Section Modulus calculation and optimization
SECTION MODULUS CALCULATION AND OPTIMIZATION
Aim: Use the section of Hood design and to calculate the section modulus of Hood using the formula Z=I/Y.
Section modulus (Z): Section mdulus is a geometric property for a given cross-section used in design of beams or flexural members. It is denoded by " z ".The section modulus is direct measure of the strength of the beam. A beam that has a larger section modulus than another will be stronger and capable of supporting grater loads. It is denoted by Z.
The rario of Area Moment of Inertia (I) to the distance (Y) from the Neutral Axis to the point where the Bending Normal stress is determined.
Section modulus (Z)= I/Y
I = Moment of inertia
Y= The distance(y) to the extreme fibers from the neutral axis.
Tool used to analyis the section: NX CAD
Section-1 type :Hollow
Moment of inertia (I) (min) : 4.811906782e+3 mm^4
(max):8.428885813e+5 mm^4
The distance(Y) to the extreme fibers from the neutral axis (Y): D/2
:488.9/2= 244.45mm
Section are (a): 42.3246 mm^2
section modulus (Z): I/Y
(minumum): 4.8119906782*10^3mm^4 / 244.45mm=0.01968496*10^3m^3
(maximum): 8.428885813*10^5mm^4/244.45mm=3.448102194*10^3m^3
Section -2 type :Hollow
In this second section the section area was increased by increasing gap between outerpanel and inner panel by 3mm at embosses.
Moment of inertia (I) (min) :4.907601623e+3 mm^4
(max): 8.505752031e+5 mm^4
section area (a): 43.026307083 mm^2
The distance(Y) to the extreme fibers from the neutral axis (Y):244.45 mm
Section modulus (Z) : I/Y
(minimum):4.907601623*10^3mm^4/ 244.45mm=0.2007609582*10^3 m^3
(maximum):8.505752031*10^5 mm^4/ 244.45mm=3.47954675*10^3 m^3
- Section modulus of inertia of 1st section(min) :0.01968496*10^3m^3
- Section modulus of inertia of 2nd section(min):0.2007609582*10^3 m^3
By comparing the both sections, section modulus of section-2 is increased by adding the extra volume to the section -1. "Z" is directly propotional to the section area. The strength of the section was increased.