Challenge

Project on Concrete Mix Design for various grades of Concrete

(ANS 1= Mix design for m35 grade concrete with fly ash

PROCEDURE

STEP 1 Stipulation for proportioning

A grade designation : M35

B Type of cement : OPC 43 grade conforming to IS 8112

C Type of mineral admixture : fly ash confirming to IS3182

D Max nominal size of aggregate :20mm

E Min cement content :320

F Max water cement ratio : 0.45

G Workability : 100mm slump value of pumpable concrete

STEP 2 Test data for materials

A cement used : OPC 43 grade confirming to IS 8112

B Specific gravity of cement : 3.15

C Specific gravity to fly ash

D Water absorbtion : Coarse agg :0.5% Fine agg :1%

IS Seive size (mm) Analysis of coarse agg fraction % of different fraction combined

i ii i ii

20 100 100 60 40 100

10 0 71.2 0 28.5 28.5

4.75 9.4 3.7 3.7

2.36 0

STEP 3 To find target mean strength for mix proportioning

Target mean stength f'ck=FCK+1.65 =35 + 1.65 = 43.25 N/mm2

STEP 4 Max water cement ratio

is taken as = 0.45

STEP 5 Calculation of water content

Max water content for 20mm agg = 186 litre

for 100 mm slump = 186+ (6/100)*186=197 litre

as superplaticizer is used the water content is reduce upto 30%

STEP 6 Calculation of cement content

Water- cement ratio =0.4

cementatious material ( cement +fly ash)= 140/0.4 = 350 kg /m3

cement content for sever exposure =320kg/m3

STEP 7 Proportion of volume of coarse agg and fine agg

vol of coarse agg= 0.64*0.9= 0.576

vol of fine agg = 1-0.576=0.424

STEP 8 Mix calculation

mix calculatio per unit volume of concrete are

A volume of concrete = 1m3

B Volume of cement= ( mass of cement / specific gravity of cement ) 1/1000 = (270/3.15)*1/1000 = 0.086 m3

C vol of flyash = ( mass of fly ash / specific gravity of fly ash) *1/1000 = (115/2.2)*1/1000 = 0.052m3

D vol of water = ( mass of water/ speific gravity of water)*1/1000 = (140/1)*1/1000 = 0.140m3

E vol of chemical admixture = (7.6/1.14)*1/1000 = 0.006m3

STEP 9 Mix proportion

Cement = 270kg/m3

fly ash = 115 kg/m3

Water = 140 kg /m3

Water cement ratio = 0.364

RESULT : The mix design for M35 grade of concrete with fly ash is 1:2.15:2.94

MIX DESIGN OF M 50 GRADE CONCRETE

STEP 1 STIPULATION FOR PROPORTIONING

A Grade designation : M50

B Type of cement : OPC grade 43 conforming to IS 8112

C Maximum nominal size of aggregate : 20mm

D Min cement content : 320 kg/m3

E Max water cement ratio : 0.45

F Method of concrete placing :pumping

G Type of agg : crushed angular agg

STEP 2 TEST DATA FOR MATERIALS

A cement used : OPC 43 grade confirming to IS 8112

B Specific gravity of cement : 3.15

C Water absorbtion : Coarse agg :o.5% Fine agg :1%

STEP 3 SELECTION OF WATER CEMENT RATIO

From table : OF IS 456-2000 by ,exosure condition

water cement ratio = 0.45

STEP 4 TO FIND TARGET MEAN STRENGTH FOR PROPORTIONING

Target mean strength , f'ck =FCK + 1.65 s

50 +1.65 * 5 = 58.25

STEP 5 SELECTION OF WATER CONTENT

FOr 100mm slump = 186+(6/100)*186= 197 litre

STEP 6 CALCULATION OF CEMENT CONTENT

water cement ratio = 0.4

cement content = 140 /0.4 = 350 kg/m3

STEP 7 MIX CALCULATION

A volume of concrete = 1m3

B vol of cement = (350/3.15)*1/1000=0.111m3

C vol of chemical admixture = (7.6/1.145)*1/1000=0.006M3

STEP 8 MIX PROPORTION

Cement = 350 kg/m3

water = 140 kg/m3

fine agg = 863 kg/m3

coarse agg = 1173 kg/m3

RESULT 1:2.46:3.35

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