Challenge

Reinforcement Detailing of Beams from ETABS output

1) AIM & INTRODUCTION : create a 5 storey building using e tabs and run analysis

PROCEDURE: design the structure - run analysis -press concrete frame design -longitundinal reinforcements will be visible

concrete frame design - drop down - design display information - shear reinforcement will be visible

RESULT:

sway shear force at right:

Vu.a=Vua^ D+L -1.4 Mu^As+Mu^Bh/LAP

Vu.b=Vub^ D+L -1.4 Mu^As+Mu^Bh/LAP

Mas=174 knm

Mbh=293knm

Lab=4.725 m

Vd+1= 92kn

Vu.a=46kn

Vu.b=230kn

sway shear force at left:

Vu.a=Vua^ D+L -1.4 Mu^Ah+Mu^Bs/LAB

Vu.b=Vub^ D+L -1.4 Mu^As+Mu^Bh/LAP

MAh= 234 knm

Mbs=155 knm

Lab=4.725 m

Vd+l= 70kn

Vu.a=185kn

Vu.b=45kn

checking for reinforcement distance is more than 100 mm in both direction hence okay

EXCISTING shear capacity in beam as per drawing (IS as per IS.456-2002 CLAUSE 40.4)

Vas=.87fyAsvd/Su

fy=415kn/mm^2

Asv=151 mm^2

d=450 mm

Sv=100mm

Vus= 245 kn is greater than sway hence it is safe

RESULT:

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