Challenge

Reinforcement Detailing of Beams from ETABS output

1. Ans,

AIM :

To run and execute the ETAB model file and find the longitudinal and shear reinforcement for the beam and find out the shear and failure on the beam with explaination.

INTRODUCTION :

The Provided ETAB file is check the conditons weather the beam are properly material property , section property etc.
Then the file is run using F5 or run command on the Analyze --- run analyse.
Once the analyze done then the Concrete frame design along the menu bar and click ok.

PROCEDURE :

In concrete frame design drop down select display design info there we can see, longitudinal and shear reinforcement for all beams.

A(steel) = 791.

As per ETABS Asv = 12.23 cm2/m

Shear Reinforcemnt :

In the end A along 2 to 3 The beam under goes huge shear which leads to failure in structure to change the failure eaither we have to decrease load or increase concrete grade which leads to heavy strength in strength.

Regarding Reinforcement detail As per IS -13920 -2016 clause 6.
The minimum requiremnet of strups at end of the column joint which is maximum of spacing 100 mm which length upto 2 * beam depth or beam or span / 4.
And also the column and beam joint the first strips has to be start from maximum of 50 mm.

AS per IS 13920 - 2016 clause 6.3.3 b.

Sway at left and right

Sway load = 1.5 * dead +1.5 * live +1.5 * Brickwork+1.5* Finishing.

V(d+l) = - 88, 87

Substitute the formula value

Right ,

Vd+l = 87

M (a,s ) = -233

M (b,h) = -220

L = 5.375

Vua = 228

Vub = 54

Left ,

Vd+l = - 88

M (a,h ) = 161

M (b,s) = 154

L = 5.375

Vua = 10

Vub = 186.

The beam diagarm is given below for the design ,

RESULT :

From the above procedure the Given ETABS file is run and find the Longitudinal and shear reinforcemnet , defects in beam design, Shear value of beam and new design beam had completely executed.

Ship work like this
in your own course.