Challenge

Section Modulus calculation and optimization

IAM UNABLE TO ATTACH THE FILE DUE TO IT SIZE IS ABOVE THE ALLOWED SIZE SO I PROVIDED THE GOOGLE DRIVE LINK BELOW:

https://drive.google.com/file/d/19VuXjQh96tjma8D1SDv7r0DcCiz_lrY8/view?usp=drive_link

 

Report:

Section Modulus calculation and optimization

 

Section modulus is a geometric property that measures the strength of a shaft or beam structure. It's used to calculate the bending stresses in a structural member.

 

Section modulus is defined as the ratio of the moment of inertia of a section about its centroidal axis to the distance of the extreme layer from the neutral axis. It can also be defined as the ratio of total moment resisted by the section to the stress in the extreme fiber, which is equal to yield stress.

 

 

IN THE BELOW IMAGE ORANGE LINE SHOWES ORIGINAL SECTION AND BLUE LINE SHOWS CHANGED OR MODIFIED SECTION

 

 THE SECTION OF THE IMPROVED BODY (BELOW)

 

LENGTH OF THE “Y” IS TAKEN AS HALF THE DISTANCE OF TWO EXTREAMS AS IN THE FIGURE BELOW (l/2)  l=881.0465

 

MOI OF ORIGINAL SECTION



MOI OF IMPROVED SECTION,new section that has an improved Section Modulus 

 

FORMULA 

 

S = I/y

 Where, 

S = Section Modulus

I = Moment of Inertia

y = distance between the neutral axis and the extreme end of the object 

CALCULATION:

                                                Y = 881.0465/2=440.52325

MOI OF ORIGINAL SECTION:    1.556580929e+04[mm*4]=8.231225654

MOI OF IMPROVED SECTION:  1.83779283e+04[mm*4] =8.995638854

 

Original section modulus

 S  = I/y

=8.231225654/440.52325

=0.01868511061mm*4

 

Improved section modulus

S  = I/y

=8.995638854/440.52325

 

=0.02042034979mm*4

 

 Difference in section modulus is 

 0.0204 - 0.0186=0.0018mm*4

Conclusion 

The section is improved with the increase in section of modulus ofwith the value of  .0018mm*4

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