Project 2

Q.(A)

FOR THE MAXIMUM HEAT GENERATION OF THE BATTERY

= JOULE HEAT + ENTROPIC HEAT

=I^2*R*T+2*(I^2*R*T)

SO FOR MAXIMUM VALUE OF CURRENT =-0.896 A

TIME IS 2 MIN =120 SEC

R=0.5 m OHM

SO I^2*R*T= (0.896)^2*120*0.5*10^-3=0.048 J-S

ENTROPIC FACTOR GIVEN AS 2 .

SO ENTROPIC HEAT =2*(0.048) = 0.09633 J-S

SO MAXIMUM HEAT GENERATION = 0.048+0.09633=0.14433792 J-S

SO MAXIMUM HEAT GENERATION = 0.14433992 J-S.

(B) FOR SOC OF THE BATTERY FOR THE OPERATION

as per the result obtained from the scope we can conclude that SOC of the battery in percentage is 55%