Section Modulus calculation and optimization
PROJECT TITLE : SECTION MODULUS CALCULATION AND OPTIMIZATION.
OBJECTIVE : The main objective of this project is to learn the basic features, tools, and the section modulus calculation and optimization using NX CAD.
INTRODUCTION :
Section Modulus : Section modulus is a geometric property for a given cross-section used in the design of beams or flexural members. Other geometric property is used in design include an area for tension and shear, the radius of gyration for compression, and the moment of inertia, and polar moment of inertia for stiffness. Any relationship between these properties is highly dependent on the shape in question. There are two types of section modulus.
- Elastic section modulus.
- Plastic section modulus.
The elastic section modulus is define as,
S=I/Y
where ,
S : is the section modulus
I : is the second moment of area (or area moment of inertia, not to be confused with the moment of inertia)
Y : is the distances from the neutral axis to any given fiber. It is often reported using Y=C, where c is the distance from the neutral axis to the most extreme fiber.
It is also often used to determine the yield moment(My) such that,
My= S x σy
where σy is the yield strength of the material.
SECTION MODULUS CALCULATION :
i have created an intersecion curve with the help of the plane consider both the inner and outer panels of hood for calculation the section modulus. Using the section inertia analysis tool to find the moment of inertia and also show the distances from neutrol axis to the most extreme fiber.
Before Optimization :


Moment of inertia maximum,Imax : 4.796312081e^+0.6[mm^4].
Moment of inertia minimum, Imin : 1.518007297e^+0.4[mm^4].
Distances from the neutral axis, Y : 878.5/2 = 439.25mm.

Section Modulus S=I/Y.
For maximum MOI :
S= (4.796312081e^+0.6[mm^4])/(439.25mm)
Smax = 10919.322mm^3.
For minimum MOI :
S= (1.518007297e^+0.4[mm^4])/(439.25mm)
Smin = 34.560mm^3.
After Optimization :
The inner panel width was increased to 0.9mm to downwards to the original curve and achieved the as shown below.


Moment of inertia maximum, Imax :4.780342048x10^6[mm^4]
Moment of inertia minimum, Imin :1.560842379x10^4[mm^4]
Distances from the neutral axis, Y : 878.5/2 = 439.25mm.
Section Modulus S=I/Y
For Maximum MOI :
S=(4.780342048x10^6[mm^4])/(439.25mm)
Smax =10882.965mm^3.
For Minimum MOI :
S=(1.560842379x10^4[mm^4])/(439.25mm)
Smin =35.535mm^3.
COMPARED TABLE :

CONCLUSION : Thus, the section modulus of the inner and outer panels of hood was calculated and compared with the optimized hood and found the better result.