Project 2_Analyze and Design the RC office building as per IS standard code in TEKLA STRUCTURAL DESIGNER

Aim:- to model the RC structure analyze and design the model elements as per the IS codal provisions

procedure:-

• open a new template in tekla
• then go to settings from the home tab
• assign the design codes and units to be considered in the model
• define the structural default settings
• click on ok

step 1:- to define the construction levels

• click on the construction levels from the model toolbar
• then add the levels in the dialogue box witha a given spacing
• click on ok

Step 2:- to draw horizontal and vertical grids

• click on the grids icoin from the model toolbar
• specify the first point and drag to draw the first grids
• then select on the parallel quick grids to draw the other grid lines with a given spacings
• similarly draw the vertical grids also

step 3:- to assign the model elements like columns, beams and slabs

• go to manage property sets from the home tab
• click on new> members > concrete column
• then define the size of the column and grade of concrete
• click on ok

• now go to model tab and select on the concrete column icon
• select the section from the properties browser
• click on the grid intersections to place the column

• similarly add the properties of the beams and slab using manage property sets and assign them to the model

GROUND FLOOR BEAM LAYOUT

FIRST FLOOR BEAM LAYOUT

ROOF BEAM LAYOUT

STRUCTURE 3D

• now define the properties of the slab and assign slab panels to the model

• to add wall panels to the model
• select the wall panels from the model tab
• then assign them to the model

step 4 :- to model the staircase

• to draw the staircase firstly we need to create a sloping planes
• to create a sloping planes select the corresponding beams and columns and add them to the sub structure
• then open a sub structure and select the slopes from the model tab
• then click on the nodes to create a sloping planes
• then click on beam and add them to a loping planes
• on which we can place a waist slab

step 5:- Calculation of loads

Calculation of dead loads

• self weight of the slab is directly taken by the tekla model
• dead load of floor finishes

assume the thickness of the floor finish as 75mm

unit weight of the concrete is 24 kn/m^3

dead load due to floor finishes = 0.075 x 24 =1.8 kn/m^2

• brick wall loading

assume the unit weight of the bricks as 20 kn/m^3

thickness of the exterior wall is 230mm

thickness of the interior walls is 115mm

height of the first floor is 3.5m

height of the second floor is 3.7m

brick wall load on the ground floor beams(exterior walls) = 3.5 x0.23 x 20=16.1 kn/m

brick wall load on the ground floor beams(interior walls) = 3.5 x0.15 x 20=10.5 kn/m

brick wall load on the first floor beams(exterior walls) = 3.7x0.23 x 20=17.02 kn/m

brick wall load on the first floor beams(interior walls) = 3.7 x0.15 x 20=11.1 kn/m

• roof loading is assumed as 1.5 kn/m^2 as per IS code provisions

FLOOR FINISHES LOAD APPLIED ON SLAB PANELS

BRICK WALL LOAD APPLIED ON THE BEAMS

Calculation of live load

• live load are obtained from the IS 875 part 2 based on the type of structure and occupancy

APPLICATION OF LIVE LOAD ON THE SLAB PANELS

Calculation of wind loads

• assume the basic wind speed as 50 m/s
• terrain category as 2
• design life of the structure as 50 years
• assume the structure to be class A

design wind speed = 50 x 1 x 1 x 1x 1.15 = 57.5

design wind pressure= 0.6 x 57.5 ^2 = 1983.75 N/m^2

Vz = 1.98 Kn/m^2

• height of the structure= 7.85 m
• length of the structure= 36 m
• width of the structure = 16m

Ratio of wall coefficients= l / w = 36 /16 =2.25

Ratio of roof coefficients= h / w = 7.85 /16 =0.49

WIND LOAD CALCULATIONS

Wind load + Y direction Face A

	+Cpi	- Cpi
external pressure coefficients	0.7	0.7
internal pressure coefficients	0.5	-0.5
net pressure coefficients	0.2	-1.2
load factor	1.98	1.98
wind load	0.396	-2.376

Wind load + Y direction Face B

	+Cpi	- Cpi
external pressure coefficients	-0.2	-0.2
internal pressure coefficients	0.5	-0.5
net pressure coefficients	0.3	-0.7
load factor	1.98	1.98
wind load	0.594	-1.365

Wind load + X direction Face C and D

	+Cpi	- Cpi
external pressure coefficients	-0.6	-0.6
internal pressure coefficients	0.5	-0.5
net pressure coefficients	- 1.1	-0.1
load factor	1.98	1.98
wind load	-2.178	-0.198

Application of wind loads to the model

• to define the load cases
• click on loads > load cases
• then add the wind load combinations to the dialogue box
• click on ok

• then we need to create frames to assign the wind loads to the model
• go to model and click on frames and select on the grid to create frames

• then select the corresponding frame to assign the wind loads

• to run the analysis
• firstly check with the modifaction factors
• then click on ist order linear analysis from the analyze tab

• the analysis has been done but the results view doesnot display any of the combinations in my project because of which i couldnot upload the images of deformations, shear force and bending moment