Project on Concrete Mix Design for various grades of Concrete
Concrete Mix Design for M35 grade concrete with fly ash
1.Stipulation for proprtioning
a.Grade designation : M35
b.Type of cement : OPC 43 grade conforming to IS8112
c.Type of mineral admixture : Fly ash conforming to IS3812(part 1)
d.Maximum nominal size of aggregate : 20mm
e.Minimum cement content : 320kg/m^3
f.Maximum water cement ratio :0.45
g.Workability : 100mm(slump value for pumpable concrete)
h.Exposure condition : Severe(for reinforced concrete)
i.Method of concrete placing : Pumping
j.Degree of supervision : Good
k.Type of aggregate : Crushed angular aggregate
l.Maximum cement content : 450kg/m^3
m.Chemical admixture type : Superplasticizer
2.Test data for materials:
a.Cement used : OPC 43 grade conforming to IS8112
b.Specific gravity of cement :3.15
c.Fly ash : Conforming to IS3812(part 1)
d.Specific gravity of fly ash : 2.2
e.Chemical admixture : Superplasticizer conforming to IS9103
f.Specific gravity of :
coarse aggregate : 2.74
fine aggregate : 2.74
g.Water absorption :
coarse aggregate :0.5%
fine aggregate :1.0%
h.Free surface moisture :
coarse aggregate : NIL
fine aggregate : NIL
i.Sieve analysis:
3.Target Strength for mix proportioning:
f'ck=fck + 1.65S
=35+1.65(5)
f'ck=43.25N/mm^2
4.Selection of water cement ratio:
From table 5 of IS456:2000 for serve exposure maximum water cement ratio=0.45
Based on exoerience adopt water cement ratio as 0.40
0.40<0.45,Hence ok
5.Selection of water content:
From table 2 of IS 10262: 2009, maximum water content for 20mm aggregare =186 litre (for 25mm to 50mm slamp range)
Estmate water contant for 100mm slamp=186+6/100x186=197 lit
As super plasticizer is used, the water content can be redued up to 30%
Based on trials water content reduction of 29% is achicred with plastieizer
Hence the arrived water content=197x0.71=140 litre
6.Calculation of cement content:
Water cement ratio=0.4
Cementitious material (cement & fly ash) content=140/0.4=350kg/m^3
From table 5 of IS 456 minimum cement content for severe exposure condition= 320 kg/m^3
350 kg/m^3> 320kg/m^3, Hence ok
Cementitious material content=350x1.10=385kg/m^3
Water content=140kg/m^3
So, water cement ratio =140/385=0.364
Fly ash @ 30% total cementitious material content=385x30%=115kg/m^3
Cement (opc) =385-115=270kg/m^3
Saving of cement while using fly ash =350-270=80kg/m^3 and
Fly ash being utilized =115kg/m^3
- Proportion of volume of coarse aggregate and fine aggregate content:
From table 3 of IS 10262=2009, volume of coarse aggregate corresponding to 20mm size aggregate and fine aggregate (zone 1) for water -cement ratio=0.6
In the present case the water cement ratio is 0.40
There fore,corrected volume of coarse aggregate for the water-cement ratio of 0.40=0.62
For pumpable concrese these values are reduced by 10%
There for, volume of coarse aggregate=0.62x0.9=0.56
Volume of fine aggregate content=1.056=0.44
8.Mix calculation:
The mix calculation per unit volume of concrete shall be as follow
a) Volume of concrete = 1m^3
b) Volume of cement = mass of amount/ Spacifice gravity of amount x1/1000 =270/3.15x1/1000
=0.086m^3
c) Volume of fly ash = mass of fly ash/ specific gravity of fly ash x1/1000
= 115/2.2 x 1/1000
= 0.052m^3
d) Volume of water = mass of water / specifice gravity of water x 1/1000
= 140 / 1 x 1 / 1000
= 0.140 m^3
e) Volume of aggregate (FA + CA)=mass of chemical admixture/specific gravity of admixturex1/1000
= 7.6/1.145 x 1 / 1000
= 0.006m^3
f) Volume of aggregate (FA+CA) = ( a - ( b+c+d+c) )
= ( 1-(0.086 + 0.052 + 0.140 + 0.006) )
= 0.716m^3
g) Mass of coarse aggregate = f x volume of coarse aggregate x specific gravity of C.A x1000
= 0.716 x 0.56 x 2.74 x 1000
= 1098kg/m^3
