Project 2
Using MATLAB/simulink and the drive cycle from the attached excel sheet, find-
- The max heat generation of the battery
- The SOC of the battery at 2 *104second of the battery operation
maximum current in the drive cycle is -0.896 at 2 minutes(120 seconds)
maximum heat generated =I^2Rt=(-0.896^2)*2*120=192.676 milli Joule
The total heat generated =Joule heat+Entropic heat
=192.676 milli+2(192.676 milli)
=74.248 milli joules.
Averege heat is calculated by taking average value of current and time
average of time =1929/26=74.19sec
Average value of current =-24.7184/26=-0.9507
Therefore joule heat generated=I^2Rt=(-0.9507^2)*2*74.19=134.11milli Joule
Total heat generated=Joule heat+Entropy heat=134.11 milli+2(134.11 )=0.402 milli Joule
The SOC of the battery at 2 *104second of the battery operation
Excel file

simulink model



Output results

Conclusion
I this project we have calculated the average and maximum heat. Also we have simulated the battery SOC, current and volatge for the given drive cycle. At 2 second, the battery SOC is arounf 99.99%.