Project 2
Objective:
- Using MATLAB/simulink and the drive cycle from the attached excel sheet, find-
- The max heat generation of the battery
- The SOC of the battery at 2 *104second of the battery operation
- Consider the battery resistance is 0.5 mOhm, delta time is 0.1 and entropic factor is 2
Battery resistance2 milli ohm

Theory:
- Using MATLAB/simulink and the drive cycle from the attached excel sheet, find-
- The max heat generation of the battery
- The SOC of the battery at 2 *104second of the battery operation
- Consider the battery resistance is 0.5 mOhm, delta time is 0.1 and entropic factor is 2.
Solution:
Heat generated = Joule heat + Entropy heat
Joule heat
- Joule heating is the physical effect that increases the internal energy and collision of electrons in a circuit carrying current that results in the generation of heat energy.
- The Joule’s heating formula is given by Q=I^2Rt.

- According to Joule’s heating formula, the heat energy generated is proportional to the time when the electric current and electrical resistance are constant.
The Joule’s heating formula is given by:
Q = I^2 Rt
Q is the amount of heat generated expressed in Joules.
I is the electric current in Ampere.
R is the resistance offered by the circuit to the electric current flow in Ohms.
t is the time the current is allowed to flow in the circuit expressed in seconds.
Consider an example of Joule heating, where 5 A of current is flowing through an electric wire of resistance 20 Ω for 10 s. The heat energy generated in Joules can be calculated using Joule's heating formula:
Q = 5^2 x 20 x 10 = 5 kJ
Given Data,
Battery resistance=0.5 mOhm
Maximum current= -0.896 ;
Time at maximum DoD, t= 120sec
entropic heat = factor 2 = 2(Joule heat)
Maximum power loss =I^2 *R = (-0.896)^2 *0.5 = 0.4 watt
Joule heat = I^2 *R*t = (-0.896)^2 *0.5* 120sec = 48.16896J
Max heat generated = joule heat + entropic heat
= joule heat + 2(Joule heat)
= 48.16896+2 (48.16896)
= 48.16896+96.33792
= 144.50688 J
- The max heat generation of the battery = 144.50688 J