Challenge

Project 2

1. Design a Warehouse Building located in Chennai using STAAD Pro Connect Edition. The specification must be as follows:

Width

30m

Length

50m

Eave Height

9m

Bay spacing

6m

Soil type

Medium

Safe Bearing Capacity

200 kN/m2

Roof slope

1 in 12

Assume suitable sections for structural elements. Follow IS800:2007, IS1893 and IS 875

  1. Prepare a Design Basis Report for the project
  2. Create structural model using STAAD Pro Connect Edition
  3. Prepare DL, LL, WL and EQL load calculations as per IS 875 standards
  4. Design using MS – Excel
    1. Steel column
    2. Rafter
    3. Base plate
    4. Pedestal
    5. Z- purlin
  1. Design Foundations using STAAD Foundation.
  2. Attach necessary sketches and drawings wherever required.
  3. All stipulations, assumptions and design parameter must adhere to Indian Standards.

Procedure:

Step 1: Model is prepared in STAAD Pro.

Step 2: Section properties and Materials are applied to all the members.

Step 3: Releases and specifications are applied.

Step 4: Support conditions are applied.

3D Rendering is as follows

Step 5: Loading are calculated and Design Parameters are applied.

Calculation of Design Loads on PEB Structure

1. Dead Load

Dead Load on Rafter

Weight of Roof Sheet = 5 Kg/m2

Weight of Purlin and sag rods = 5 Kg/m2

Additional weight = 5 Kg/m2

Total weight of rafter = 15 Kg/m2

Dead load on rafter = 15 x 10 x 8 = 1200 N/m = 1.2 kN/m

Dead Load on Purlin = 10 x 10 x 8 = 800 N/m = 0.8 kN/m

Mezz Slab self-weight (150 mm thk slab) = 0.15 x 25 kN/m3 = 3.75 kN/m2

Floor Finishes and additional load on Mezz Floor = (150 + 500) kg/m2 = 0.65 kN/m2

Weight of 230mm thick brick wall (4-meter height) on Mezz floor = 20 kN/m3 x 0.23 x 4 = 18.4 kN/m

2. Live Load

Live Load on Roof and canopy = 57 kg/m2 x 10 x 8 = 4.56 kN/m

Live Load on Mezz Floor = 400 kg/m2 = 4 kN/m2Collateral Load

3. Collateral Load on Roof

Load of Electrical fittings = 0.1 kN/m2

Load of Sprinklers = 0.03 kN/m2

Load of rockwool Insulation and bubble wrap insulation = 0.15 kN/m2

Load of Solar Panels = 0.15 kN/m2

Load of Ceiling = 0.1 kN/m2

Total Collateral load on Roof = 0.53 x 8 = 4.24 kN/m

Collateral Load on Mezz Floor (due to false ceiling & electrical fittings)

= 0.2 x 8 = 1.6 kN/m

Collateral Load on column due to Bracket Beam

Load due to service line supported on the beam spanning 8 m width= 150 kg/m x 8 x 10 = 12 kN

Moment acting on column due to service line = 12 x 0.75 = 9 kNm

Collateral Load on Jack Beam due to service line= 2.5 kN/m

Collateral Load on Mezz False Ceiling = 3.2 kN/m

4. Wind Load

Basic wind speed = 50 m/s for chennai

K1 - 1.00

K2 - 1.05 (Terrain Catogory-1. Building height at eaves = 10.50 m)

K3 - 1.00

K4 - 1.00 (For other structures)

Coefficient of cyclonic wind may be taken as 1,

Kd -0.9

Ka (Rafter) - 0.8 or as per tributary area.

Ka (Column) - 0.8245 or as per tributary area.

Ka (Purlin) - 0.9721 or as per tributary area.