h) Mass of fine aggregate = f x volume of fine aggregate x specific gravity of F.A x 1000
= 0.716 x 0.44 x 2.74 x 1000
= 863 kg/m^3
- Mix Proportions for trial number 1 :
Cement = 270kg/m^3
Fly ash = 115 kg/m^3
Water = 140 kg/m^3
Fine aggregate = 868 kg /m^3
Coarse aggregate = 1098 kg/m^3
Chemical admixture = 7 kg/m^3
Water cement ratio = 0.364
Mix ratio = 1: 2.24: 2.85
Concrete Mix Design for M50 grade concrete without flyash
1.Stipulations of proportationing:
a.Grade designation :M50
b.Type of cement :OPC 43 grade conforming to IS 8112
c.Maximum nominal size of aggregate: 20mm
d.Minimum cement content :320Kg/m^3
e.Maximum water cement ratio :0.45
f.Workability :100mm
g.Exposure condition :Severe
h.Method of concrete placing :Pumping
i.Degree of supervision :Good
j.Type of aggregate :crushing angular aggregate
k.Maximum cement content :450Kg/m^3
l.Chemical admixture type : Superplasticizer
2.Test data for material:
a.Cement used : OPC 43 grade conforming to IS 8112
b.Specific gravity of cement :3.15
c.Chemical admixture :Superplasticizer conforming to IS9103
d.Specific gravity of:
Coarse aggregate:2.74
Fine aggregate :2.74
e.Water absorption:
Coarse aggregate :0.5%
Fine aggregate :1.0%
f.Free surface moisture :
Coarse aggregate :Nil
Fine aggregate :Nil
i.Sieve analysis:
3.Target strength for mix proportioning:
f'ck=fck+1.65S
= 50+1.65(5)
f'ck=58.25N/mm^2
4.Selection of water cement ratio :
From table 5 of IS456:2000 for severe exposure maximum water cement ratio=0.40
Based on experience adopted water cement ratio is 0.40
Hence ok
5.Selection of water content:
From table2 of IS10262:2009,maximum water content for 20mm aggregate=186litre(for 25mm to 50mm slump range)
Estimated water content for 100mm slump=186+6/100 x 186=197 litre
As superplasticizer is used the water content can be reduced up to 20% and above
Based on trails water content reduced of 29% is achieved with plasticizer
Hence the arrived water content =197x0.71=140litre
6.Calculation of cement content:
water cement ratio:0.4
Cement contrent =140/0.4=350Kg/m^3
From table 5 of Is 456 minimum cement content for severe exposure condition=320Kg/m^3
350Kg/m^3>320Kg/m^3
Hence ok
7.Proportion of volume of coarse aggregate and fine aggregatr content:
From table 3 of IS10262:2009 volume of coarse aggregate correponding to 20mm size aggregate and fine aggregate for water cement ratio=0.6
In the present case the water cement ratio is 0.40
Therfore corrected volume of coarse aggregate for the water cement ratio of 0.40=0.62
For pumpable concrete these values are reduced by 10%
Therefore volume of coarse aggregate=0.62x0.9=0.56
volume of fine aggregate content=1-0.56=0.44
8.Mix calculation:
The max calculation per unit volume of concrete shall be as follows
a. Volume of concrete = 1 m^3
b. Volume of cement = mass of cement / specific gravity of cement x 1/1000
= 350 / 3.15 x 1 / 1000 = 0.111m^3
c. Volume of water = mass of water / specific gravity of water x 1 / 1000
= 140 / 1 x 1 / 1000 = 0.140 m^3
d. Volume of chemical admixture = mass of chemical asmixture /specific gravity of admixture x 1 / 1000
= 7.6 / 1.145 x 1 / 1000 = 0.006m^3
e. Volume of aggregate (FA+CA) = (a- (b+c+d))
= (1-(0.111+0.140+0.006))
= 0.743m^3
f. mass of coarse aggregate = e x Volume of coarse aggregate x specific gravity of coarse aggr x 1000
= 0.743 x 0.56 x 2.74 x 1000
= 1140 kg/m^3
g. mass of fine aggregate = e x Volume of fine aggr x specific gravity of fine aggr x 1000
= 0.743 x 0.44 x 2.74 x 1000
= 896 kg/m^3
9.Mix proportions for trial number 1:
Cement = 350Kg/m^3
Water = 140Kg/m^3
fine aggregate =896Kg/m^3
Coarse aggregate =1140Kg/m^3
Chemical admixture =7Kg/m^3
Water cement ratio = 0.4
Trial mix ratio =1:2.56:3.26