Challenge

Project 2

Using MATLAB/simulink and the drive cycle from the attached excel sheet, find-

  1. The max heat generation of the battery
  2. The SOC of the battery at 2 *104second of the battery operation

maximum current in the drive cycle is -0.896 at 2 minutes(120 seconds)

maximum heat generated =I^2Rt=(-0.896^2)*2*120=192.676 milli Joule

The total heat generated =Joule heat+Entropic heat

=192.676 milli+2(192.676 milli)

=74.248 milli joules.

Averege heat is calculated by taking average value of current and time

average of time =1929/26=74.19sec

Average value of current =-24.7184/26=-0.9507

Therefore joule heat generated=I^2Rt=(-0.9507^2)*2*74.19=134.11milli Joule

Total heat generated=Joule heat+Entropy heat=134.11 milli+2(134.11 )=0.402 milli Joule

The SOC of the battery at 2 *104second of the battery operation

Excel file

simulink model

Output results

Conclusion

I this project we have calculated the average and maximum heat. Also we have simulated the battery SOC, current and volatge for the given drive cycle. At 2 second, the battery SOC is arounf 99.99%.

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