Ka (Side Runner) - 0.978 or as per tributary area

Kc -0.9

Design wind pressure = pd = kd x ka x kc x 0.6 x (Vb x k1 x k2 x k3 x k4)2 = 0.652 kN/m2

But should not be less than 0.7 Pz = 0.7 x 1.006 = 0.704 kN/m2

Cpe - As per table 5 & 6 of IS: 875 (Part 3) – 2015

h/w = 10/60 = 0.6

L/w = 170/60 = 2.83

Cpe On wall:

Direction

A

B

C

D

0 deg.

0.7

-0.25

-0.6

-0.6

90 deg.

-0.5

-0.5

0.7

-0.1

Cpe On Roof:

Roof angle = 2.86

Direction

EF

GH

EG

FH

0 deg.

-0.86

-0.4

90 deg.

-0.8

-0.4

Cpi = 0.2

Wind Load on Columns = (Cpe – Cpi) x A x Pd

Wind about X Direction + Cpi = (0.7 – 0.2) x 8 x 0.704 = 2.816 kN/m on Wall A

Wind about X Direction + Cpi = (-0.25 – 0.2) x 8 x 0.704 = -2.534 kN/m on Wall B

Wind about X Direction + Cpi = (-0.6 – 0.2) x 6.75 x 0.704 = -3.802 kN/m on Wall C & D

Wind about X Direction - Cpi = (0.7 + 0.2) x 8 x 0.704 = 5.069 kN/m on Wall A

Wind about X Direction - Cpi = (-0.25 + 0.2) x 8 x 0.704 = -0.282 kN/m on Wall B

Wind about X Direction - Cpi = (-0.6 + 0.2) x 6.75 x 0.704 = -1.9 kN/m on Wall C & D

Wind about Z Direction + Cpi = (-0.5 – 0.2) x 8 x 0.704 = -3.942 kN/m on Wall A

Wind about Z Direction + Cpi = (-0.5 – 0.2) x 8 x 0.704 = -3.942 kN/m on Wall B

Wind about Z Direction + Cpi = (0.7 – 0.2) x 6.75 x 0.704 = 2.376 kN/m on Wall C

Wind about Z Direction + Cpi = (-0.1 – 0.2) x 6.75 x 0.704 = -1.425 kN/m on Wall D

Wind about Z Direction - Cpi = (-0.5 + 0.2) x 8 x 0.704 = -1.689 kN/m on Wall A

Wind about Z Direction - Cpi = (-0.5 + 0.2) x 8 x 0.704 = -1.689 kN/m on Wall B

Wind about Z Direction - Cpi = (0.7 + 0.2) x 6.75 x 0.704 = 4.276 kN/m on Wall C

Wind about Z Direction - Cpi = (-0.1 + 0.2) x 6.75 x 0.704 = 0.475 kN/m on Wall D

Wind Load on Rafters = (Cpe – Cpi) x A x Pd

Wind about X Direction + Cpi = (-0.86 – 0.2) x 8 x 0.704 = -5.970 kN/m on Side A Rafter

Wind about X Direction + Cpi = (-0.4 – 0.2) x 8 x 0.704 = -3.378 kN/m on Side B Rafter

Wind about X Direction - Cpi = (-0.86 + 0.2) x 8 x 0.704 = -3.716 kN/m on Side A Rafter

Wind about X Direction - Cpi = (-0.4 + 0.2) x 8 x 0.704 = -1.125 kN/m on Side B Rafter

Wind about Z Direction + Cpi = (-0.8 - 0.2) x 6.75 x 0.704 = -4.752 kN/m Side C Rafter

Wind about Z Direction + Cpi = (-0.4 - 0.2) x 6.75 x 0.704 = -2.851 kN/m Side D Rafter

Wind about Z Direction - Cpi = (-0.8 + 0.2) x 6.75 x 0.704 = - 2.851kN/m Side C Rafter

Wind about Z Direction - Cpi = (-0.4 + 0.2) x 6.75 x 0.704 = -0.950 kN/m Side D Rafter

Wind Load on Canopy

Cp - As per table 8 of IS: 875 (Part 3) – 2015

Roof Angle 2.86 deg.

