Section Modulus calculation and optimization

SECTION MODULUS CALCULATION AND OPTIMIZATION

AIM

To Calculate section modulus and optimization of Hood design. Hood Assembly to be previously design. The section modulus increases the moment of resistance increases.

FORMULA

`S=I/Y`

Where,

S = Section modulus

,I= Moment of inertia

Y= Distance between the neutral axis and the extreme end of the object

SECTION MODULUS

• It is a geometric property for a given cross section used in the design of flexural members.
• The section modulus is the ratio of total moment of resistance by the section to stress in extreme fibre.
• It gives an idea about how much load given structure can take
• The section modulus increases the moment of resistance increases and hence its load bearing capacity.

SECTION MODULUS CALCULATION

Moment of inertia (max) =, I = 1.5649×10^7 mm^4

Moment of inertia (min) =, I = 1.5020×10^5 mm^4

Distance between the neutral axis and the extreme end of the object, Y = 487.4152/2

Y= 243.7076 mm

Section modulus, S = I/Y

= 1.5020×10^5 / 243.7076

S=616.3123 mm^3

OPTIMIZATION

Inner panel depth 2mm increased

Moment of inertia (max) =, I = 1.5645×10^7 mm^4

Moment of inertia (min) =, I = 1.6939×10^5 mm^4

Distance between the neutral axis and the extreme end of the object, Y = 487.4152/2

Y= 243.7076 mm

Section modulus, S = I/Y

= 1.6939×10^5 / 243.7076

S=695.0542 mm^3

CONCLUSION

Thus, the Section modulus increases the moment of inertia increases and hence its load bearing capacity.