Reinforcement Detailing of Beams from ETABS output

AIM:
⦁ To Providing details of longitudinal and shear reinforcement for the two continuous beams using ETABS.
PROCEDURE:
Step 1:
⦁ After downloading the model given in the question, click the Concrete frame design tool in the ribbon tab.
⦁ Choose Select design combinations
⦁ Select the appropriate combination from the dialogue box
⦁ Click ok.
⦁ Once the analysis is done, Click concrete frame icon
⦁ After clicking the icon, it starts checking the concrete design

⦁ After the checking is done, go to the plan view
⦁ On the plan view we have a column and beam detailing
⦁ For this, Grid 3 and Grid A need to provide reinforcement details.
GRID-3:
At Top:
⦁ Maximum Ast at Support = 1940.
⦁ Maximum Ast at Middle = 485.
* 2 dia of 32mm = 1606
* 1 dia of 25 mm = 490
Therefore, to satisfy the support we need to provide 2 dia of 32mm bar and additionally in the middle need to provide 1 dia of 25mm.
At Bottom:
⦁ Maximum Ast at Support = 1056
⦁ Maximum Ast at Middle = 1501
* 3 dia of 25mm = 1470
* 1 dia of 16mm = 200.96
Therefore, to satisfy the support we need to provide 3 dia of 25mm bar and additionally in the middle need to provide 1 dia of 16mm.

Grid A:
At Top:
⦁ Maximum Ast at Support = 2045
⦁ Maximum Ast at Middle = 477.
* 2 dia of 32mm = 1606
* 1 dia of 25 mm = 490
Therefore, to satisfy the support we need to provide 2 dia of 32mm bar and additionally need to provide 1 dia of 25mm.
At Bottom:
⦁ Maximum Ast at Support = 1927
⦁ Maximum Ast at Middle = 789
* 2 dia of 32mm = 1606
* 1 dia of 16mm = 200.96
Therefore, to satisfy the support we need to provide 2 dia of 32mm bar and additionally in the middle need to provide 1 dia of 16mm.

Right-Click the Grid A beam
⦁ Click Details and switch it into shear details
⦁ As per clause 6.3.3 the design force of equivalent Ve = 248 kN
⦁ Shear force under the linear analysis as per the load combination of UDCons66 = 184 kN