Cp -ve = 1.08

Cp +ve = 0.35

Wind Load on Canopy (Upward) = 1.08 x 8 x 0.704 = 6.082 kN/m

Wind Load on Canopy (Downward) = 0.35 x 8 x 0.704 = 1.971 kN/m

5. Seismic Load

As per IS: 1893 - 2016

Seismic zone - III - Z = 0.16

Rf - 4.0

I - 1.0

SS - 3.0

25% of Live Load on roof considered for calculation of seismic forces.

100% of collateral load on roof considered for calculation of seismic forces.

50% of (Live load + Collateral load) on mezzanine floor considered for calculation of seismic forces.

100% of Dead load considered for calculation of seismic forces.

Design Parameters:

  • IS 800 LSD
  • FYLD = 345000 for Portal frame and Mezz Beams
  • FYLD = 250000 for Bracings
  • BEAM = -1
  • STP = 2 for welded sections
  • MAIN = 250 for tie beam
  • Ly = Lx = 1.5m for Rafter
  • Ly = Lx = 3.25m for Columns
  • Ly = Lx = 4.4m for columns supporting canopy
  • Lz = 11m for Internal columns
  • Ly = Lx = 0.5m for Mezz floor beams
  • Lz = 6.75m for Mezz Floor beams
  • Ly = 1.7m for Canopy Beam
  • RATIO = 1
  • STEEL TAKE OFF

Results of the analysis is as follows which shows are members are passing and no member property has failed.

Foundation Design:

Check for Max/min Bearing Pressure
a) wt of soil above the footing
= (area of footing-Area of pedestel)xdepth of soil x unit weight of soil
= ((13.35x3.35) - (0·3×0.45)) x 1.2 × 18 =239.45 KN
b) self wt of footing.
= (vol of footing + vol of pedestall)x unit wt of concrete = ((3.35 × 3·35 x 0·7) + (0.3 × 0.4 x 1)) × 25
= 199.77 KN
Total load on footing
= a + b + Imposed load
= 239.45 + 199.47 + 1500
= 1939.26 kN
Section modulus of footing, Z=bd^2/6
= 3.35×(3.35)^2/6
Maximam bearing pressure
P/A+M/Z
= 1939.26 / (3.35 + 3.35) + 150 / 6.26
= 196.7 kN/m^2
Min bearing Pressure
P/A+M/Z
M=148.8 kN/m^2
which is less than safe bearing capacity ie 200kN/m^2
As per Staad pro calculation:
Check for ultimate Bearing pressure
Max ultimate bearing pressure
P/A+M/Z
= (239.45 +199.77 +1.5x1500)/ 3.35×.35 +(1.5×50/6.26)
=275.5 kN/m2
Min ultimate Bearing Pressure
P/A+M/Z
=239.6-35.9=203.7kN/m^2
which is less than safe bearing capacity for ultimate Loads - 400 KN/m2
As per Staad pro calculations:

Design using MS – Excel

1. Steel column :-

Height of column h = 9m

Yeild strength fy = 250N/mm^2

Elastic modulus E = 200000N/mm^2

Material factor γm = 1.1

Step :- 1

Section classification:

Properties of selected section

ISHB

400

A

10466mm^2

h

400mm

B

250mm

t

10.6mm

T

12.7mm

rx

166.1mm

ry

51.6mm

Zp

cm^3

Flange criterion b/T = 9.84

Web criterion d/t = 35.34

ε = 1

b/T < 10.5

d/t < 42

The section is classified as COMPACT

Step :- 2

Effective length:

As both ends pin-jointed

KLx = 9m

KLy = 9m

KLz = 9m

Slenderness ratio

KLx/rx = 54.18

KLy/ry = 174.42

Non-dimensional effective slenderness ratio

λ = 1.964

Step :- 3

To calculate φ:

h/bf = 1.60

> 1.2

T = 12.7mm

So, buckling class = b

α = 0.34

φ = 0.5(1+α(λ-0.2)+λ^2)

