To calculate dead and live load for industrial steel structures and to apply them using TSD
1)
Aim - To calculate dead load in design report based on IS code and apply dead load on the model
Procedure -
Dead load = 1.2 kn/m^2
Finishes = 0.05*24 = 1.2 kn/m^2
Ceiling load = 0.3 kn/m^2
Roof load = 1.5 kn/m^2
Brick wall load -
1) Ground to Intermediate floor = 0.15*20*5.2 = 15.6 kn/m^2
2) Intermediate to Roof floor = 0.15*20*6.8 = 20.4 kn/m^2
3) Roof to Top floor = 0.15*20*4.8 = 14.4 kn/m^2
Step 1 -
- Open Tekla structural designer software and open the week 3 file
- Using model tab select slabs on beam option
- And add slabs to each floor

Step 2 -
- Now add loads using load cases option in load tab
- We will get new window and add the required load in this window

Step 3 -
- Now go to load tab and select combinations
- We will get new window and add required combinations
- Then select the levels where we need to apply the load

Step 4 -
- Under load tab select the area to apply load on slab

- 3D view -

Step 5 -
- Under load tab select UDL applied on the brick wall
- Apply load on Roof

Result -
Hence,we completed calculations of dead load using IS code.
2)
Aim - To calculate live load in design report based on IS code and apply live load on the model
Live load as per IS 875 -
Equipment room = 5 kn/m^2
Workshop = 5 kn/m^2
Staircase = 5 kn/m^2
Administration room = 5 kn/m^2
Store room = 5 kn/m^2
Meeting room = 5 kn/m^2
Conference room = 5 kn/m^2
Toilet = 2 kn/m^2
Rest room = 2 kn/m^2
Office room = 3 kn/m^2
Procedure -
- Select the levels where we want to apply the loads
- Using load tab select the area option to apply load on slab
- Now we can see the area load applied on the slab
Ground floor -

Intermediate floor -

Roof floor -

Result -
Hence,we have calculated live load using IS code.
3)
Aim - To generate a calculation for 5T crane loading based on following inputs
Given data -
Centre to centre span of the wheel = 10m
Weight of crab = 40kn
Number of wheels = 4
Wheel base = 2m
Crane capacity = 50kn
Weight of trolley = 10 kn
Minimum hook approach = 1m
Maximum point load on crane -
= Crane capacity + Weight of trolley
= 50 + 10
= 60 kn
UDL = Self weight of crane / Distance between rails
= 40 / 14
= 2.89 kn/m
Moment at A -
Sigma MA = 0
60*1-14RB-2.89*14/2=0
RB = 24.5 kn
Sigma Fy = 0
RA-RB-60-2.89*14=0
RA = 75.9 kn
Now,assume total self weight of girder = 1.5 kn/m^2
Factored load = 1.5*1.5 = 2.25 kn/m^2
Load on each wheel = 75.9/2 = 37.95kn
Factored load = 37.95*1.5 =57 kn
Moment at C -
Sigma MC = 0
6RD= 2.25*6*3-57*4.5+57*2.5
RD = 73.25 kn
Sigma Fy = 0
RC =RD =57=57=2.25*6
RC = 54.25 kn
Maximum shear force -
Sigma MF = 0
6RE-57*6-57*4-2.25*6*3=0
RE = 101.75 kn
V = WL/2=1.5*6/2 = 4.5 kn
Impact load - 10% of wheel load = 10/100* 101.75 = 10.175 kn
Maximum shear force = 10.175+101.75+4.5 = 116.425 kn
Lateral load analysis = 5% of total weight = 5/100* 60 = 3 kn