Challenge

Section Modulus calculation and optimization

Aim:

To find the section modulus of the hood and optimization to improve the overall section modulus.

Objective:

Use the section from your Hood design and calculate the section modulus using the formula S= I/y.

SECTION MODULUS

Ratio of total moment resisted by the section to the stress in the extreme fibre.
It gives us an idea about how much of load the given structure can take.
If the section modulus increases the moment of resistence increases and hence its load bearing capacity.

S = I/y

where, S - Section modulus

I - moment of inertia

y - distance from neutral axis to the extreme end of the object.

Calculation:

Case 1: Before Optimization

The below image shows the distance between the ends of the hood.
From this in order to find the value of y, we have to take the half of the distance between the ends of the hood.
Hence the value of the y is 239.05mm

Case 2: After Optimization

The hood inner panel’s curve is offset by 0.5mm outwards and section inertia analysis is done same as case 1 for a closed curve.

I (MAX) = 4.643e+05 (mm^4)

I (MIN) = 1.389e+08 (mm^4)

As per the section modulus equation,

S = I/y

I = MOI (min) Value is considered

y = Total distance / 2, Total distance = 478.05 mm

y = 478.05 / 2

y = 239.025 mm

Therefore, S = 464300 mm^4 / 239.025 mm

S = 1942.474 mm^3

Conclusion:

Resulting by comparing case 1 & case 2,

The section modulus value of case 2 is higher than the case 1
As we increase the section area, the moment of inertia & section modulus increase which means strength and load material also increase. Which the moment of inertia directly proportional to the strength of the material.

Ship work like this
in your own course.