live load for industrial steel structures and to apply them using TSD
WEEK 4 CHALLENGE
- Calculate dead load in design report based on IS code and apply dead load on the model
- Finishes of 50mm
- Slab as per design
- Brickwall 150mm thickness
- Roofing load based on purlin size
- Ceiling loading 0f 0.3KN per sq m
Answer:
Apply dead load to the model and compute dead load in the design report using the IS code.
50mm Slab finishes according to design
Brickwall with a 150 mm thickness
Purlin size determines the roofing load
Maximum loading of 0.3 KN per square meter
Concrete's unit of weight is 24 KN/m^3.
Dead Weight:
Final loading (Area Loading) = 0.05*24 = 1.2 KN/m^2.
Software will design the slab load.
Brickwall Loading: 150 mm = Brickwall Thickness
Weight in units: 20 KN/m^3
Floor Height = 5.2 meters between the first and lowest floors
Brickwall loading equals 0.15 x 20 x 5.2 = 15.6 KN/m.
Floor height = 6.8 meters from first floor to roof
Brickwall loads equal 0.15 x 20 x 6.8 = 20.4 KN/m.
Ceiling loading is equal to 0.3 KN/m^2, while roof loading is based on Purlin Size of 1.5 KN/m^2. All load scenarios and combinations are generated.
Dead load of 1.2 KN/m^2 is applied to the roof, first floor, and ground floor.
- Calculate live load in design report based on IS code and apply live load on the model
- Assume the loading based on IS 875
- Roof loading
- Consider equipment loading as 5KN per sq m
Answer:
Aim: To calculate design report based on IS Code, and apply live load on the model.
Assume that the roof loading is in accordance with IS 875.
Aim for a 5KN equipment loading per square meter.
In response:
Ground-Level Rooms:
5KN/m^2 in the stair case
Workshop: 5 KN/m^2 (With Light Machinery in Mind)
5KN/m^2 is the corridor.
Conference Space: 5KN/m^2
5KN/m^2 is the store room.
Toilet: 2KN/m^2.
Canteen: 3KN/m^2
Office Space = 3KN/m^2
Conference: 5 KN/m^2.
Equip = 10KN/m^2
First Floor Rooms:
5KN/m^2 in the stair case
Bathroom: 2KN/m^2
5KN/m^2 for the meeting
Room for Administration: 5KN/m^2
Office Space = 3KN/m^2
Toilet: 3KN/m^2.
10 KN/m^2 is the live load applied to the equipment room slab.
Applying a live load of 5 KN/m^2 to the staircase slab
10 KN/m^2 is the live load applied to the equipment room slab.
3 KN/m^2 is the live load applied to the office room slab.
- Generate a calculation for 5T crane loading based on following inputs
- Centre to Centre of wheel = 10m
- Weight of crab = 40 KN
- Number of wheels = 4
- Wheel base = 2m
Answer:
Crane weight: 50 kg
Crane girder's own weight, without the trolley, is 40KN.
Trolly Car or Crab Weight = 10 KN
The crane hook's approximate minimum approach to the gantry girder is one meter.
The length of the gantry rails in centimeters
C/c distance in meters between columns
Rail section self-weight = 300N/m = 0.3KN/m^2
Steel yield stress is 250 N/m^2 or 0.25 KN/m^2.
Wheelbase: 2 meters
To determine the crane's maximum wheel load:
The crane's maximum point load is 50 + 10 = 60 KN.
Crane self-weight = 40 KN
Using UDL= (self weight of crane/c/c distance between gantry rails), this can be converted.
= 40 KN/10 m = 4 KN/m
2. Taking into account the live loads
Spending a moment thinking about C
75.85x3.4375-75.85x0.6875 = RDx5.5 = 56.9 KN RD
Spending a moment thinking about D
75.85x4.8125-75.85x2.0625=RCx5.5
RC is 94.81 KN.
At M2= RDx2.0625, the maximum bending moment will be below the wheel load.
= 2.0625 x 56.9 = 117.35 KN-m
10% of the maximum static wheel load is the impact load.
Impact-related maximum BM, M3 equals 10% of M2
11.735 KN-m = 0.1x117.35
M is equal to M1+M2+M3+117.35+11.735 = 135.90 KN-m
To determine the Maximum Shear Force resulting from vertical loads
1. Regarding dead loads
Shear force resulting from body weight V is equal to wl/2, or 1.8x5.5/2. = 4.95 KN
One of the wheel loads is at the support for the maximum shear force caused by the wheel loads.
2. Regarding Live loads
Spending a moment thinking about F
Rex 5.5-75.85x 5.5-75.85x 2.75 = 0
113.775 KN is RE.
3. Regarding Impact loads
10% of the maximum wheel load is the impact load.
Maximum impact shear force is equal to 0.1 x 113.775 = 11.38 KN.
Maximum shear force overall = 4.95 + 113.775 + 11.38 = 130 KN
Analysis of Lateral Loads
Lateral load is equal to 5% of the total weight raised by the crane and the trolley.
= 0.05 x (10 + 50) = 3 KN
Since we have four wheels, the lateral load for one wheel is 3/4 = 0.75 KN.
The percentage approach can be used to compute maximum bending moments and shear force:
Maximum horizontal response at C as a function of lateral force
= (Max wheel load due to vertical load)/(Lateral forcexlateral force due to response at C due to vertical load)
= 0.75x56.9/75.85
= 0.56 KN
Maximum horizontal response at D as a function of lateral force
= (Maximum wheel load due to vertical load / Lateral force x Lateral force due to reaction at D owing to vertical load)
= 0.75x94.81/75.85
= 0.94 KN
The total lateral load (0.56 + 0.94) = 1.5 KN
Lateral load bending moment = 0.75x117.35/75.85 = 1.16 KN-m