φ = 2.73

Step :- 4

Claculation of χ:

χ = 0.216N/mm^2

Step :- 5

Calculation of fcd:

fcd = χfy/γm

= 49.17

Step :- 6

Factored Axial Load:

Pd = Afcd

= 514.614kN

2. Rafter :-

Span of I beam = 6m

Dead load = 18kN/m

Imposed load = 40kN/m

Length of bearing = 100mm

Yield strength = 250N/mm^2

Step :- 1

Design load calculation

Factored load = 87kN/m

Factored bending moment = 391.5kNm

Step :- 2

Section modulus required:

Zreqd = 1722600mm^3

= 1722.60cm^3

Step :- 3

Section classification:

Properties of selected section

ISMB

250

A

475.5mm^2

D

250mm

B

125mm

t

6.9mm

T

12.5mm

Izz

5131.6cm^4

Iyy

344.5cm^4

Zp

459.76cm^3

Flange criterion B/2T = 5

Web criterion (D-2T)t = 32.61

ε = 1

B/2T < 9.4

(D-2T)/t < 83.9

The section is classified as PLASTIC

Step :- 4

Moment of resistance of the cross section:

Moment Md = (Zpχfy)/γm

Md = 104.491kNm

< 391.50

Hence section ISMB 250 is adequate for flexure

Step :- 4

Shear resistance of the cross section:

Shear capacity Vc = 0.6fyAv/γm

Av = 1725mm^2

Vc = 235.23kN

V = 261kN

V/Vc = 1.11

> 0.6

Step :- 5

Check for web buckling:

Slenderness ratio of web = 2.5d/t

d = 225mm

= 70.33mm

Design compressive stress fc = 203N/mm^2

Pw = 315.16kN

> 261

Hence web is safe against shear buckling

Step :- 6

Check for web crippling at support:

Root radius of ISMB250 R = 13mm

tf + R = 25.5mm

Dispersion length n^2 = 63.75mm

Pcrip = 245625N

= 245.63kN

< 261

Hence section adequate for web crippling

Step :- 7

Check for serviceability Deflection:

Design load = 58kN/m

Deflection δ = 95.36mm

Allowable deflection = 30mm

Hence serviceability is satisfied

3. Base plate :-

Step :- 1

Strength of concrete fcu = 40 N/mm^2

Yield strength of steel fy = 250 N/mm^2

Material factor γm = .kN

Factored load = 1500 kN

Step :- 2

Steel column section:

Thickness of flange T = 12.7 mm

Step :- 3

Area required:

Bearing strength of concrete = 0.4fcu

= 16 N/mm^2

Area required = 93750 mm^2

Let size of plate

Bplate = 350 mm

Dplate = 350 mm

Area of plate = 122500 mm^2

Let projection on each side

a = b

= 25 mm

w = 12.24 N/mm^2

Thickness of slab base ts = 7.7 mm

< 12.70 mm

So use base plate of size 350mmx350mmx12mm.

4. Pedestal :-

Grade of concrete = 40N/mm^2

Load = 123kN

Moment = 116kNm

Horizontal shear = 13kN

Yield strength = 250N/mm^2

Length of base plate L = 450mm

Width of the base plate B = 350mm

C/C distance of (Ld) of bolt group in Z = 300mm

C/C distance of (Ld) of bolt group in X = 180mm

Bearing strength of concrete fc = 16N/mm^2

Depth of column D = 300mm

Width of column W = 250mm

Step :- 1

Anchor Bolt Details:

Dia of anchor bolt = 24mm

No of anchor bolt on each side = 4

Total number of anchor bolt,n = 8

Gross area of the bolt 'Asb' = 452.16mm^2

Net area of the bolt 'Anb' = 352mm^2

Ultimate tensile strength of the bolt fub = 400N/mm^2

Fyb(Anchor bolt) = 240N/mm^2

Step :- 2

Base plate details:

