Project on Concrete Mix Design for various grades of Concrete
Aim: To develop the Concrete Mix Design for M35 grade concrete with fly ash and M50 grade concrete without fly ash.
Introduction:
Concrete Mixing is the mixing of the concrete ingredients of utmost importance in order to produce good quality fresh concrete. A well-mixed concrete of desired workability and performance in both fresh and hardened states is required and the color after the mixing should be uniform.
Here, we'll be dealing with the concrete mix design for M35 grade concrete with fly ash, and in the second part, we'll be performing the same procedure for M50 grade concrete but without fly ash.
Formulae to be kept in mind:
- Cement content = water content / (w/c ratio)
- Volume of cement = (Mass of cement) / (Specific Gravity of cement) * 1/1000
- Volume of water = (Mass of water) / (Specific Gravity of water) * 1/1000
- Volume of chemical admixture = (Mass of admixture) / (Specific Gravity of admixture) * 1/1000
- Target mean strength, f'ck = fck + 1.65*s
Here, f'ck = targetted avg. compressive strength (28 days) ;
fck = characteristic compressive strength (28 days) ;
s = standard deviation ;
6. Aggregate volume = [a-(b+c+d)]
7. Mass of coarse aggregate = e * Volume of coarse aggregate * Specific gravity of fine aggregate * 1000
8. Mass of fine aggregate = e * Volume of fine aggregate * Specific gravity of fine aggregate * 1000
- To develop the Concrete Mix Design for M35 grade concrete with fly ash
- Grading Information:
Grade type : M35
Cement type : OPC M43 Grade
Mineral admixture type : Fly Ash
Aggregate nominal size : 20mm
Aggregate type : Crushed Angular Aggregate
Condition : Severe
Max. w/c ratio : 0.45
Workability : 100mm
Max. cement content : 450 kg/m3
Min. cement content : 320 kg/m3
Chemical Admixture type : Superplasticizer
- Materials test data:
Specific Gravity of Cement : 3.15
Specific Gravity of Fly ash : 2.2
Specific Gravity of coarse aggregate : 2.74
Specific Gravity of fine aggregate : 2.64
Water absorption (Coarse aggregate) : 0.5%
Water absorption (Fine aggregate) : 0.5%
- Targetted strength of mix proportion:
f'ck = fck + 1.65*s
Here, s = 5 N/mm2 (refer Table I in IS 10262:2009)
f'ck = 35 + 1.65*5
= 35 + 8.25
= 43.25 N/mm2
So, Targetted mean strength of mix proportion = 43.25 N/mm2
- Water-Cement ratio selection:
As per IS 456:2000, the maximum w/c ratio = 0.45 (M50)
here, adopted w/c ratio = 0.44
- Water content required: (Refer IS 10262:2009)
From Table2, max. Water content for 20mm aggregate = 186 litre
Addition of 6% water = 186 + [(6/100)*186] = 197 litre
20% has been achieved, so
197*0.8 = 158 litre
So, Water content required = 158 litres
- Cement calculation and required fly ash:
here, w/c ratio = 0.44
Total cement (cement + fly ash) = 158/0.44 = 359 kg/m3
Final cement content = 359 * 1.10 = 395 kg
From Table5, Min. cement content in severe condition = 320 kg
Since 320kg < 395kg>
New w/c ratio = 158/395 = 0.4
Fly Ash taken is 30% of total cement content = 395*0.3 = 118.5 kg/m3
Cement required = 395 - 118 = 277 kg/m3
Therefore, cement required in addition to fly ash = 350 - 277 = 73 kg/m3
- Volume of coarse and fine aggregate content: (Refer IS 10262:2009)
From Table3, the volume of coarse aggregate corresponds to 20mm size for w/c ratio 0.44
= 0.632
Since, pumpable concrete so 10% reduction, so
= 0.632 * 0.9 = 0.568
Volume of fine aggregate = 1 - 0.568 = 0.431
