Challenge

To calculate dead and live load for industrial steel structures and to apply them using TSD

  1. Calculate dead load in design report based on IS code and apply dead load on the model

APPICATION OF DEAD LOAD ON THE MODEL.

  • Finishes of 50mm

dead load of finishing

0.05*24= 1.2 kn/m2

  • Slab as per design

Dead load of slab = 0.15*25= 3.5kn/m^2

  • Brickwall 150mm thickness

DEAD LOAD OF BRICK WALL THIICKNESS( 150MM) = 0.15*3*20= 9 KN/M

  • Roofing load based on purlin size

DEAD LOAD

  • Ceiling loading 0f 0.3KN per sq m

  1. Calculate live load in design report based on IS code and apply live load on the model

FOR INDUSTRIAL BUIDIN

  • Assume the loading based on IS 875

TOILET AND BATHROOM = 2KN/M2

CORRIDOR,PSSAG , STAIRCASE=5KN/M2

KITCHEN = 3N/M2

EQUPMENT ROO= 10KN/M2

  • Roof loading

ROOF DEPEND UPON THE ACCESSEBLE AND NON ASSECELE

ACCESS= 1.5 KN/M2

NON ASSECCEBLE = 0.75 KN/M2

  • Consider equipment loading as 5KN per sq m

APPICATION OF LIVE LOAD ON THE MODEL.

  1. Generate a calculation for 5T crane loading based on following inputs
  • Centre to Centre of wheel = 10m
  • Weight of crab = 40 KN
  • Number of wheels = 4
  • Wheel base = 2m

ASSUME THE COLUNM DISTANCE BETWEEN GAINTRY RAILS IS = 18 M

LOADING CAPACITY OF CRANE= 50 KN

WEIGHT OF CRAB= 40 KN

MAXIMUM WHEEL LOAD ON THE CRANE =

POINT LOAD ACTING ON THE SPAN DISTANT 1M FROM END = 50 KN

SELF WEEIGT OF CRANE INCLUDING CRAB ACTS UDL ON THE SPAN OF 10 M= 40 /18= 2.23 KN/M

Ra*18= 50*17+4*18*18/2

= 83 KN

Rb= 7.14 kn

take maximum value

Ra= 83 kn

SO LOAD ON EACH OF THE WHEEL= 83/2= 41.5 KN

MAXIMUM BENDING MOMENT DUE TO WHEEL LOAD ON COLUMN OF DISTANCE 10M =

TAKE MOENT ABOUT D

Rc*10= 41.5*6.5+41.5*4.5+2.4*10*5

Rc =57.64 kn

Rd =49.4 kn

bending moent uner whee due to rection RD= 49.4*4.5=222 kn-m

bending moent due to to impact= 0.1* 222= 22.5 kn-m

so total bendig moment = 22.5+222=244.5 kn-m 34.5kn-m

bending moment due to dead load = wl2/2 =2.4*10*5 =120kn-m

maximum bending moment =344.5 kn-m

MAXIMM SHEAR FORCE

FOR MAXIMUMSHEAR FORCE OE O THE WHEEL SOULD BE AT THE SUPPORT

Rc*10= 41.5*10+41.5* (10-2)

=415+332

Rc =74.7 KN

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