Ultimate tensile strength of a plate,fu = 490N/mm^2

Thickness of plate = 16mm

Yield stress of plate = 330N/mm^2

Step :- 3

Anchor bolt design:

Area of the plate = 157500mm^2

Stress Max pressure σ1 = F/A+6*Mz/BL^2

= 10.60N/mm^2

< 16

OK

Min pressure σ2 = F/A-6*Mz/BL^2

= -9.04N/mm^2

< 16

C = L*σ1/(σ1+σ2)

= 242.89mm

a = L/2-C/3

= 144.04mm

e = (L-Ld)/2

= 75mm

y = (L-C/3-e)

= 294.04mm

Tension in anchor bolts along the length of plate

FT = (Mz-Fxa)/y

= 364.38

Tension per bolt = 91.10kN

Shear per bolt,V = 1.63kN

Step :- 4

Shear check:

Factored shear force Vsb = 1.63kN

Vd,sd = 81290.9N

= 81.291kN

Factored Vd,sb = 65.03kN

Step :- 5

Tensile check:

Factored tensile force in bolt Tb = 91.10kN

Tensile strength of bolt Td,b = Tnb/γmb

Tn,b = 0.9fubAn

= 126720N

= 126.72kN

Tn,b = fybAsb(γmb/γmo)

= 123316N

= 123.316kN

Lesser of two = 123.32kN

So, Td,b = 98.65kN

Step :- 6

Combined unity check:

(Vsb/Vdb)^2+(Tb/Tdb)^2

Vsb/Vdb = 0.025

Tb/Tdb = 0.92

Unity check = 0.85

< 1

Hence OK

Step :- 7

Anchor bolt length:

Bond strength in tension bd = 1.4N/mm^2

Anchor length required = Tb/(3.14*d*τbd)

= 863.44mm

Let anchor bolt bolt length = 900mm

5. Purlin :-

Step :- 1

Span of the purlin = 7m

Spacing of the purlin = 1.5m

Number of sag rods = 1

Slope of the roof = 5deg

Step :- 2

Dead loads:

Weight of sheeting = 5kg/m^2

Self weight of purlin = 4.22kg/m^2

Additional load = 10%

= 0.42kg/m^2

Total dead load = 0.096kN/m^2

Live loads:

Live load on roof = 75kg/m^2

= 0.75kN/m^2

Wind loads:

Basic wind spped = 50m/s

Terrain category = 2

Building class = B

k1 = 1

k2 = 1

k3 = 1

Design wind speed Vz = 57m/s

Design wind pressure Pz = 1949.40N/m^2

= 1.95kN/m^2

Length of the building I = 50m

Breadth of the building w = 30m

Height of the building h = 10.5m

Height of the building at eaves = 9m

h/w = 0.35

I/w = 1.67

External pressure coefficient

Maximum downward Cpe = -0.4

Maximum upward Cpe = -0.7

Internal pressure coefficient

Maximum positive Cpi = 0.5

Maximum negative Cpi = -0.5

For maximum upward wind force

Maximum upward Cpe = -0.7

Cpi = -0.5

Cpe + Cpi = -1.2

Pz = 1.95

Wind pressure for purlin design = -2.339kN/m^2

For maximum upward wind force

Max upward Cpe = -0.4

Cpi = 0.5

Cpe + Cpi = 0.1

Pz = 1.95

Wind pressure for purlin design = 0.195kN/m^2

Step :- 3

Design load calculation:

Spacing of purlin = 1.5m

Slope of roof = 5deg

Total dead load = 0.096kN/m^2

DL normal component = 0.144kN/m

DL tangential component = 0.013kN/m

Total live load = 0.75kN/m^2

LL normal component = 1.121kN/m

LL tangential component = 0.098kN/m

WL1 wind load = -2.339kN/m^2

WL normal component = -3.496kN/m

WL2 wind load = 0.195kN/m^2

WL normal component = 0.291kN/m

Summary of loads

DL+LL

DL+WL1

DL+LL+WL2

Normal load

1.265

-3.351

1.556

Tangential load

0.111

0.013

0.111

DL+LL

0.75(DL+WL1)