Therefore, the volume of coarse aggregate is 0.568, and the volume of fine aggregate is 0.431
- Mix calculations:
Volume of concrete = 1m3
Volume of cement = (277/3.15) * (1/1000) = 0.087m3
Volume of fly ash = (118/2.2) * (1/1000) = 0.053m3
Volume of water = (158/1) * (1/1000) = 0.158m3
Volume of chemical admixture = (7.6/1.145) * (1/1000) = 0.006m3
Volume of all aggregates = [1-(0.087+0.053+0.158+0.006)] = 0.696m3
Mass of coarse aggregate = 0.696 * 0.568 * 2.74 * 1000 = 1077 kg/m3
Mass of fine aggregate = 0.696 * 0.431 * 2.74 * 1000 = 822 kg/m3
Therefore, mix proportions:
Cement = 277 kg/m3
Fly ash = 118 kg/m3
Water = 158 lit/m3
Fine Aggregate = 822 kg/m3
Coarse Aggregate = 1077 kg/m3
Chemical Admixture = 7.18 kg/m3
W/C ratio = 0.44
- Mix Proportion = 1 : 2.08 : 2.72
- To develop the Concrete Mix Design for M50 grade concrete without fly ash
- Grading Information:
Grade type : M50
Cement type : OPC M53 Grade
Aggregate nominal size : 20mm
Aggregate type : Crushed Angular Aggregate
Condition : Severe
Max. w/c ratio : 0.45
Workability : 100mm
Max. cement content : 450 kg/m3
Min. cement content : 320 kg/m3
Chemical Admixture type : Superplasticizer
- Materials test data:
Specific Gravity of Cement : 3.15
Specific Gravity of coarse aggregate : 2.74
Specific Gravity of fine aggregate : 2.64
Water absorption (Coarse aggregate) : 0.5%
Water absorption (Fine aggregate) : 1.0%
- Targetted strength of mix proportion:
f'ck = fck + 1.65*s
Here, s = 5 N/mm2 (refer Table I in IS 10262:2009)
f'ck = 50 + 1.65*5
= 50 + 8.25
= 58.25 N/mm2
So, Targetted mean strength of mix proportion = 58.25 N/mm2
- Water-Cement ratio selection:
As per IS 456:2000, the maximum w/c ratio = 0.45 (M50)
here, adopted w/c ratio = 0.44
- Water content required: (Refer IS 10262:2009)
From Table2, max. Water content for 20mm aggregate = 186 litre
Addition of 6% water = 186 + [(6/100)*186] = 197 litre
20% has been achieved, so
197*0.8 = 158 litre
So, Water content required = 158 litres
- Cement required calculation :
here, w/c ratio = 0.44
Total cement (cement + fly ash) = 158/0.44 = 359 kg/m3
From Table5, Min. cement content in severe condition = 320 kg/m3
Since 320kg/m3 < 359kg>3, so Cement content was found to be 359kg/m3
Therefore, the cement required is 359kg/m3
- Volume of coarse and fine aggregate content: (Refer IS 10262:2009)
From Table3, the volume of coarse aggregate corresponds to 20mm size for w/c ratio 0.44
= 0.632
Since, pumpable concrete so 10% reduction, so
= 0.632 * 0.9 = 0.568
Volume of fine aggregate = 1 - 0.568 = 0.431
Therefore, the volume of coarse aggregate is 0.568, and the volume of fine aggregate is 0.431
- Mix calculations:
Volume of concrete = 1m3
Volume of cement = (359/3.15) * (1/1000) = 0.114m3
Volume of water = (158/1) * (1/1000) = 0.158m3
Volume of chemical admixture = (7.6/1.145) * (1/1000) = 0.006m3
Volume of all aggregates = [1 - (0.114 + 0.053 + 0.158 + 0.006)] = 0.722m3
Mass of coarse aggregate = 0.722 * 0.568 * 2.74 * 1000 = 1123 kg/m3
Mass of fine aggregate = 0.722 * 0.431 * 2.74 * 1000 = 852 kg/m3
Therefore, mix proportions:
Cement = 359 kg/m3
Water = 158 lit/m3
Fine Aggregate = 852 kg/m3
Coarse Aggregate = 1123 kg/m3
Chemical Admixture = 7.18 kg/m3
W/C ratio = 0.44
- Mix Proportion = 1 : 2.28 : 3.12
Result:
The Concrete Mix Design for M35 grade concrete with fly ash is 1 : 2.08 : 2.72
The Concrete Mix Design for M50 grade concrete without fly ash 1 : 2.28 : 3.12