0.75(DL+LL+WL2)

Normal load

1.265

-2.514

1.167

Tangential load

0.111

0.009

0.083

Maximum normal component = 1.265kN/m

Step :- 4

Purlin section:

Section selected = Zx200x6x2.3

Yield stress of material = 2400kg/cm^2

Flange width b = 60mm

Depth of section d = 200mm

Thickness t = 2.30mm

Length of Lip lip_I = 20mm

Internal bending radius = 3mm

Area = 8.07cm^2

Zxx = 47.72cm^3

Zyy = 10.22cm^3

Ixx = 477.18cm^4

Iyy = 61.34cm^4

Weight of purlin = 6.335kg/m

= 4.223kg/m^2

Check for basic properties:

t = 2.30mm

w = 49.40mm

Fy = 2400kg/cm^2

w/t = 21.48

< 60

OK

Check for stress:

Span major axis = 7m

Span minor axis = 2m

BM coefficient for Mxx = 10

BM coefficient for Myy = 10

DL+LL

DL+WL1

DL+LL+WL2

Normal load

6.198

16.422

7.625

Tangential load

0.060

0.007

0.060

Mxx/Zxx

129.878

344.133

159.789

Myy/Zyy

5.895

0.672

5.895

(Mxx/Zxx)+(Myy/Zyy)

135.773

344.805

165.684

Maximum compressive stress = 344.80N/mm^2

1435/sq.root of f = 24.44

> 21.48

Hence section OK

Step :- 5

Combined Bending And Shear stresses in web:

h/t = 84.96

DL+LL

DL+WL1

DL+LL+WL2

Fbw

506.539

673.697

637.697

Fv

735.223

977.847

977.847

Actual stress

fbw

129.878

344.133

159.789

fv

5.895

0.672

5.895

fbw/Fbw

0.256

0.511

0.237

fv/Fv

0.008

0.001

0.006

Sqrt of sum of squares

0.257

0.511

0.237

Maximum combined stresses = 0.511

< 1

OK

Step :- 6

Check for deflection:

Number of spans = 3

Deflection = (3/384)(wl^4/EI)

w = 3.351kN/m

Span = 6m

E = 207400N/mm^2

Ixx = 477.18cm^4

δ = 34.29mm

Allowable deflection δ = Span/180

= 33.33mm

> 34.29

Not OK


2. Design a simply supported gantry girder to carry electric overhead travelling crane

Span of gantry girder = 7 m

Span of crane girder = 9 m

Crane capacity = 250 kN

Self-weight of trolley, hook, electric motor etc. = 40 kN

Self-weight of crane girder excluding trolley = 100 kN

Minimum hook approach = 1.0 m

Distance between wheels = 3 m

Self-weight of rails = 0.2 kN/m

Ans:

Step :- 1

Given Data:

Span of gantry girder = 7 m

Span of crane girder = 9 m

Crane capacity = 250 kN

Self-weight of trolley, hook, electric motor etc. = 40 kN

Self-weight of crane girder excluding trolley = 100 kN

Minimum hook approach = 1.0 m

Distance between wheels = 3 m

Self-weight of rails = 0.2 kN/m

Step :- 2

Maximum moment due to vertical load:

Weight of trolley + weight of load lifted = 250 + 40 = 290kN

Self weight of crane girder = 100kN

For maximum reaction on girder, the moving load should be as close to the gantry as possible

Reaction at A RA = 501kN

Reaction at B RB = 281.875kN

Load on gantry girder from each wheel = 251kN

Factored wheel load = 375.833kN

Maximum moment ME = 634.21kNm

Let self weight of girder = 2kN/m

Dead load = 2.2kN/m

Factored DL = 3.3kN/m

M due to DL = 20.21kNm

M due to impact load = 158.55kNm

Factored moment due to all vertical loads,

M = 812.99kNm

Step :- 3

Maximum moment due to lateral load:

Horizontal force transferred to rails = 29kN

Horizontal force on each wheel = 7.25kN

Factored horizontal force = 10.875kN

Maximum moment = 18.35kNm

Vertical shear due to wheel loads = 563.75kN

Impact = 140.94kN

Self weight = 9.90kN

Total shear = 714.59kN

Lateral shear due to surge = 20.68kN

Step :- 4

Preliminary section determination:

Minimum economic depth D = L/12

= 583.333mm

Width of compression flange b = L/40 to L/30

= 175 to 233

Required plastic modulus Zp = 1.4M/fy

= 4552721

= 4552.72x10^3

Let us try ISMB600 with ISMC400 on compression flange.

Step :- 5

Properties of selected section:

ISMB

[email protected]/m

A

15600mm^2

h

600mm

b

210mm

tf

20.3mm

tw

12mm

Izz

91800x10^4mm^4

Iyy

2650x10^4mm^4

R

20mm

ISMC

[email protected]/m

A

6380mm^2

h

400mm

b

100mm

tf

15.3mm

tw

8.8mm

Izz

15200x10^4mm^4

Iyy

508x10^4mm^4

Cyy

2.42mm

Step :- 6

Let the distance of N>A> from, t,he tensio,n range by y':

y' = 388.93mm

Izz = 1348.13x10^6mm^4

Zez = 3466240mm^3

For compression flange about y-y axis

I = 16766.7x10^4mm^4

Zey = 838333mm^3

Total area of section = 21980mm^2

Let plastic N>A> be at a distance

Yp = 580.88mm

Zpz = 4410317mm^3

For top flange Zpy = 1078488mm^3

Step :- 7

Section classfication:

For ISMB b/t = 4.90

< 9.4

d/t = 43.28

< 84

For ISMC b/t = 5.96

< 9.4

Hence section is plastic

Step :- 8

Check for local moment capacity:

Local moment capacity for bending in vertical plane

Mdz = fyZp/1.1

= 1002.34kNm

Mdz = 1.2Zefy/1.1

= 945.34kNm

For top flange

Mdy = 245.11kNm

Mdy = 228.64kNm

In the above which ever the minimum value is taken

Mdz = 945.34kNm

Mdy = 228.64kNm

Step :- 9

Check for combined local capacity:

(812.99/945.34)+(18.35/228.64)<1

0.947<1

Step :- 10

Check for buckling resistance:

Md = βbZpfbd

βb = 1

Lt = 7000mm

E = 200000N/mm^2

hf = 597.5mm

Iy = 17850x10^4mm^4

A = 21980mm^2

ry = 90.12mm

fcr,b = 417.43N/mm^2

λ = 0.744

φ = 0.95

= 0.97N/mm^2

fbd = 166.591

Mdz = 734.72kNm

Mdy = 202.84kNm

Hence 1.20>1

Hence section is unsafe against torsional buckling

Step :- 11

Check for shear:

Vz = 714.59kN

Shear capacity = Avfyw/(3^0.5x1.1)

= 944755N

= 944.755kN

> 714.59

Now = 566.853kN

Low shear

Step :- 12

Check for web buckling:

b = 175mm

n1 = 232.6mm

d = 519.4mm

t = 12mm

= 104.746

Fcd = 128.6N/mm^2

Buckling resistance = 629008kN

> 714.59kN

Step :- 13

Check for deflection at working load:

Vertical deflection

Serviceability vertical wheel load = 251kN

Deflection at mid span a = 2000mm

Izz = 1348.13x10^5mm^4

δ = 25.32mm

Horizontal deflection

I = 16766.65x10^4mm^4

δ = 4.88mm

L/750 = 9.33mm

Unsafe in vertical direction.

Safe in lateral direction.

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